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1 |
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Last time, I mean Tuesday, we discussed box plot |
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2 |
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and we introduced how can we use box plot to |
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3 |
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determine if any point is suspected to be an |
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4 |
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outlier by using the lower limit and upper limit. |
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5 |
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And we mentioned last time that if any point is |
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6 |
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below the lower limit or is above the upper limit, |
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7 |
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that point is considered to be an outlier. So |
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8 |
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that's one of the usage of the backsplat. I mean, |
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9 |
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for this specific example, we mentioned last time |
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10 |
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27 is an outlier. And also here you can tell also |
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11 |
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the data are right skewed because the right tail |
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12 |
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exactly is much longer than the left tail. I mean |
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13 |
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the distance between or from the median and the |
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14 |
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maximum value is bigger or larger than the |
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15 |
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distance from the median to the smallest value. |
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16 |
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That means the data is not symmetric, it's quite |
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17 |
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skewed to the right. In this case, you cannot use |
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18 |
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the mean or the range as a measure of spread and |
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19 |
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median and, I'm sorry, mean as a measure of |
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20 |
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tendency. Because these measures are affected by |
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21 |
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outcomes. In this case, you have to use the median |
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22 |
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instead of the mean and IQR instead of the range |
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23 |
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because IQR is the mid-spread of the data because |
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24 |
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we just take the range from Q3 to Q1. That means |
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25 |
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we ignore The data below Q1 and data after Q3. |
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26 |
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That means IQR is not affected by outlier and it's |
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27 |
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better to use it instead of R, of the range. |
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28 |
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If the data has an outlier, it's better just to |
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29 |
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make a star or circle for the box plot because |
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30 |
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this one mentioned that that point is an outlier. |
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31 |
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Sometimes outlier is maximum value or the largest |
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32 |
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value you have. sometimes maybe the minimum value. |
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33 |
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So it depends on the data. For this example, 27, |
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34 |
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which was the maximum, is an outlier. But zero is |
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35 |
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not outlier in this case, because zero is above |
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36 |
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the lower limit. Let's move to the next topic, |
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37 |
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which talks about covariance and correlation. |
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38 |
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Later, we'll talk in more details about |
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39 |
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Correlation and regression, that's when maybe |
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40 |
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chapter 11 or 12. But here we just show how can we |
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41 |
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compute the covariance of the correlation |
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42 |
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coefficient and what's the meaning of that value |
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43 |
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we have. The covariance means it measures the |
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44 |
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strength of the linear relationship between two |
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45 |
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numerical variables. That means if the data set is |
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46 |
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numeric, I mean if both variables are numeric, in |
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47 |
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this case we can use the covariance to measure the |
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48 |
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strength of the linear association or relationship |
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49 |
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between two numerical variables. Now the formula |
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50 |
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is used to compute the covariance given by this |
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51 |
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one. It's summation of the product of xi minus x |
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52 |
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bar, yi minus y bar, divided by n minus 1. |
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53 |
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00:03:59,660 --> 00:04:03,120 |
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So we need first to compute the means of x and y, |
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54 |
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then find x minus x bar times y minus y bar, then |
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55 |
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sum all of these values, then divide by n minus 1. |
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56 |
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The covariance only concerned with the strength of |
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57 |
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the relationship. By using the sign of the |
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58 |
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covariance, you can tell if there exists positive |
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59 |
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or negative relationship between the two |
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60 |
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variables. For example, if the covariance between |
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61 |
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x and y is positive, that means x and y move In |
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62 |
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the same direction. It means that if X goes up, Y |
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63 |
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will go in the same position. If X goes down, also |
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64 |
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Y goes down. For example, suppose we are |
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65 |
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interested in the relationship between consumption |
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66 |
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and income. We know that if income increases, if |
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67 |
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income goes up, if your salary goes up, that means |
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68 |
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consumption also will go up. So that means they go |
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69 |
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in the same or move in the same position. So for |
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70 |
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sure, the covariance between X and Y should be |
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71 |
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positive. On the other hand, if the covariance |
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72 |
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between X and Y is negative, that means X goes up. |
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73 |
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Y will go to the same, to the opposite direction. |
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74 |
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I mean they move to opposite direction. That means |
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75 |
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there exists negative relationship between X and |
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76 |
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Y. For example, you score in statistics a number |
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77 |
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of missing classes. If you miss more classes, it |
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78 |
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means your score will go down so as x increases y |
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79 |
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will go down so there is positive relationship or |
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80 |
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negative relationship between x and y i mean x |
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81 |
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goes up the other go in the same direction |
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82 |
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sometimes |
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83 |
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there is exist no relationship between x and y In |
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84 |
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that case, covariance between x and y equals zero. |
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85 |
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00:06:24,880 --> 00:06:31,320 |
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For example, your score in statistics and your |
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86 |
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weight. |
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87 |
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It makes sense that there is no relationship |
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88 |
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between your weight and your score. In this case, |
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89 |
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we are saying x and y are independent. I mean, |
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90 |
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they are uncorrelated. Because as one variable |
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91 |
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increases, the other maybe go up or go down. Or |
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92 |
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maybe constant. So that means there exists no |
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93 |
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relationship between the two variables. In that |
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94 |
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case, the covariance between x and y equals zero. |
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95 |
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00:07:06,450 --> 00:07:09,210 |
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Now, by using the covariance, you can determine |
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96 |
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the direction of the relationship. I mean, you can |
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97 |
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just figure out if the relation is positive or |
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98 |
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00:07:14,850 --> 00:07:18,980 |
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negative. But you cannot tell exactly the strength |
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99 |
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of the relationship. I mean you cannot tell if |
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100 |
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they exist. strong moderate or weak relationship |
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101 |
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just you can tell there exists positive or |
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102 |
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negative or maybe the relationship does not exist |
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103 |
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00:07:33,520 --> 00:07:36,580 |
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but you cannot tell the exact strength of the |
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104 |
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relationship by using the value of the covariance |
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105 |
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I mean the size of the covariance does not tell |
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106 |
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anything about the strength so generally speaking |
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107 |
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covariance between x and y measures the strength |
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108 |
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of two numerical variables, and you only tell if |
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109 |
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there exists positive or negative relationship, |
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110 |
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but you cannot tell anything about the strength of |
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111 |
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00:08:04,510 --> 00:08:06,910 |
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the relationship. Any questions? |
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112 |
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00:08:09,610 --> 00:08:15,210 |
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So let me ask you just to summarize what I said so |
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113 |
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00:08:15,210 --> 00:08:21,100 |
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far. Just give me the summary or conclusion. of |
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114 |
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the covariance. The value of the covariance |
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115 |
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determine if the relationship between the |
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116 |
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variables are positive or negative or there is no |
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117 |
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00:08:29,410 --> 00:08:31,970 |
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relationship that when the covariance is more than |
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118 |
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00:08:31,970 --> 00:08:34,170 |
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zero, the meaning that it's positive, the |
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119 |
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00:08:34,170 --> 00:08:36,930 |
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relationship is positive and one variable go up, |
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120 |
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another go up and vice versa. And when the |
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121 |
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00:08:39,590 --> 00:08:41,810 |
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covariance is less than zero, there is negative |
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122 |
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relationship and the meaning that when one |
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123 |
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variable go up, the other goes down and vice versa |
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124 |
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00:08:47,490 --> 00:08:50,550 |
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and when the covariance equals zero, there is no |
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125 |
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00:08:50,550 --> 00:08:53,350 |
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relationship between the variables. And what's |
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126 |
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00:08:53,350 --> 00:08:54,930 |
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about the strength? |
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127 |
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00:08:57,950 --> 00:09:03,450 |
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So just tell the direction, not the strength of |
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128 |
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00:09:03,450 --> 00:09:08,610 |
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the relationship. Now, in order to determine both |
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129 |
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00:09:08,610 --> 00:09:12,110 |
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the direction and the strength, we can use the |
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130 |
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00:09:12,110 --> 00:09:17,580 |
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coefficient of correlation. The coefficient of |
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131 |
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00:09:17,580 --> 00:09:20,320 |
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correlation measures the relative strength of the |
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132 |
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00:09:20,320 --> 00:09:22,780 |
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linear relationship between two numerical |
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133 |
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00:09:22,780 --> 00:09:27,940 |
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variables. The simplest formula that can be used |
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134 |
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00:09:27,940 --> 00:09:31,220 |
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to compute the correlation coefficient is given by |
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135 |
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00:09:31,220 --> 00:09:34,440 |
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this one. Maybe this is the easiest formula you |
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136 |
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can use. I mean, it's shortcut formula for |
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137 |
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computation. There are many other formulas to |
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138 |
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00:09:40,860 --> 00:09:44,490 |
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compute the correlation. This one is the easiest |
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139 |
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00:09:44,490 --> 00:09:52,570 |
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one. R is just sum of xy minus n, n is the sample |
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140 |
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00:09:52,570 --> 00:09:57,570 |
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size, times x bar is the sample mean, y bar is the |
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141 |
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00:09:57,570 --> 00:10:01,090 |
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sample mean for y, because here we have two |
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142 |
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00:10:01,090 --> 00:10:06,250 |
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variables, divided by square root, don't forget |
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143 |
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00:10:06,250 --> 00:10:11,490 |
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the square root, of two quantities. One conserved |
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144 |
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00:10:11,490 --> 00:10:15,710 |
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for x and the other for y. The first one, sum of x |
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145 |
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00:10:15,710 --> 00:10:18,850 |
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squared minus nx bar squared. The other one is |
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146 |
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00:10:18,850 --> 00:10:21,830 |
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similar just for the other variables, sum y |
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147 |
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00:10:21,830 --> 00:10:26,090 |
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squared minus ny bar squared. So in order to |
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148 |
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00:10:26,090 --> 00:10:28,650 |
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determine the value of R, we need, |
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149 |
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00:10:32,170 --> 00:10:35,890 |
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suppose for example, we have x and y, theta x and |
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150 |
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00:10:35,890 --> 00:10:36,110 |
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y. |
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151 |
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00:10:40,350 --> 00:10:44,730 |
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x is called explanatory |
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152 |
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00:10:44,730 --> 00:10:54,390 |
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variable and |
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153 |
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y is called response variable |
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154 |
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00:11:04,590 --> 00:11:07,970 |
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sometimes x is called independent |
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155 |
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00:11:21,760 --> 00:11:25,320 |
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For example, suppose we are talking about |
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156 |
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00:11:25,320 --> 00:11:32,280 |
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consumption and |
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157 |
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00:11:32,280 --> 00:11:36,700 |
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input. And we are interested in the relationship |
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158 |
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00:11:36,700 --> 00:11:41,360 |
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between these two variables. Now, except for the |
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159 |
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00:11:41,360 --> 00:11:44,900 |
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variable or the independent, this one affects the |
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160 |
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00:11:44,900 --> 00:11:49,840 |
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other variable. As we mentioned, as your income |
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161 |
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00:11:49,840 --> 00:11:53,800 |
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increases, your consumption will go in the same |
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162 |
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00:11:53,800 --> 00:11:59,580 |
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direction, increases also. Income causes Y, or |
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163 |
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00:11:59,580 --> 00:12:04,340 |
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income affects Y. In this case, income is your X. |
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164 |
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00:12:06,180 --> 00:12:07,780 |
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Most of the time we use |
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165 |
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00:12:10,790 --> 00:12:15,590 |
|
And Y for independent. So in this case, the |
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|
166 |
|
00:12:15,590 --> 00:12:19,370 |
|
response variable or your outcome or the dependent |
|
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167 |
|
00:12:19,370 --> 00:12:23,110 |
|
variable is your consumption. So Y is consumption, |
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|
168 |
|
00:12:23,530 --> 00:12:29,150 |
|
X is income. So now in order to determine the |
|
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|
169 |
|
00:12:29,150 --> 00:12:32,950 |
|
correlation coefficient, we have the data of X and |
|
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|
170 |
|
00:12:32,950 --> 00:12:33,210 |
|
Y. |
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171 |
|
00:12:36,350 --> 00:12:39,190 |
|
The values of X, I mean the number of pairs of X |
|
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172 |
|
00:12:39,190 --> 00:12:41,990 |
|
should be equal to the number of pairs of Y. So if |
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173 |
|
00:12:41,990 --> 00:12:44,930 |
|
we have ten observations for X, we should have the |
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174 |
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00:12:44,930 --> 00:12:50,010 |
|
same number of observations for Y. It's pairs. X1, |
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175 |
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00:12:50,090 --> 00:12:54,750 |
|
Y1, X2, Y2, and so on. Now, the formula to compute |
|
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|
176 |
|
00:12:54,750 --> 00:13:04,170 |
|
R, the shortcut formula is sum of XY minus N times |
|
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|
177 |
|
00:13:04,970 --> 00:13:09,630 |
|
x bar, y bar, divided by the square root of two |
|
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|
178 |
|
00:13:09,630 --> 00:13:12,770 |
|
quantities. The first one, sum of x squared minus |
|
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179 |
|
00:13:12,770 --> 00:13:17,270 |
|
n x bar. The other one, sum of y squared minus ny |
|
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|
180 |
|
00:13:17,270 --> 00:13:21,710 |
|
y squared. So the first thing we have to do is to |
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|
181 |
|
00:13:21,710 --> 00:13:24,210 |
|
find the mean for each x and y. |
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|
182 |
|
00:13:28,230 --> 00:13:37,210 |
|
So first step, compute x bar and y bar. Next, if |
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183 |
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00:13:37,210 --> 00:13:41,690 |
|
you look here, we have x and y, x times y. So we |
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184 |
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00:13:41,690 --> 00:13:48,870 |
|
need to compute the product of x times y. So just |
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185 |
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00:13:48,870 --> 00:13:53,870 |
|
for example, suppose x is 10, y is 5. So x times y |
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186 |
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00:13:53,870 --> 00:13:54,970 |
|
is 50. |
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|
187 |
|
00:13:57,810 --> 00:13:59,950 |
|
In addition to that, you have to compute |
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|
188 |
|
00:14:06,790 --> 00:14:12,470 |
|
100 x squared and y squared. It's like 125. |
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189 |
|
00:14:14,810 --> 00:14:18,870 |
|
Do the same calculations for the rest of the data |
|
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|
190 |
|
00:14:18,870 --> 00:14:22,290 |
|
you have. We have other data here, so we have to |
|
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|
191 |
|
00:14:22,290 --> 00:14:25,410 |
|
compute the same for the others. |
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|
192 |
|
00:14:28,470 --> 00:14:33,250 |
|
Then finally, just add xy, x squared, y squared. |
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|
193 |
|
00:14:35,910 --> 00:14:40,830 |
|
The values you have here in this formula, in order |
|
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|
194 |
|
00:14:40,830 --> 00:14:44,830 |
|
to compute the coefficient. |
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|
195 |
|
00:14:54,250 --> 00:15:00,070 |
|
Now, this value ranges between minus one and plus |
|
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|
196 |
|
00:15:00,070 --> 00:15:00,370 |
|
one. |
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|
197 |
|
00:15:06,520 --> 00:15:10,800 |
|
So it's between minus one and plus one. That means |
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|
198 |
|
00:15:10,800 --> 00:15:15,840 |
|
it's never smaller |
|
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|
199 |
|
00:15:15,840 --> 00:15:20,200 |
|
than minus one or greater than one. It's between |
|
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|
200 |
|
00:15:20,200 --> 00:15:21,480 |
|
minus one and plus one. |
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|
201 |
|
00:15:24,360 --> 00:15:28,300 |
|
Make sense? I mean if your value is suppose you |
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|
202 |
|
00:15:28,300 --> 00:15:34,520 |
|
did mistake for any of these computations and R |
|
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|
203 |
|
00:15:34,520 --> 00:15:41,710 |
|
might be 1.15, 115. That means there is an error. |
|
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|
204 |
|
00:15:42,270 --> 00:15:45,870 |
|
Or for example, if R is negative 1.5, that means |
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|
205 |
|
00:15:45,870 --> 00:15:49,610 |
|
there is a mistake. So you have to find or figure |
|
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|
206 |
|
00:15:49,610 --> 00:15:55,670 |
|
out what is that mistake. So that's simple |
|
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|
207 |
|
00:15:55,670 --> 00:15:59,090 |
|
calculations. Usually in the exam, we will give |
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|
208 |
|
00:15:59,090 --> 00:16:01,350 |
|
the formula for the correlation coefficient, as we |
|
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|
209 |
|
00:16:01,350 --> 00:16:03,590 |
|
mentioned before. In addition to that, we will |
|
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|
210 |
|
00:16:03,590 --> 00:16:04,330 |
|
give the summation. |
|
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|
211 |
|
00:16:07,780 --> 00:16:12,720 |
|
The sum of xy is given, sum x squared and sum y |
|
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|
212 |
|
00:16:12,720 --> 00:16:18,320 |
|
squared. Also sum of x and sum of y, in order to |
|
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|
213 |
|
00:16:18,320 --> 00:16:22,320 |
|
determine the means of x and y. For example, |
|
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|
214 |
|
00:16:22,520 --> 00:16:26,860 |
|
suppose I give sum of xi and i goes from 1 to 10 |
|
|
|
215 |
|
00:16:26,860 --> 00:16:31,760 |
|
is 700, for example. You have to know that the |
|
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|
216 |
|
00:16:31,760 --> 00:16:38,720 |
|
sample size is 10, so x bar. is 700 divided by 10, |
|
|
|
217 |
|
00:16:39,320 --> 00:16:46,180 |
|
so it's 7. Then use the curve to compute the |
|
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|
218 |
|
00:16:46,180 --> 00:16:52,000 |
|
coefficient of correlation. Questions? I think |
|
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|
219 |
|
00:16:52,000 --> 00:16:55,900 |
|
straightforward, maybe the easiest topic in this |
|
|
|
220 |
|
00:16:55,900 --> 00:17:02,980 |
|
book is to compute the coefficient of correlation |
|
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|
221 |
|
00:17:02,980 --> 00:17:09,070 |
|
or correlation coefficient. Now my question is, do |
|
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|
222 |
|
00:17:09,070 --> 00:17:13,090 |
|
you think outliers affect the correlation |
|
|
|
223 |
|
00:17:13,090 --> 00:17:13,690 |
|
coefficient? |
|
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|
224 |
|
00:17:17,010 --> 00:17:23,210 |
|
We said last time outliers affect the mean, the |
|
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|
225 |
|
00:17:23,210 --> 00:17:28,310 |
|
range, the variance. Now the question is, do |
|
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|
226 |
|
00:17:28,310 --> 00:17:33,510 |
|
outliers affect the correlation? |
|
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|
227 |
|
00:17:37,410 --> 00:17:38,170 |
|
Y. |
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|
228 |
|
00:17:43,830 --> 00:17:51,330 |
|
Exactly. The formula for R has X bar in it or Y |
|
|
|
229 |
|
00:17:51,330 --> 00:17:56,670 |
|
bar. So it means outliers affect |
|
|
|
230 |
|
00:17:56,670 --> 00:18:01,210 |
|
the correlation coefficient. So the answer is yes. |
|
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|
231 |
|
00:18:03,470 --> 00:18:06,410 |
|
Here we have x bar and y bar. Also, there is |
|
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|
232 |
|
00:18:06,410 --> 00:18:10,690 |
|
another formula to compute R. That formula is |
|
|
|
233 |
|
00:18:10,690 --> 00:18:13,370 |
|
given by covariance between x and y. |
|
|
|
234 |
|
00:18:17,510 --> 00:18:21,930 |
|
These two formulas are quite similar. I mean, by |
|
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|
235 |
|
00:18:21,930 --> 00:18:26,070 |
|
using this one, we can end with this formula. So |
|
|
|
236 |
|
00:18:26,070 --> 00:18:33,090 |
|
this formula depends on this x is y. standard |
|
|
|
237 |
|
00:18:33,090 --> 00:18:36,170 |
|
deviations of X and Y. That means outlier will |
|
|
|
238 |
|
00:18:36,170 --> 00:18:42,530 |
|
affect the correlation coefficient. So in case of |
|
|
|
239 |
|
00:18:42,530 --> 00:18:45,670 |
|
outliers, R could be changed. |
|
|
|
240 |
|
00:18:51,170 --> 00:18:55,530 |
|
That formula is called simple correlation |
|
|
|
241 |
|
00:18:55,530 --> 00:18:58,790 |
|
coefficient. On the other hand, we have population |
|
|
|
242 |
|
00:18:58,790 --> 00:19:02,200 |
|
correlation coefficient. If you remember last |
|
|
|
243 |
|
00:19:02,200 --> 00:19:08,940 |
|
time, we used X bar as the sample mean and mu as |
|
|
|
244 |
|
00:19:08,940 --> 00:19:14,460 |
|
population mean. Also, S square as sample variance |
|
|
|
245 |
|
00:19:14,460 --> 00:19:18,740 |
|
and sigma square as population variance. Here, R |
|
|
|
246 |
|
00:19:18,740 --> 00:19:24,360 |
|
is used as sample coefficient of correlation and |
|
|
|
247 |
|
00:19:24,360 --> 00:19:29,420 |
|
rho, this Greek letter pronounced as rho. Rho is |
|
|
|
248 |
|
00:19:29,420 --> 00:19:35,160 |
|
used for population coefficient of correlation. |
|
|
|
249 |
|
00:19:37,640 --> 00:19:42,040 |
|
There are some features of R or Rho. The first one |
|
|
|
250 |
|
00:19:42,040 --> 00:19:47,960 |
|
is unity-free. R or Rho is unity-free. That means |
|
|
|
251 |
|
00:19:47,960 --> 00:19:54,900 |
|
if X represents... |
|
|
|
252 |
|
00:19:54,900 --> 00:19:58,960 |
|
And let's assume that the correlation between X |
|
|
|
253 |
|
00:19:58,960 --> 00:20:02,040 |
|
and Y equals 0.75. |
|
|
|
254 |
|
00:20:04,680 --> 00:20:07,260 |
|
Now, in this case, there is no unity. You cannot |
|
|
|
255 |
|
00:20:07,260 --> 00:20:13,480 |
|
say 0.75 years or 0.75 kilograms. It's unity-free. |
|
|
|
256 |
|
00:20:13,940 --> 00:20:17,840 |
|
There is no unit for the correlation coefficient, |
|
|
|
257 |
|
00:20:18,020 --> 00:20:21,120 |
|
the same as Cv. If you remember Cv, the |
|
|
|
258 |
|
00:20:21,120 --> 00:20:24,320 |
|
coefficient of correlation, also this one is unity |
|
|
|
259 |
|
00:20:24,320 --> 00:20:30,500 |
|
-free. The second feature of R ranges between |
|
|
|
260 |
|
00:20:30,500 --> 00:20:36,740 |
|
minus one and plus one. As I mentioned, R lies |
|
|
|
261 |
|
00:20:36,740 --> 00:20:42,340 |
|
between minus one and plus one. Now, by using the |
|
|
|
262 |
|
00:20:42,340 --> 00:20:48,100 |
|
value of R, you can determine two things. Number |
|
|
|
263 |
|
00:20:48,100 --> 00:20:53,360 |
|
one, we can determine the direction. and strength |
|
|
|
264 |
|
00:20:53,360 --> 00:20:56,940 |
|
by using the sign you can determine if there |
|
|
|
265 |
|
00:20:56,940 --> 00:21:03,980 |
|
exists positive or negative so sign of R determine |
|
|
|
266 |
|
00:21:03,980 --> 00:21:08,040 |
|
negative or positive relationship the direction |
|
|
|
267 |
|
00:21:08,040 --> 00:21:17,840 |
|
the absolute value of R I mean absolute of R I |
|
|
|
268 |
|
00:21:17,840 --> 00:21:21,980 |
|
mean ignore the sign So the absolute value of R |
|
|
|
269 |
|
00:21:21,980 --> 00:21:24,100 |
|
determines the strength. |
|
|
|
270 |
|
00:21:27,700 --> 00:21:30,760 |
|
So by using the sine of R, you can determine the |
|
|
|
271 |
|
00:21:30,760 --> 00:21:35,680 |
|
direction, either positive or negative. By using |
|
|
|
272 |
|
00:21:35,680 --> 00:21:37,740 |
|
the absolute value, you can determine the |
|
|
|
273 |
|
00:21:37,740 --> 00:21:43,500 |
|
strength. We can split the strength into two |
|
|
|
274 |
|
00:21:43,500 --> 00:21:52,810 |
|
parts, either strong, moderate, or weak. So weak, |
|
|
|
275 |
|
00:21:53,770 --> 00:21:59,130 |
|
moderate, and strong by using the absolute value |
|
|
|
276 |
|
00:21:59,130 --> 00:22:03,870 |
|
of R. The closer to minus one, if R is close to |
|
|
|
277 |
|
00:22:03,870 --> 00:22:07,010 |
|
minus one, the stronger the negative relationship |
|
|
|
278 |
|
00:22:07,010 --> 00:22:09,430 |
|
between X and Y. For example, imagine |
|
|
|
279 |
|
00:22:22,670 --> 00:22:26,130 |
|
And as we mentioned, R ranges between minus 1 and |
|
|
|
280 |
|
00:22:26,130 --> 00:22:26,630 |
|
plus 1. |
|
|
|
281 |
|
00:22:30,070 --> 00:22:35,710 |
|
So if R is close to minus 1, it's a strong |
|
|
|
282 |
|
00:22:35,710 --> 00:22:41,250 |
|
relationship. Strong linked relationship. The |
|
|
|
283 |
|
00:22:41,250 --> 00:22:45,190 |
|
closer to 1, the stronger the positive |
|
|
|
284 |
|
00:22:45,190 --> 00:22:49,230 |
|
relationship. I mean, if R is close. Strong |
|
|
|
285 |
|
00:22:49,230 --> 00:22:54,480 |
|
positive. So strong in either direction, either to |
|
|
|
286 |
|
00:22:54,480 --> 00:22:57,640 |
|
the left side or to the right side. Strong |
|
|
|
287 |
|
00:22:57,640 --> 00:23:00,280 |
|
negative. On the other hand, there exists strong |
|
|
|
288 |
|
00:23:00,280 --> 00:23:05,940 |
|
negative relationship. Positive. Positive. If R is |
|
|
|
289 |
|
00:23:05,940 --> 00:23:10,640 |
|
close to zero, weak. Here we can say there exists |
|
|
|
290 |
|
00:23:10,640 --> 00:23:15,940 |
|
weak relationship between X and Y. |
|
|
|
291 |
|
00:23:19,260 --> 00:23:25,480 |
|
If R is close to 0.5 or |
|
|
|
292 |
|
00:23:25,480 --> 00:23:32,320 |
|
minus 0.5, you can say there exists positive |
|
|
|
293 |
|
00:23:32,320 --> 00:23:38,840 |
|
-moderate or negative-moderate relationship. So |
|
|
|
294 |
|
00:23:38,840 --> 00:23:42,200 |
|
you can split or you can divide the strength of |
|
|
|
295 |
|
00:23:42,200 --> 00:23:44,540 |
|
the relationship between X and Y into three parts. |
|
|
|
296 |
|
00:23:45,860 --> 00:23:50,700 |
|
Strong, close to minus one of Plus one, weak, |
|
|
|
297 |
|
00:23:51,060 --> 00:23:59,580 |
|
close to zero, moderate, close to 0.5. 0.5 is |
|
|
|
298 |
|
00:23:59,580 --> 00:24:04,580 |
|
halfway between 0 and 1, and minus 0.5 is also |
|
|
|
299 |
|
00:24:04,580 --> 00:24:09,040 |
|
halfway between minus 1 and 0. Now for example, |
|
|
|
300 |
|
00:24:09,920 --> 00:24:15,580 |
|
what's about if R equals minus 0.5? Suppose R1 is |
|
|
|
301 |
|
00:24:15,580 --> 00:24:16,500 |
|
minus 0.5. |
|
|
|
302 |
|
00:24:20,180 --> 00:24:27,400 |
|
strong negative or equal minus point eight strong |
|
|
|
303 |
|
00:24:27,400 --> 00:24:33,540 |
|
negative which is more strong nine nine because |
|
|
|
304 |
|
00:24:33,540 --> 00:24:39,670 |
|
this value is close closer to minus one than Minus |
|
|
|
305 |
|
00:24:39,670 --> 00:24:44,070 |
|
0.8. Even this value is greater than minus 0.9, |
|
|
|
306 |
|
00:24:44,530 --> 00:24:50,870 |
|
but minus 0.9 is close to minus 1, more closer to |
|
|
|
307 |
|
00:24:50,870 --> 00:24:56,910 |
|
minus 1 than minus 0.8. On the other hand, if R |
|
|
|
308 |
|
00:24:56,910 --> 00:25:01,190 |
|
equals 0.75, that means there exists positive |
|
|
|
309 |
|
00:25:01,190 --> 00:25:06,970 |
|
relationship. If R equals 0.85, also there exists |
|
|
|
310 |
|
00:25:06,970 --> 00:25:13,540 |
|
positive. But R2 is stronger than R1, because 0.85 |
|
|
|
311 |
|
00:25:13,540 --> 00:25:20,980 |
|
is closer to plus 1 than 0.7. So we can say that |
|
|
|
312 |
|
00:25:20,980 --> 00:25:23,960 |
|
there exists strong relationship between X and Y, |
|
|
|
313 |
|
00:25:24,020 --> 00:25:27,260 |
|
and this relationship is positive. So again, by |
|
|
|
314 |
|
00:25:27,260 --> 00:25:32,530 |
|
using the sign, you can tell the direction. The |
|
|
|
315 |
|
00:25:32,530 --> 00:25:35,910 |
|
absolute value can tell the strength of the |
|
|
|
316 |
|
00:25:35,910 --> 00:25:39,870 |
|
relationship between X and Y. So there are five |
|
|
|
317 |
|
00:25:39,870 --> 00:25:44,150 |
|
features of R, unity-free. Ranges between minus |
|
|
|
318 |
|
00:25:44,150 --> 00:25:47,750 |
|
one and plus one. Closer to minus one, it means |
|
|
|
319 |
|
00:25:47,750 --> 00:25:51,950 |
|
stronger negative. Closer to plus one, stronger |
|
|
|
320 |
|
00:25:51,950 --> 00:25:56,410 |
|
positive. Close to zero, it means there is no |
|
|
|
321 |
|
00:25:56,410 --> 00:26:00,790 |
|
relationship. Or the weaker, the relationship |
|
|
|
322 |
|
00:26:00,790 --> 00:26:13,240 |
|
between X and Y. By using scatter plots, we |
|
|
|
323 |
|
00:26:13,240 --> 00:26:18,160 |
|
can construct a scatter plot by plotting the Y |
|
|
|
324 |
|
00:26:18,160 --> 00:26:24,060 |
|
values versus the X values. Y in the vertical axis |
|
|
|
325 |
|
00:26:24,060 --> 00:26:28,400 |
|
and X in the horizontal axis. If you look |
|
|
|
326 |
|
00:26:28,400 --> 00:26:34,500 |
|
carefully at graph number one and three, We see |
|
|
|
327 |
|
00:26:34,500 --> 00:26:42,540 |
|
that all the points lie on the straight line, |
|
|
|
328 |
|
00:26:44,060 --> 00:26:48,880 |
|
either this way or the other way. If all the |
|
|
|
329 |
|
00:26:48,880 --> 00:26:52,320 |
|
points lie on the straight line, it means they |
|
|
|
330 |
|
00:26:52,320 --> 00:26:56,970 |
|
exist perfectly. not even strong it's perfect |
|
|
|
331 |
|
00:26:56,970 --> 00:27:02,710 |
|
relationship either negative or positive so this |
|
|
|
332 |
|
00:27:02,710 --> 00:27:07,530 |
|
one perfect negative negative |
|
|
|
333 |
|
00:27:07,530 --> 00:27:14,090 |
|
because x increases y goes down decline so if x is |
|
|
|
334 |
|
00:27:14,090 --> 00:27:19,590 |
|
for example five maybe y is supposed to twenty if |
|
|
|
335 |
|
00:27:19,590 --> 00:27:25,510 |
|
x increased to seven maybe y is fifteen So if X |
|
|
|
336 |
|
00:27:25,510 --> 00:27:29,290 |
|
increases, in this case, Y declines or decreases, |
|
|
|
337 |
|
00:27:29,850 --> 00:27:34,290 |
|
it means there exists negative relationship. On |
|
|
|
338 |
|
00:27:34,290 --> 00:27:40,970 |
|
the other hand, the left corner here, positive |
|
|
|
339 |
|
00:27:40,970 --> 00:27:44,710 |
|
relationship, because X increases, Y also goes up. |
|
|
|
340 |
|
00:27:45,970 --> 00:27:48,990 |
|
And perfect, because all the points lie on the |
|
|
|
341 |
|
00:27:48,990 --> 00:27:52,110 |
|
straight line. So it's perfect, positive, perfect, |
|
|
|
342 |
|
00:27:52,250 --> 00:27:57,350 |
|
negative relationship. So it's straightforward to |
|
|
|
343 |
|
00:27:57,350 --> 00:27:59,550 |
|
determine if it's perfect by using scatterplot. |
|
|
|
344 |
|
00:28:02,230 --> 00:28:04,950 |
|
Also, by scatterplot, you can tell the direction |
|
|
|
345 |
|
00:28:04,950 --> 00:28:09,270 |
|
of the relationship. For the second scatterplot, |
|
|
|
346 |
|
00:28:09,630 --> 00:28:12,270 |
|
it seems to be that there exists negative |
|
|
|
347 |
|
00:28:12,270 --> 00:28:13,730 |
|
relationship between X and Y. |
|
|
|
348 |
|
00:28:16,850 --> 00:28:21,030 |
|
In this one, also there exists a relationship |
|
|
|
349 |
|
00:28:24,730 --> 00:28:32,170 |
|
positive which one is strong more strong this |
|
|
|
350 |
|
00:28:32,170 --> 00:28:37,110 |
|
one is stronger because the points are close to |
|
|
|
351 |
|
00:28:37,110 --> 00:28:40,710 |
|
the straight line much more than the other scatter |
|
|
|
352 |
|
00:28:40,710 --> 00:28:43,410 |
|
plot so you can say there exists negative |
|
|
|
353 |
|
00:28:43,410 --> 00:28:45,810 |
|
relationship but that one is stronger than the |
|
|
|
354 |
|
00:28:45,810 --> 00:28:49,550 |
|
other one this one is positive but the points are |
|
|
|
355 |
|
00:28:49,550 --> 00:28:55,400 |
|
scattered around the straight line so you can tell |
|
|
|
356 |
|
00:28:55,400 --> 00:29:00,000 |
|
the direction and sometimes sometimes not all the |
|
|
|
357 |
|
00:29:00,000 --> 00:29:04,640 |
|
time you can tell the strength sometimes it's very |
|
|
|
358 |
|
00:29:04,640 --> 00:29:07,960 |
|
clear that the relation is strong if the points |
|
|
|
359 |
|
00:29:07,960 --> 00:29:11,480 |
|
are very close straight line that means the |
|
|
|
360 |
|
00:29:11,480 --> 00:29:15,940 |
|
relation is strong now the other one the last one |
|
|
|
361 |
|
00:29:15,940 --> 00:29:23,850 |
|
here As X increases, Y stays at the same value. |
|
|
|
362 |
|
00:29:23,970 --> 00:29:29,450 |
|
For example, if Y is 20 and X is 1. X is 1, Y is |
|
|
|
363 |
|
00:29:29,450 --> 00:29:33,870 |
|
20. X increases to 2, for example. Y is still 20. |
|
|
|
364 |
|
00:29:34,650 --> 00:29:37,230 |
|
So that means there is no relationship between X |
|
|
|
365 |
|
00:29:37,230 --> 00:29:41,830 |
|
and Y. It's a constant. Y equals a constant value. |
|
|
|
366 |
|
00:29:42,690 --> 00:29:50,490 |
|
Whatever X is, Y will have constant value. So that |
|
|
|
367 |
|
00:29:50,490 --> 00:29:54,790 |
|
means there is no relationship between X and Y. |
|
|
|
368 |
|
00:29:56,490 --> 00:30:01,850 |
|
Let's see how can we compute the correlation |
|
|
|
369 |
|
00:30:01,850 --> 00:30:07,530 |
|
between two variables. For example, suppose we |
|
|
|
370 |
|
00:30:07,530 --> 00:30:12,150 |
|
have data for father's height and son's height. |
|
|
|
371 |
|
00:30:13,370 --> 00:30:16,510 |
|
And we are interested to see if father's height |
|
|
|
372 |
|
00:30:16,510 --> 00:30:21,730 |
|
affects his son's height. So we have data for 10 |
|
|
|
373 |
|
00:30:21,730 --> 00:30:28,610 |
|
observations here. Father number one, his height |
|
|
|
374 |
|
00:30:28,610 --> 00:30:38,570 |
|
is 64 inches. And you know that inch equals 2 |
|
|
|
375 |
|
00:30:38,570 --> 00:30:39,230 |
|
.5. |
|
|
|
376 |
|
00:30:43,520 --> 00:30:52,920 |
|
So X is 64, Sun's height is 65. X is 68, Sun's |
|
|
|
377 |
|
00:30:52,920 --> 00:30:58,820 |
|
height is 67 and so on. Sometimes, if the dataset |
|
|
|
378 |
|
00:30:58,820 --> 00:31:02,600 |
|
is small enough, as in this example, we have just |
|
|
|
379 |
|
00:31:02,600 --> 00:31:08,640 |
|
10 observations, you can tell the direction. I |
|
|
|
380 |
|
00:31:08,640 --> 00:31:12,060 |
|
mean, you can say, yes, for this specific example, |
|
|
|
381 |
|
00:31:12,580 --> 00:31:15,280 |
|
there exists positive relationship between x and |
|
|
|
382 |
|
00:31:15,280 --> 00:31:20,820 |
|
y. But if the data set is large, it's very hard to |
|
|
|
383 |
|
00:31:20,820 --> 00:31:22,620 |
|
figure out if the relation is positive or |
|
|
|
384 |
|
00:31:22,620 --> 00:31:26,400 |
|
negative. So we have to find or to compute the |
|
|
|
385 |
|
00:31:26,400 --> 00:31:29,700 |
|
coefficient of correlation in order to see there |
|
|
|
386 |
|
00:31:29,700 --> 00:31:32,940 |
|
exists positive, negative, strong, weak, or |
|
|
|
387 |
|
00:31:32,940 --> 00:31:37,820 |
|
moderate. but again you can tell from this simple |
|
|
|
388 |
|
00:31:37,820 --> 00:31:40,280 |
|
example yes there is a positive relationship |
|
|
|
389 |
|
00:31:40,280 --> 00:31:44,660 |
|
because just if you pick random numbers here for |
|
|
|
390 |
|
00:31:44,660 --> 00:31:49,240 |
|
example 64 father's height his son's height 65 if |
|
|
|
391 |
|
00:31:49,240 --> 00:31:54,600 |
|
we move up here to 70 for father's height his |
|
|
|
392 |
|
00:31:54,600 --> 00:32:00,160 |
|
son's height is going to be 72 so as father |
|
|
|
393 |
|
00:32:00,160 --> 00:32:05,020 |
|
heights increases Also, son's height increases. |
|
|
|
394 |
|
00:32:06,320 --> 00:32:11,700 |
|
For example, 77, father's height. His son's height |
|
|
|
395 |
|
00:32:11,700 --> 00:32:15,160 |
|
is 76. So that means there exists positive |
|
|
|
396 |
|
00:32:15,160 --> 00:32:19,740 |
|
relationship. Make sense? But again, for large |
|
|
|
397 |
|
00:32:19,740 --> 00:32:20,780 |
|
data, you cannot tell that. |
|
|
|
398 |
|
00:32:31,710 --> 00:32:36,090 |
|
If, again, by using this data, small data, you can |
|
|
|
399 |
|
00:32:36,090 --> 00:32:40,730 |
|
determine just the length, the strength, I'm |
|
|
|
400 |
|
00:32:40,730 --> 00:32:43,490 |
|
sorry, the strength of a relationship or the |
|
|
|
401 |
|
00:32:43,490 --> 00:32:47,590 |
|
direction of the relationship. Just pick any |
|
|
|
402 |
|
00:32:47,590 --> 00:32:51,030 |
|
number at random. For example, if we pick this |
|
|
|
403 |
|
00:32:51,030 --> 00:32:51,290 |
|
number. |
|
|
|
404 |
|
00:32:55,050 --> 00:33:00,180 |
|
Father's height is 68, his son's height is 70. Now |
|
|
|
405 |
|
00:33:00,180 --> 00:33:02,180 |
|
suppose we pick another number that is greater |
|
|
|
406 |
|
00:33:02,180 --> 00:33:05,840 |
|
than 68, then let's see what will happen. For |
|
|
|
407 |
|
00:33:05,840 --> 00:33:11,060 |
|
father's height 70, his son's height increases up |
|
|
|
408 |
|
00:33:11,060 --> 00:33:17,160 |
|
to 72. Similarly, 72 father's height, his son's |
|
|
|
409 |
|
00:33:17,160 --> 00:33:22,060 |
|
height 75. So that means X increases, Y also |
|
|
|
410 |
|
00:33:22,060 --> 00:33:25,740 |
|
increases. So that means there exists both of |
|
|
|
411 |
|
00:33:25,740 --> 00:33:32,570 |
|
them. For sure it is hard to tell this direction |
|
|
|
412 |
|
00:33:32,570 --> 00:33:36,130 |
|
if the data is large. Because maybe you will find |
|
|
|
413 |
|
00:33:36,130 --> 00:33:40,250 |
|
as X increases for one point, Y maybe decreases |
|
|
|
414 |
|
00:33:40,250 --> 00:33:43,610 |
|
for that point. So it depends on the data you |
|
|
|
415 |
|
00:33:43,610 --> 00:33:49,010 |
|
have. Anyway, let's see how can we compute R. I |
|
|
|
416 |
|
00:33:49,010 --> 00:33:53,770 |
|
will use Excel to show how can we do these |
|
|
|
417 |
|
00:33:53,770 --> 00:33:54,550 |
|
calculations. |
|
|
|
418 |
|
00:34:02,110 --> 00:34:06,530 |
|
The screen is clear. But give me the data of X and |
|
|
|
419 |
|
00:34:06,530 --> 00:34:06,750 |
|
Y. |
|
|
|
420 |
|
00:34:10,710 --> 00:34:14,310 |
|
X is 64. 68. |
|
|
|
421 |
|
00:34:18,910 --> 00:34:26,830 |
|
68. 78. There is one 68. 78. 74. |
|
|
|
422 |
|
00:34:31,120 --> 00:34:37,600 |
|
Seventy-four. Seventy-five. Seventy-six. |
|
|
|
423 |
|
00:34:38,360 --> 00:34:42,240 |
|
Seventy-seven. Seventy-five. So that's the values |
|
|
|
424 |
|
00:34:42,240 --> 00:34:49,440 |
|
of X, Y values. Seventy. Seventy-five. Seventy |
|
|
|
425 |
|
00:34:49,440 --> 00:34:49,800 |
|
-seven. |
|
|
|
426 |
|
00:35:17,230 --> 00:35:23,730 |
|
So first we have to compute it. x times y so |
|
|
|
427 |
|
00:35:23,730 --> 00:35:28,270 |
|
that's as x times |
|
|
|
428 |
|
00:35:28,270 --> 00:35:38,230 |
|
the value of y so 46 times 65 equals 4160 x |
|
|
|
429 |
|
00:35:38,230 --> 00:35:46,050 |
|
squared so this value squared for y squared 65 |
|
|
|
430 |
|
00:35:48,660 --> 00:35:53,700 |
|
Square and we have to do this one for the rest of |
|
|
|
431 |
|
00:35:53,700 --> 00:36:03,160 |
|
the data So |
|
|
|
432 |
|
00:36:03,160 --> 00:36:07,600 |
|
that's the sum of XY sum X squared and Y squared |
|
|
|
433 |
|
00:36:07,600 --> 00:36:13,480 |
|
now the summation So |
|
|
|
434 |
|
00:36:13,480 --> 00:36:17,180 |
|
that's the sum of X and Y |
|
|
|
435 |
|
00:36:20,380 --> 00:36:27,040 |
|
We have to compute the mean of x and y. So that is |
|
|
|
436 |
|
00:36:27,040 --> 00:36:31,380 |
|
this sum divided by n, where n is 10 in this case. |
|
|
|
437 |
|
00:36:34,600 --> 00:36:36,100 |
|
So this is the first step. |
|
|
|
438 |
|
00:36:41,820 --> 00:36:48,900 |
|
Let's see how can we compute R. R, we have sum of |
|
|
|
439 |
|
00:36:48,900 --> 00:37:00,780 |
|
x, y. minus n is 10 times x bar times y bar. This |
|
|
|
440 |
|
00:37:00,780 --> 00:37:03,100 |
|
is the first quantity. The other one is square |
|
|
|
441 |
|
00:37:03,100 --> 00:37:08,580 |
|
root of sum |
|
|
|
442 |
|
00:37:08,580 --> 00:37:15,420 |
|
x squared minus n x bar squared. |
|
|
|
443 |
|
00:37:18,830 --> 00:37:24,770 |
|
times some y squared minus n times y bar squared. |
|
|
|
444 |
|
00:37:28,930 --> 00:37:34,090 |
|
And we have to find the square root of this value. |
|
|
|
445 |
|
00:37:34,210 --> 00:37:40,810 |
|
So square root, that will give this result. So now |
|
|
|
446 |
|
00:37:40,810 --> 00:37:46,990 |
|
R equals this value divided by |
|
|
|
447 |
|
00:37:49,670 --> 00:37:54,890 |
|
155 and round always to two decimal places will |
|
|
|
448 |
|
00:37:54,890 --> 00:38:05,590 |
|
give 87 so r is 87 so first step we have x and y |
|
|
|
449 |
|
00:38:05,590 --> 00:38:12,470 |
|
compute xy x squared y squared sum of these all of |
|
|
|
450 |
|
00:38:12,470 --> 00:38:18,100 |
|
these then x bar y bar values are given Then just |
|
|
|
451 |
|
00:38:18,100 --> 00:38:20,820 |
|
use the formula you have, we'll get R to be at |
|
|
|
452 |
|
00:38:20,820 --> 00:38:31,540 |
|
seven. So in this case, if we just go back to |
|
|
|
453 |
|
00:38:31,540 --> 00:38:33,400 |
|
the slide we have here. |
|
|
|
454 |
|
00:38:36,440 --> 00:38:41,380 |
|
As we mentioned, father's height is the |
|
|
|
455 |
|
00:38:41,380 --> 00:38:45,640 |
|
explanatory variable. Son's height is the response |
|
|
|
456 |
|
00:38:45,640 --> 00:38:46,060 |
|
variable. |
|
|
|
457 |
|
00:38:49,190 --> 00:38:52,810 |
|
And that simple calculation gives summation of xi, |
|
|
|
458 |
|
00:38:54,050 --> 00:38:57,810 |
|
summation of yi, summation x squared, y squared, |
|
|
|
459 |
|
00:38:57,970 --> 00:39:02,690 |
|
and some xy. And finally, we'll get that result, |
|
|
|
460 |
|
00:39:02,850 --> 00:39:07,850 |
|
87%. Now, the sign is positive. That means there |
|
|
|
461 |
|
00:39:07,850 --> 00:39:13,960 |
|
exists positive. And 0.87 is close to 1. That |
|
|
|
462 |
|
00:39:13,960 --> 00:39:17,320 |
|
means there exists strong positive relationship |
|
|
|
463 |
|
00:39:17,320 --> 00:39:22,480 |
|
between father's and son's height. I think the |
|
|
|
464 |
|
00:39:22,480 --> 00:39:25,060 |
|
calculation is straightforward. |
|
|
|
465 |
|
00:39:27,280 --> 00:39:33,280 |
|
Now, for this example, the data are given in |
|
|
|
466 |
|
00:39:33,280 --> 00:39:37,460 |
|
inches. I mean father's and son's height in inch. |
|
|
|
467 |
|
00:39:38,730 --> 00:39:41,050 |
|
Suppose we want to convert from inch to |
|
|
|
468 |
|
00:39:41,050 --> 00:39:44,750 |
|
centimeter, so we have to multiply by 2. Do you |
|
|
|
469 |
|
00:39:44,750 --> 00:39:52,050 |
|
think in this case, R will change? So if we add or |
|
|
|
470 |
|
00:39:52,050 --> 00:39:59,910 |
|
multiply or divide, R will not change? I mean, if |
|
|
|
471 |
|
00:39:59,910 --> 00:40:06,880 |
|
we have X values, And we divide or multiply X, I |
|
|
|
472 |
|
00:40:06,880 --> 00:40:09,460 |
|
mean each value of X, by a number, by a fixed |
|
|
|
473 |
|
00:40:09,460 --> 00:40:12,600 |
|
value. For example, suppose here we multiplied |
|
|
|
474 |
|
00:40:12,600 --> 00:40:19,460 |
|
each value by 2.5 for X. Also multiply Y by the |
|
|
|
475 |
|
00:40:19,460 --> 00:40:24,520 |
|
same value, 2.5. Y will be the same. In addition |
|
|
|
476 |
|
00:40:24,520 --> 00:40:28,920 |
|
to that, if we multiply X by 2.5, for example, and |
|
|
|
477 |
|
00:40:28,920 --> 00:40:34,960 |
|
Y by 5, also R will not change. But you have to be |
|
|
|
478 |
|
00:40:34,960 --> 00:40:39,400 |
|
careful. We multiply each value of x by the same |
|
|
|
479 |
|
00:40:39,400 --> 00:40:45,700 |
|
number. And each value of y by the same number, |
|
|
|
480 |
|
00:40:45,820 --> 00:40:49,640 |
|
that number may be different from x. So I mean |
|
|
|
481 |
|
00:40:49,640 --> 00:40:56,540 |
|
multiply x by 2.5 and y by minus 1 or plus 2 or |
|
|
|
482 |
|
00:40:56,540 --> 00:41:01,000 |
|
whatever you have. But if it's negative, then |
|
|
|
483 |
|
00:41:01,000 --> 00:41:05,640 |
|
we'll get negative answer. I mean if Y is |
|
|
|
484 |
|
00:41:05,640 --> 00:41:08,060 |
|
positive, for example, and we multiply each value |
|
|
|
485 |
|
00:41:08,060 --> 00:41:13,000 |
|
Y by minus one, that will give negative sign. But |
|
|
|
486 |
|
00:41:13,000 --> 00:41:17,640 |
|
here I meant if we multiply this value by positive |
|
|
|
487 |
|
00:41:17,640 --> 00:41:21,320 |
|
sign, plus two, plus three, and let's see how can |
|
|
|
488 |
|
00:41:21,320 --> 00:41:22,540 |
|
we do that by Excel. |
|
|
|
489 |
|
00:41:26,320 --> 00:41:31,480 |
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Now this is the data we have. I just make copy. |
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490 |
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00:41:37,730 --> 00:41:45,190 |
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I will multiply each value X by 2.5. And I will do |
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491 |
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00:41:45,190 --> 00:41:49,590 |
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the same for Y |
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492 |
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00:41:49,590 --> 00:41:57,190 |
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value. I will replace this data by the new one. |
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493 |
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00:41:58,070 --> 00:42:00,410 |
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For sure the calculations will, the computations |
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494 |
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00:42:00,410 --> 00:42:09,740 |
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here will change, but R will stay the same. So |
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495 |
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00:42:09,740 --> 00:42:14,620 |
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here we multiply each x by 2.5 and the same for y. |
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496 |
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00:42:15,540 --> 00:42:19,400 |
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The calculations here are different. We have |
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497 |
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00:42:19,400 --> 00:42:22,960 |
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different sum, different sum of x, sum of y and so |
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498 |
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00:42:22,960 --> 00:42:31,040 |
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on, but are the same. Let's see if we multiply |
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499 |
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00:42:31,040 --> 00:42:38,880 |
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just x by 2.5 and y the same. |
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500 |
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00:42:41,840 --> 00:42:49,360 |
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So we multiplied x by 2.5 and we keep it make |
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501 |
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00:42:49,360 --> 00:42:57,840 |
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sense? Now let's see how outliers will affect the |
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502 |
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00:42:57,840 --> 00:43:03,260 |
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value of R. Let's say if we change one point in |
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503 |
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00:43:03,260 --> 00:43:08,480 |
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the data set support. I just changed 64. |
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504 |
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00:43:13,750 --> 00:43:24,350 |
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for example if just by typo and just enter 6 so it |
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505 |
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00:43:24,350 --> 00:43:33,510 |
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was 87 it becomes 0.7 so there is a big difference |
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506 |
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00:43:33,510 --> 00:43:38,670 |
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between 0.87 and 0.7 and just we change one value |
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507 |
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00:43:38,670 --> 00:43:45,920 |
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now suppose the other one is zero 82. The other is |
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508 |
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00:43:45,920 --> 00:43:48,260 |
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2, for example. 1. |
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509 |
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00:43:53,380 --> 00:43:59,200 |
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I just changed half of the data. Now R was 87, it |
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510 |
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00:43:59,200 --> 00:44:02,920 |
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becomes 59. That means these outliers, these |
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511 |
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00:44:02,920 --> 00:44:06,180 |
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values for sure are outliers and they fit the |
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512 |
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00:44:06,180 --> 00:44:07,060 |
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correlation coefficient. |
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513 |
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00:44:11,110 --> 00:44:14,970 |
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Now let's see if we just change this 1 to be 200. |
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514 |
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00:44:15,870 --> 00:44:20,430 |
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It will go from 50 to up to 63. That means any |
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515 |
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00:44:20,430 --> 00:44:26,010 |
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changes in x or y values will change the y. But if |
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516 |
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00:44:26,010 --> 00:44:30,070 |
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we add or multiply all the values by a constant, r |
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517 |
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00:44:30,070 --> 00:44:31,170 |
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will stay the same. |
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518 |
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00:44:35,250 --> 00:44:43,590 |
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Any questions? That's the end of chapter 3. I will |
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519 |
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00:44:43,590 --> 00:44:48,990 |
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move quickly to the practice problems we have. And |
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520 |
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00:44:48,990 --> 00:44:55,270 |
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we posted the practice in the course website. |
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