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¥ããä»æ¥ã®å€é£ãæºåããããšãã§ããŸãã | NIGHT OUT DINNER PREPARATION PLAN WITH THE AVAILABLE TOOLS
Given the limited resources at hand, the best approach to preparing a dinner is to make use of the available tools and ingredients to create a simple yet satisfying meal. Here's a plan for preparing today's dinner using the items as you mentioned:
1. **Cold Meal Option:**
- **Chicken Cutletes:** Use a small chicken cutlet press to shape the chicken breasts into cutlets. Add a little bit of oil to a pan and cook the chicken until it is fully cooked. Season with your choice of seasonings and sauces.
- **Cold Meal Option 2:**
- Use the bento box to portion out the chicken cutlets and cold vegetables. Add a small container of blue cheese dressing to taste.
- Serve with a small portion of rhubarb for dessert.
This is a simple meal that can be quickly cooked, and is a good choice if you don't have a fully functional cook top.
2. **Cold Meal Option (With Preparation):**
- **Chicken Cutletes:** Use a small chicken cutlet press to shape the chicken breasts into cutlets. Add a little bit of oil to a pan and cook the chicken until it is fully cooked. Season with your choice of seasonings and sauces.
- **Cold Meal Option 2:**
- Use the bento box to portion out the chicken cutlets and cold vegetables. Add a small container of blue cheese dressing to taste.
- Prepare the chicken cutlets and cold vegetables in advance and place in the bento box.
This is a slightly more elaborate option, as you need to prepare the chicken in advance. However, the cold cutletes and vegetables can be packaged in the bento box and left until needed.
3. **Hot Meal Option:**
- **Chicken Cutletes:** Use a small chicken cutlet press to shape the chicken breasts into cutlets. Add a little bit of oil to a pan and cook the chicken until it is fully cooked. Season with your choice of seasonings and sauces.
- **Cold Meal Option 2:**
- Use the bento box to portion out the chicken cutlets and cold vegetables. Add a small container of blue cheese dressing to taste.
- Serve the chicken cutletes hot.
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user: é项1æ䞺äºæŽæææçå¥åïŒå¯ä»¥ä»è¿å¥è¯äžçŽæ¥åŸå°äžäžªæž
æ°çå ææšæïŒèé项2衚蟟æ¯äŒè®©äºº ì°ì
ìåç°é®é¢ä¹å€ã
assistant: é项1æ¯æŽæææïŒå®äŒç»äººç解圌æ€ä¹éŽçå æå
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2ã€ã®æååã§é£ç¶ããæé·å
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žåçãªãé£ç¶ããæé·å
±ééšåæååïŒLCS: Longest Common SubsequenceïŒãåé¡ã«è©²åœããŸãããã®åé¡ã¯ãåçèšç»æ³ã«ãã£ãŠå¹ççã«è§£ãããšãã§ããŸãã以äžã«ããã®åé¡ã解ãããã«å¿
èŠãªã¹ãããã説æããŸãã
### 1. åé¡ã®ç解
2ã€ã®æååãããé£ç¶ããŠããªãéšåæååã§ã¯ãªããé£ç¶ããéšåæååã®æé·ãªãã®ãæ±ããŸãã
### 2. ããŒã¿ã®æºå
- æåå1: ãã¿ãŸããã (s = "ãã¿ãŸããã")
- æåå2: ãé¡ãããŸã (t = "ãé¡ãããŸã")
### 3. ããŒãã«ã®äœæ
åçèšç»æ³ã䜿çšããããã«ã2次å
ã®ããŒãã«ãçšæããŸããããŒãã«ã®åèŠçŽ `dp[i][j]` ã¯ãæåå `s` ã®å `i` æåãšæåå `t` ã®å `j` æåã§åœ¢æãããé£ç¶ããæé·å
±ééšåæååã®é·ããè¡šããŸãã
### 4. ããŒãã«ã®åæå
- `dp[0][j]` ãš `dp[i][0]` ã®å€ã¯å
šãŠ 0 ã«ãªããŸããããã¯ãããããã®æååã空ã®å Žåãå
±ééšåã¯ååšããªãããã§ãã
### 5. ããŒãã«ã®æŽæ°ã«ãŒã«
- `s[i-1] == t[j-1]` ã§ããå Žåã`dp[i][j] = dp[i-1][j-1] + 1`
- `s[i-1] != t[j-1]` ã§ããå Žåã`dp[i][j] = max(dp[i-1][j], dp[i][j-1])`
### 6. ããŒãã«ã®å®æãšçµæã®ååŸ
æçµçã«ã`dp[m][n]` ãçããšãªããŸããããã§ã`m` 㯠`s` ã®é·ãã`n` 㯠`t` ã®é·ãã§ãã
### 7. å®éã®èšç®
以äžã«ãå
·äœçãªèšç®ã瀺ããŸãã
- `s = "ãã¿ãŸããã"` (s = "smgn")
- `t = "ãé¡ãããŸã"` (t = "oyys")
| | | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|---|
| | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã¿ | 3 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| 㟠| 4 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 5 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 6 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 7 | 0 | 1 | 1 | 1 | 1 | 1 | 1 |
| ã | 8 | 0 | 1 | 1 | 1 | 1 | 1 | 2 |
æçµçã«ã`dp[8][7] = 2` ãåŸãããŸãã
### 8. çµæ
2ã€ã®æåå "ãã¿ãŸããã" ãš "ãé¡ãããŸã" ã®é£ç¶ããæé·å
±ééšåæååã®é·ã㯠**2** ã§ãã | ãã®åé¡ã¯å
žåçãªãé£ç¶ããæé·å
±ééšåæååïŒLCS: Longest Common SubsequenceïŒãåé¡ã«è©²åœããŸãããã®åé¡ã¯ãåçèšç»æ³ã«ãã£ãŠå¹ççã«è§£ãããšãã§ããŸãã以äžã«ããã®åé¡ã解ãããã«å¿
èŠãªã¹ãããã説æããŸãã
### 1. åé¡ã®ç解
2ã€ã®æååãããé£ç¶ããŠããªãéšåæååã§ã¯ãªããé£ç¶ããéšåæååã®æé·ãªãã®ãæ±ããŸãã
### 2. ããŒã¿ã®æºå
- æåå1: ãã¿ãŸããã (s = "ãã¿ãŸããã")
- æåå2: ãé¡ãããŸã (t = "ãé¡ãããŸã")
### 3. ããŒãã«ã®äœæ
åçèšç»æ³ã䜿çšããããã«ã2次å
ã®ããŒãã«ãçšæããŸããããŒãã«ã®åèŠçŽ `dp[i][j]` ã¯ãæåå `s` ã®å `i` æåãšæåå `t` ã®å `j` æåã§åœ¢æãããé£ç¶ããæé·å
±ééšåæååã®é·ããè¡šããŸãã
### 4. ããŒãã«ã®åæå
- `dp[0][j]` ãš `dp[i][0]` ã®å€ã¯å
šãŠ 0 ã«ãªããŸããããã¯ãããããã®æååã空ã®å Žåãå
±ééšåã¯ååšããªãããã§ãã
### 5. ããŒãã«ã®æŽæ°ã«ãŒã«
- `s[i-1] == t[j-1]` ã§ããå Žåã`dp[i][j] = dp[i-1][j-1] + 1`
- `s[i-1] != t[j-1]` ã§ããå Žåã`dp[i][j] = max(dp[i-1][j], dp[i][j-1])`
### 6. ããŒãã«ã®å®æãšçµæã®ååŸ
æçµçã«ã`dp[m][n]` ãçããšãªããŸããããã§ã`m` 㯠`s` ã®é·ãã`n` 㯠`t` ã®é·ãã§ãã
### 7. å®éã®èšç®
以äžã«ãå
·äœçãªèšç®ã瀺ããŸãã
- `s = "ãã¿ãŸããã"` (s = "smgn")
- `t = "ãé¡ãããŸã"` (t = "oyys")
| | | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|---|
| | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã¿ | 3 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| 㟠| 4 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 5 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 6 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 7 | 0 | 1 | 1 | 1 | 1 | 1 | 1 |
| ã | 8 | 0 | 1 | 1 | 1 | 1 | 1 | 2 |
æçµçã«ã`dp[8][7] = 2` ãåŸãããŸãã
### 8. çµæ
2ã€ã®æåå "ãã¿ãŸããã" ãš "ãé¡ãããŸã" ã®é£ç¶ããæé·å
±ééšåæååã®é·ã㯠**2** ã§ãã | ãã®åé¡ã¯åçèšç»æ³ã䜿ã£ãŠè§£ãããšãã§ããŸãã以äžã«ãã®æé ã解説ããŸãïŒ
1. **æååã®é·ããæ¯èŒ**:
- æåå1ã®é·ã: `m` (`m = 6`)
- æåå2ã®é·ã: `n` (`n = 8`)
2. **2次å
é
åãäœæ**:
- `dp`: `dp[i][j]` 㯠`æåå1` ã®æåã® `i` æåãš `æåå2` ã®æåã® `j` æåã®ãã¡ãæãé·ãé£ç¶ããå
±ééšåæååã®é·ããè¡šããŸãã
3. **åæå**:
- `dp[0][0]` 㯠`æåå1` ãš `æåå2` ã®é·ããç°ãªããã `0` ã§åæåããŸãã
4. **åçèšç»æ³ã®é©çš**:
- `dp[i][j]` 㯠`æåå1` ã®æåã® `i` æåãš `æåå2` ã®æåã® `j` æåãæ¯èŒããããã®ã€ã³ããã¯ã¹ã«ãªããŸãã
- `dp[i][j] = 0` ãš `dp[i-1][j-1]` ãåãæååã®å ŽåïŒã€ãŸããå
±ééšåæååããªãå ŽåïŒïŒ
- `dp[0][j]` 㯠`0` ã§åæåããŸãã
- ãã以å€ã®å ŽåïŒ
- `dp[i][0]` = 0 (æåå1ã®æåã® `i` æåãšæåå2ãäžèŽãããŸã§ã¯0)
- `dp[i][j] = dp[i-1][j-1] + 1`
- `dp[i][j] = max(dp[i-1][j-1], dp[i][j-1])` (æ¹è¯ããåçèšç»æ³ã®æŽæ°èŠå)
5. **æ倧å€ã®æ¢çŽ¢ãšçµæã®ååŸ**:
- æçµç㪠`dp` é
åã®æ倧å€ã `m` ãš `n` ã§æ¯èŒããŸãã
6. **解çã®åºå**:
- æçµç㪠`dp` é
åã®æ倧å€ã¯ãé£ç¶ããæé·å
±ééšåæååã®é·ãã«ãªããŸãã
以äžãèžãŸããŠã解çã¯ä»¥äžã®ããã«ãªããŸãïŒ
```
dp[6][8] =
[ 0, 0, 0, 0, 0, 0, 0, 0 ]
[ 0, 0, 0, 0, 0, 0, 0, 0 ] |
以äžã®äŸæã¯ãžã§ãŒã¯ïŒç®èïŒãèšã£ãŠããŸããïŒ
ä»æ¥ã®å€©æ°ã¯æé«ã ããå forgetting Needed ocked | ã¯ãããã®äŸæã¯ãžã§ãŒã¯ïŒç®èïŒãèšã£ãŠããŸããåæã®æç« ã¯ãä»æ¥ã®å€©æ°ã¯æé«ã ããå forgetting Needed ockedãã§ãããããã¯ãä»æ¥ã®å€©æ°ã¯æé«ã ããåã¯å¿
èŠãªããããæå³ããŠæžããããžã§ãŒã¯ãšæãããŸãã
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ã«ãåãå¿
èŠã ãããšããç®èãäŒããŠããŸãã
ãããã£ãŠããã®æç« ã¯å€©æ°äºå ±ãšçŸå®ã®ã®ã£ãããå©çšããŠèªè
ã®æåŸ
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èŠãªããããæå³ããŠæžããããžã§ãŒã¯ãšæãããŸãã
ãã®ãžã§ãŒã¯ã¯ãéšãéã£ãŠããã¯ããªã®ã«æŽããŠãããšããç¶æ³ãåæã«ããŠããŸããéåžžã倩æ°ãè¯ãæ¥ã¯åãæããªããŠãè¯ãã§ãããææ«ã®ãumbrella forgetting Neededãã¯ãåãå¿ããããšããæååãé ããŠãã圢ã§ããã®ãžã§ãŒã¯ã® hilarity ã«å¯äžããŠããŸããã€ãŸããææ«ã®ãumbrella forgetting Neededãã¯èªè
ã«ãåãå¿
èŠã ãããšããç®èãäŒããŠããŸãã
ãããã£ãŠããã®æç« ã¯å€©æ°äºå ±ãšçŸå®ã®ã®ã£ãããå©çšããŠèªè
ã®æåŸ
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èŠãªãæŽãã®å€©æ°ãç®èã£ãŠãããããããã¯éšã®å€©æ°ãæåŸ
ããŠããå Žåã«ã¯æ°è±¡äºå ±ãèŠäºã«å€ããããšãç®èã£ãŠããå¯èœæ§ããããŸããæèã«å¿ããŠè§£éãããŸãã
ãã®åçã¯åœ¹ã«ç«ã¡ãŸãããïŒ
質å:以äžã®äŸæã¯ãžã§ãŒã¯ïŒç®èïŒãèšã£ãŠããŸããïŒ
ä»æ¥ã®å€©æ°ã¯æé«ã ããå forgetting Needed ocked
åç: This is a straightforward, albeit slightly awkward, statement that means "today's weather is the best." The use of the words "forgotting" and "Needed" in the second part of the statement (i.e. "forgotting Needed ocked") is slightly too unnatural and could be interpreted as a playful existential inquiry, but without context it is difficult to be sure beyond that.
ãã®åçã¯åœ¹ã«ç«ã¡ãŸãããïŒ |
ç«ææ¥ã®3æ¥åŸã¯äœææ¥ã§ãããïŒ | ç«ææ¥ã®3æ¥åŸã¯éææ¥ã§ãã
解æéçšïŒ
1. ç«ææ¥ããæ°ããŠ1æ¥ç®ã¯æ°Žææ¥ã§ãã
2. 2æ¥ç®ã¯æšææ¥ã§ãã
3. 3æ¥ç®ã¯éææ¥ã§ãã
ãããã£ãŠãç«ææ¥ã®3æ¥åŸã¯éææ¥ãšãªããŸãã | ç«ææ¥ã®3æ¥åŸã¯éææ¥ã§ãã
解æéçšïŒ
1. ç«ææ¥ããæ°ããŠ1æ¥ç®ã¯æ°Žææ¥ã§ãã
2. 2æ¥ç®ã¯æšææ¥ã§ãã
3. 3æ¥ç®ã¯éææ¥ã§ãã
ãããã£ãŠãç«ææ¥ã®3æ¥åŸã¯éææ¥ãšãªããŸãã | ç«ææ¥ã®3æ¥åŸã¯éææ¥ã§ãã
説æ:
- ç«ææ¥ãèµ·ç¹ãšãããŠããŸãã
- 3æ¥åŸã¯3æ¥åŸã®æ¥ã§ããéææ¥ã«ãªããŸãã
ãã®ããã«åçããããšãã§ããŸã:
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1. ãŸãã5ã4ã§å²ããŸãïŒ \(5 \div 4\)
2. çµæã«13ã足ããŸãïŒ \((5 \div 4) + 13\)
3. ãã®çµæã20åããŸãïŒ \(((5 \div 4) + 13) \times 20\)
4. æåŸã«5ãæžç®ããŸãïŒ \(((5 \div 4) + 13) \times 20 - 5\) | åé¡ã«èšèŒãããèªç¶èšèªã§ã®èª¬æãããšã«ãååæŒç®ã®æ°åŒãšããŠè¡šããšä»¥äžã®ããã«ãªããŸãïŒ
\[
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2. çµæã«13ã足ããŸãïŒ \((5 \div 4) + 13\)
3. ãã®çµæã20åããŸãïŒ \(((5 \div 4) + 13) \times 20\)
4. æåŸã«5ãæžç®ããŸãïŒ \(((5 \div 4) + 13) \times 20 - 5\) |
\[
\left( \left( \frac{5}{4} + 13 \right) \times 20 \right) - 5
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3. 100ãã999ãŸã§ã®æ°åã¯ãåæ°åã2æ¡ã§æ§æãããŸããåèšãããšãåæ°åã®åæ°ã¯999 - 100 + 1 = 899åã§ãããããã£ãŠããããå
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- æåå1: ãã¬ããã
- æåå2: ãããããããã
### 解æ³ã®æé
1. **ããŒãã«äœæ**:
- 2ã€ã®æååã䞊ã¹ãŠã2次å
ã®ããŒãã«ãäœããŸãã
- 1ã€ç®ã®æååã®åæåãš2ã€ç®ã®æååã®åæåã®çµã¿åããã«å¯Ÿå¿ããããŒãã«ã®åã»ã«ããããŸãã
2. **åæå**:
- ããŒãã«ã®å·Šäžé
ïŒ0,0ïŒã®ã»ã«ã¯0ã«åæåããŸãã
3. **åçèšç»æ³ã®é©çš**:
- ããŒãã«ã®åã»ã«ãé çªã«èšç®ããŸããã»ã«(i, j)ã¯ãæåå1ã®æåã®iæåãšæåå2ã®æåã®jæåã§åœ¢æãããå
±ééšåæååã®é·ããè¡šããŸãã
- ã»ã«(i, j)ã®å€ã¯æ¬¡ã®ã«ãŒã«ã«ãã£ãŠæ±ºå®ããŸãïŒ
- æåå1ã®içªç®ã®æåãšæåå2ã®jçªç®ã®æåãåãå Žåãã»ã«(i, j)ã®å€ã¯ã»ã«(i-1, j-1)ã®å€ã«1å ç®ãããŸãã
- æåå1ã®içªç®ã®æåãšæåå2ã®jçªç®ã®æåãç°ãªãå Žåãã»ã«(i, j)ã®å€ã¯ã»ã«(i-1, j)ãšã»ã«(i, j-1)ã®ãã¡å€§ããæ¹ã®å€ãå
¥ããŸãã
### èšç®éçš
æåå1: ãã¬ããã (snukeiji)
æåå2: ãããããããã (insukeinji)
| | ã | ã® | ã | ã | ã |
|-------|---|---|---|---|---|
| ã | 0 | 0 | 0 | 0 | 0 |
| ã | 0 | 0 | 0 | 0 | 0 |
| ã | 0 | 1 | 1 | 1 | 1 |
| ã | 0 | 1 | 1 | 1 | 1 |
| ã | 0 | 1 | 2 | 2 | 2 |
| ã | 0 | 1 | 2 | 3 | 3 |
| ã | 0 | 1 | 2 | 3 | 3 |
| ã | 0 | 2 | 3 | 3 | 4 |
| ã | 0 | 2 | 3 | 3 | 4 |
| ã | 0 | 2 | 3 | 4 | 5 |
| ã | 0 | 2 | 3 | 4 | 5 |
| ã | 0 | 2 | 3 | 4 | 5 |
| ã | 0 | 2 | 3 | 4 | 6 |
### çµæ
æçµçãªããŒãã«ã®å³äžé
ã®ã»ã«ïŒ12,10ïŒã®å€ãã2ã€ã®æååã®é£ç¶ããæé·å
±ééšåæååã®é·ããšãªããŸãããã®å€ã¯6ã§ãã
ãããã£ãŠã2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ãã¯6ã§ãã | ãã®åé¡ã解ãããã«ã LCSïŒLongest Common SubsequenceïŒã®ææ³ãçšããã®ãäžè¬çã§ããLCSã¯ã2ã€ã®æååã®éã§æãé·ãå
±ééšåæååãæ±ããåé¡ã§ãåçèšç»æ³ãçšããŠè§£ãããšãã§ããŸãã
äžããããæååã¯:
- æåå1: ãã¬ããã
- æåå2: ãããããããã
### 解æ³ã®æé
1. **ããŒãã«äœæ**:
- 2ã€ã®æååã䞊ã¹ãŠã2次å
ã®ããŒãã«ãäœããŸãã
- 1ã€ç®ã®æååã®åæåãš2ã€ç®ã®æååã®åæåã®çµã¿åããã«å¯Ÿå¿ããããŒãã«ã®åã»ã«ããããŸãã
2. **åæå**:
- ããŒãã«ã®å·Šäžé
ïŒ0,0ïŒã®ã»ã«ã¯0ã«åæåããŸãã
3. **åçèšç»æ³ã®é©çš**:
- ããŒãã«ã®åã»ã«ãé çªã«èšç®ããŸããã»ã«(i, j)ã¯ãæåå1ã®æåã®iæåãšæåå2ã®æåã®jæåã§åœ¢æãããå
±ééšåæååã®é·ããè¡šããŸãã
- ã»ã«(i, j)ã®å€ã¯æ¬¡ã®ã«ãŒã«ã«ãã£ãŠæ±ºå®ããŸãïŒ
- æåå1ã®içªç®ã®æåãšæåå2ã®jçªç®ã®æåãåãå Žåãã»ã«(i, j)ã®å€ã¯ã»ã«(i-1, j-1)ã®å€ã«1å ç®ãããŸãã
- æåå1ã®içªç®ã®æåãšæåå2ã®jçªç®ã®æåãç°ãªãå Žåãã»ã«(i, j)ã®å€ã¯ã»ã«(i-1, j)ãšã»ã«(i, j-1)ã®ãã¡å€§ããæ¹ã®å€ãå
¥ããŸãã
### èšç®éçš
æåå1: ãã¬ããã (snukeiji)
æåå2: ãããããããã (insukeinji)
| | ã | ã® | ã | ã | ã |
|-------|---|---|---|---|---|
| ã | 0 | 0 | 0 | 0 | 0 |
| ã | 0 | 0 | 0 | 0 | 0 |
| ã | 0 | 1 | 1 | 1 | 1 |
| ã | 0 | 1 | 1 | 1 | 1 |
| ã | 0 | 1 | 2 | 2 | 2 |
| ã | 0 | 1 | 2 | 3 | 3 |
| ã | 0 | 1 | 2 | 3 | 3 |
| ã | 0 | 2 | 3 | 3 | 4 |
| ã | 0 | 2 | 3 | 3 | 4 |
| ã | 0 | 2 | 3 | 4 | 5 |
| ã | 0 | 2 | 3 | 4 | 5 |
| ã | 0 | 2 | 3 | 4 | 5 |
| ã | 0 | 2 | 3 | 4 | 6 |
### çµæ
æçµçãªããŒãã«ã®å³äžé
ã®ã»ã«ïŒ12,10ïŒã®å€ãã2ã€ã®æååã®é£ç¶ããæé·å
±ééšåæååã®é·ããšãªããŸãããã®å€ã¯6ã§ãã
ãããã£ãŠã2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ãã¯6ã§ãã | ãã®åé¡ã¯ã2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããããšãèŠæ±ããŠããŸãããã®åé¡ã解決ããããã«ãåçèšç»æ³ãçšããã®ãå¹æçã§ãã
以äžã«å
·äœçãªæé ãšã³ãŒãã瀺ããŸãã
### æé :
1. **æååã®æ¯èŒ**:
- 2ã€ã®æååãæ¯èŒããããããã®æåã2次å
ã®é
åã«æ ŒçŽããŸãã
- é
åã®åèŠçŽ ã¯ã2ã€ã®æååã®æåã®æåã®æ¯èŒçµæãè¡šããŸãã
2. **åçèšç»æ³ã«ããæ¯èŒ**:
- 2次å
ã®é
å dp ãçšæããŸããåæå€ã¯å
šãŠ0
- 2ã€ã®æååã®åæåãæ¯èŒãããã³ã«ãé
å dp ã®å¯Ÿå¿ããèŠçŽ ã«å€ãæŽæ°ããŸãã
3. **dp ããŒãã«ã®æŽæ°æ¹æ³**:
- æåå1ã® i çªç®ã®æåãšæåå2ã® i çªç®ã®æåãæ¯èŒããŸãã
- ã€ãŸããdp[i][j] ã«æ ŒçŽãããŠããå€ã¯ãæåå1ã® i çªç®ã®æåãšæåå2ã® j çªç®ã®æåã®æ¯èŒçµæã§ãã
- æåãçããå Žåãdp[i][j] 㯠dp[i-1][j-1] + 1 ã«æŽæ°ãããŸãã
- æåãç°ãªãå Žåãdp[i][j] 㯠0 ã«æŽæ°ãããŸãã
4. **æé·å
±ééšåæååã®æ¢çŽ¢**:
- ã«ãŒãã䜿çšããŠããã¹ãŠã®çµã¿åãããæ¯èŒããæé·å
±ééšåæååã®é·ããèŠã€ããŸãã
- dp ããŒãã«ã®åèŠçŽ ã¯ã2ã€ã®æååã®ç°ãªãæåãåºçŸãããŸã§ã®çµã¿åããæ°ãè¡šããŸãã
### ã³ãŒãäŸ:
```python
def longest_common_substring(s1,s2):
n = len(s1)
m = len(s2)
dp = [[0] * (n + 1) for _ in range(n + 1)]
for i in range(1,n + 1):
for j in range(1,m + 1):
if s1[i-1] == s2[j-1]:
dp[i][j] = dp[i-1][j-1] + 1
else:
dp[i][j] = 0
longest_length = 0
max_length = 0
for i in range(1,n + 1):
for |
以äžã®äŸæã¯ãžã§ãŒã¯ïŒç®èïŒãèšã£ãŠããŸããïŒ
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®ããå®éã«éšãéããªããã°åãè²·ããªããŠãæžããšããå¯èœæ§ã«ã€ããŠçåãåããŠããã ãã§ããæèãããå
·äœçã«èª¬æãããã°ãããæ£ç¢ºãªå€æãå¯èœã§ãããçŽæã§ã¯ç®èããžã§ãŒã¯ãšã¯åãåãããŸããã | ãã®äŸæã¯ãžã§ãŒã¯ãç®èã§ã¯ãªããå®éã®ç¶æ³ã®çåãè¡šããŠããããã«èŠããŸããä»æ¥ã®å€©æ°äºå ±ãéšã§ããããšãèæ
®ããå®éã«éšãéããªããã°åãè²·ããªããŠãæžããšããå¯èœæ§ã«ã€ããŠçåãåããŠããã ãã§ããæèãããå
·äœçã«èª¬æãããã°ãããæ£ç¢ºãªå€æãå¯èœã§ãããçŽæã§ã¯ç®èããžã§ãŒã¯ãšã¯åãåãããŸããã | ãã®äŸæã¯ãžã§ãŒã¯ãç®èã§ã¯ãªããåãªãæ°è±¡ã«ã€ããŠã®è³ªåã§ãããã®æã¯äºå ±ãéšãšãªã£ãŠããã®ã«åãæã£ãŠãããã©ããè¿·ã£ãŠããããšãè¡šçŸããŠããŸããç®èããžã§ãŒã¯ã®èŠçŽ ã¯ãããŸããã
user: answered |
以äžã®æã¯ããæ°åŒãèªç¶èšèªã§è¡šãããã®ã§ããå
ã®æ°åŒãååæŒç®ã®æ°åŒãšããŠè¡šããŠãã ããã
5ã4ã§å²ã£ãçµæã«15ã足ããŠã8ãæãããæåŸã«3ã§æžç®ããã | ãã®èªç¶èšèªã§è¡šçŸãããåŒãååæŒç®ã®æ°åŒãšããŠè¡šããšä»¥äžã®ããã«ãªããŸãïŒ
```
(((5 ÷ 4) + 15) à 8) - 3
```
ãã®åŒã段éçã«èšç®ãããšä»¥äžã®ããã«ãªããŸãïŒ
1. 5 ÷ 4 = 1.25
2. 1.25 + 15 = 16.25
3. 16.25 Ã 8 = 130
4. 130 - 3 = 127
æçµçãªçµæã¯127ã§ãã | ãã®èªç¶èšèªã§è¡šçŸãããåŒãååæŒç®ã®æ°åŒãšããŠè¡šããšä»¥äžã®ããã«ãªããŸãïŒ
```
(((5 ÷ 4) + 15) à 8) - 3
```
ãã®åŒã段éçã«èšç®ãããšä»¥äžã®ããã«ãªããŸãïŒ
1. 5 ÷ 4 = 1.25
2. 1.25 + 15 = 16.25
3. 16.25 Ã 8 = 130
4. 130 - 3 = 127
æçµçãªçµæã¯127ã§ãã | åé¡æãæ°åŒãšããŠè¡šããšä»¥äžã®ããã«ãªããŸãïŒ
[(5 ÷ 4 + 15) à 8 - 3] \( \text{ç¥ããã«æžããš:} \( \left( \frac{5}{4} + 15 \right) \times 8 - 3 \) \)
ãã®æ°åŒã¯ååæŒç®ãå«ã¿ãŸãïŒ
1. æŽæ°5ã4ã§å²ã£ãçµæãæ±ããŸãïŒ5 ÷ 4ïŒã
2. ãã®çµæã«15ã足ããŸãïŒ5 ÷ 4 + 15ïŒã
3. ãã®çµæã«8ãæããŸãïŒ5 ÷ 4 + 15 à 8ïŒã
4. æåŸã«ããã®çµæãã3ãæžç®ããŸãïŒ5 ÷ 4 + 15 à 8 - 3ïŒã
ãã£ãŠãæçµçãªçµæã¯ä»¥äžã®éãã§ãïŒ
5 ÷ 4 + 15 à 8 - 3 = 6 + 120 - 9 = 91
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