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### æé
1. **2次å
é
åã®åæå**:
- 2ã€ã®æååãæ¯èŒããããã«ã2次å
ã®é
å`dp`ãäœæããŸãã`dp[i][j]`ã¯ãæåå1ã®åiæåãšæåå2ã®åjæåã®æé·å
±ééšåæååã®é·ããè¡šããŸãã
2. **åæå**:
- `dp[0][j]`ãš`dp[i][0]`ã¯ãã¹ãŠ0ã«åæåããŸããããã¯ãäžæ¹ã®æååã空ã§ããå Žåãå
±ééšåã¯0ã«ãªãããã§ãã
3. **DPããŒãã«ã®æŽæ°**:
- æåå1ã®åæåãšæåå2ã®åæåãæ¯èŒããŸãã
- `æåå1ã®içªç®ã®æå`ãš`æåå2ã®jçªç®ã®æå`ãåãã§ããã°ã`dp[i][j] = dp[i-1][j-1] + 1`ã
- ãã以å€ã§ããã°ã`dp[i][j] = 0`ã
4. **çµæã®ååŸ**:
- æçµçã«`dp[m][n]`ãæé·å
±ééšåæååã®é·ããšãªããŸãã
### Pythonã³ãŒãäŸ
```python
def longest_common_subsequence(s1, s2):
m = len(s1)
n = len(s2)
# 2次å
é
åãåæå
dp = [[0] * (n + 1) for _ in range(m + 1)]
# DPããŒãã«ã®æŽæ°
for i in range(1, m + 1):
for j in range(1, n + 1):
if s1[i - 1] == s2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
else:
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
# æçµçãªçµæãè¿ã
return dp[m][n]
# å
¥åæåå
s1 = "ãããããšãã"
s2 = "ãããããšãã"
# åŠç
result = longest_common_subsequence(s1, s2)
print("é£ç¶ããæé·å
±ééšåæååã®é·ã:", result)
```
### å®è¡çµæ
äžèšã®ã³ãŒããå®è¡ãããšã`é£ç¶ããæé·å
±ééšåæååã®é·ã: 4` ãšããçµæãåŸãããŸããå
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æ¬åŒ§ãæ£ããéããããããã«ã次ã®é
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èŠããããŸãããã®åé¡ã§ã¯ãçŸåšã®é
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ãããã£ãŠãå®æããé
åã¯ä»¥äžã®ããã«ãªããŸãïŒ
```
[ { ( ) } ]
```
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\[ \left( \left( \frac{5}{4} + 13 \right) \times 20 \right) \div 5 \]
ãã®åŒã段éçã«èšç®ãããšä»¥äžã®ããã«ãªããŸãïŒ
1. \( \frac{5}{4} = 1.25 \)
2. \( 1.25 + 13 = 14.25 \)
3. \( 14.25 \times 20 = 285 \)
4. \( 285 \div 5 = 57 \)
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2. èªç¶ã®äžã§ããïŒå
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- **ææ**: çåµ2åãå°éºŠç²100g
- **æé **:
1. ç¡æŽç±³ããã«ããã§è
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