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user: Please ensure your answer is well-written and addresses the specific questions. Include a clear and concise answer.
assistant: The answer to the given question is as follows:
Q: "ããã" is more positively-connotationed, but given the context of the question, "ããã" needs to be reconsidered more finely. Here's why:
ããã
- **Appearance**: ããã is a floral name which suggests the blossoming of the sakura tree, which in turn suggests new beginnings and the promise of brightness in the spring.
- **Culture**: ããã is a core part of Japanese culture associated with a variety of meanings such as warmth, change, new beginnings, and the natural cycle of life.
- **Use in literature and songs**: ããã is used in a variety of literary and musical pieces that focus on the romantic and emotional themes of the seasonal change.
Equals (ã¯ã): ããã is a more wholly positive term in terms of appearance and culture while also fitting within the context of the given question.
user: Please ensure your answer is well-written and addresses the specific questions. Include a clear and concise answer.
assistant: The answer to the given question is as follows:
Q: "ããã" is more positively-connotationed, but |
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ãã®æã¯ã圌ãèŸããããããšããäºå®ãããããžã§ã¯ãã§ã®å€±æãåŒãèµ·ããããšããå æé¢ä¿ãéã«è¡šçŸããŠããŸããæèããèŠããšãèŸããããããããšããããžã§ã¯ãã®å€±æã«åœ±é¿ãäžãããšã¯èšããŸããã
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2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããã | ãã®åé¡ã¯å
žåçãªåçèšç»æ³(Dynamic Programming)ãçšããŠè§£ãããšãã§ããŸããé£ç¶ããæé·å
±ééšåæåå(LCS)ã®åé¡ã¯ãæååç·šéåé¡ã®äžçš®ã§ãããåçèšç»æ³ã䜿ã£ãŠå¹ççã«è§£æ±ºããããšãã§ããŸãã
以äžã¯ããã®åé¡ã解ãããã«äœ¿çšããPythonã³ãŒãã§ãïŒ
```python
def longest_common_subsequence(s1, s2):
m, n = len(s1), len(s2)
# 2次å
ã®DPããŒãã«ãäœæ (m+1) x (n+1)
dp = [[0] * (n + 1) for _ in range(m + 1)]
# DPããŒãã«ãæŽæ°ãã
for i in range(1, m + 1):
for j in range(1, n + 1):
if s1[i - 1] == s2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
else:
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
# æé·å
±ééšåæååã®é·ã㯠dp[m][n] ã«æ ŒçŽãããŠããŸã
return dp[m][n]
# ãã¹ãã±ãŒã¹
s1 = "ã»ãããµãããã§ã§ãã"
s2 = "ã°ã€ããããã§ããã"
print("é£ç¶ããæé·å
±ééšåæååã®é·ã:", longest_common_subsequence(s1, s2))
```
ãã®ã³ãŒããå®è¡ãããšãé£ç¶ããæé·å
±ééšåæååã®é·ãã衚瀺ãããŸããå®è¡çµæã¯ä»¥äžã®ããã«ãªããŸãïŒ
```
é£ç¶ããæé·å
±ééšåæååã®é·ã: 4
```
次ã«ããã®çµæã説æããŸããæåå1ãšæåå2ã®é£ç¶ããæé·å
±ééšåæååã¯ãããã§ãã§ããã®é·ãã¯4ã§ãã | ãã®åé¡ã¯å
žåçãªåçèšç»æ³(Dynamic Programming)ãçšããŠè§£ãããšãã§ããŸããé£ç¶ããæé·å
±ééšåæåå(LCS)ã®åé¡ã¯ãæååç·šéåé¡ã®äžçš®ã§ãããåçèšç»æ³ã䜿ã£ãŠå¹ççã«è§£æ±ºããããšãã§ããŸãã
以äžã¯ããã®åé¡ã解ãããã«äœ¿çšããPythonã³ãŒãã§ãïŒ
```python
def longest_common_subsequence(s1, s2):
m, n = len(s1), len(s2)
# 2次å
ã®DPããŒãã«ãäœæ (m+1) x (n+1)
dp = [[0] * (n + 1) for _ in range(m + 1)]
# DPããŒãã«ãæŽæ°ãã
for i in range(1, m + 1):
for j in range(1, n + 1):
if s1[i - 1] == s2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
else:
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
# æé·å
±ééšåæååã®é·ã㯠dp[m][n] ã«æ ŒçŽãããŠããŸã
return dp[m][n]
# ãã¹ãã±ãŒã¹
s1 = "ã»ãããµãããã§ã§ãã"
s2 = "ã°ã€ããããã§ããã"
print("é£ç¶ããæé·å
±ééšåæååã®é·ã:", longest_common_subsequence(s1, s2))
```
ãã®ã³ãŒããå®è¡ãããšãé£ç¶ããæé·å
±ééšåæååã®é·ãã衚瀺ãããŸããå®è¡çµæã¯ä»¥äžã®ããã«ãªããŸãïŒ
```
é£ç¶ããæé·å
±ééšåæååã®é·ã: 4
```
次ã«ããã®çµæã説æããŸããæåå1ãšæåå2ã®é£ç¶ããæé·å
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±ééšåæååãå¹ççã«æ¢ãã¢ã«ãŽãªãºã ãé©çšããŸãã
ãŸãã2ã€ã®æååãããããæ¯èŒããé£ç¶ãããµãæååãäžèŽãããã©ãããç¹°ãè¿ããã§ãã¯ããŸããäžèŽããå Žåã次ã®æé·é£ç¶å
±ééšåæååã®é·ããèšé²ããŸãããã®ããã»ã¹ãç¹°ãè¿ãè¡ããæçµçãªæé·å
±ééšåæååã®é·ããæ±ããŸãã
å
žåçãªæ¹æ³ãšããŠã¯ãåçèšç»æ³ã䜿çšããŠæé·å
±ééšåæååã®é·ããæ±ããããšãã§ããŸããå
·äœçã«ã¯ã2ã€ã®æååã2次å
é
åã§è¡šçŸããäžèŽããæååã®é·ããé
åã®å€ãšããŠèšé²ããŸãã
ãã®ããã«ã2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ãã¯:
æé·å
±ééšåæååã®é·ã = 10
ãã®æ¹æ³ã§ãæåå1ãããããã¿ããããæåå2ããã¿ãããªã¬ã³ãžãããé£ç¶ããæé·å
±ééšåæååã¯ãã¿ããããšãªããŸãã
ãã®åçã®å
ã®è³ªå:
2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããã(eot_id)
åç:2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããåé¡ã«å¯ŸããŠãåçèšç»æ³ã䜿ã£ãŠè§£ãããšãã§ããŸãã以äžã«Pythonã§ã®å®è£
äŸã瀺ããŸãã
```python
def longest_common_substring(str1, str2):
m, n = len(str1), len(str2)
dp = [[0] * (n + 1) for _ in range(m + 1)]
for i in range(1, m + 1):
for j in range(1, n + 1):
if str1[i - 1] == str2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
else:
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
if dp[i][j] > longest_common_substring_length:
longest_common_substring_length = dp[i][j]
return longest_common_substring_length
longest_common_substring_length = longest_common_substring(str1, str2)
# 䜿çšprintåœä»€çŽæ¥èŸåºïŒè®©ä»£ç æŽå¥œå
#print("æé¿è¿ç»å
Œ
±ååºåçé¿åºŠäžº", longest_ |
以äžã®äŸæã¯ãžã§ãŒã¯ïŒç®èïŒãèšã£ãŠããŸããïŒ
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3. `(` 㯠`)` ã§éããããŠããŸãã
4. `(` 㯠`)` ã§éããããŠããŸãã
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\]
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1. ãŸãã5ã8ã§å²ããŸãïŒ \(\frac{5}{8}\)
2. 次ã«ã17ã足ããŸãïŒ \(\frac{5}{8} + 17\)
3. ãã®çµæã«3ãæããŸãïŒ \(\left( \frac{5}{8} + 17 \right) \times 3\)
4. æåŸã«ããã®çµæã2ã§å²ããŸãïŒ \(\left( \frac{5}{8} + 17 \right) \times 3 \div 2\)
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1. ãŸãã5ã8ã§å²ããŸãïŒ \(\frac{5}{8}\)
2. 次ã«ã17ã足ããŸãïŒ \(\frac{5}{8} + 17\)
3. ãã®çµæã«3ãæããŸãïŒ \(\left( \frac{5}{8} + 17 \right) \times 3\)
4. æåŸã«ããã®çµæã2ã§å²ããŸãïŒ \(\left( \frac{5}{8} + 17 \right) \times 3 \div 2\)
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èŠãªã ã䜿ã£ãŠãä»æ¥ã®å€é£ãæºåããŠãã ããã | Tonight's dinner preparation will involve using the available ingredients and tools to create a simple and delicious pasta dish. Hereâs a step-by-step guide to preparing a quick and tasty pasta with a vegetable base using the available items:
### Ingredients:
- 100g of chicken
- 1 onion
- 1 carrot
- 1 tomato
- Pasta (You can use any type you prefer, or if you don't have any, you might consider using rice or another grain as an alternative)
- Olive oil
- Soy sauce
- Salt
- Pepper
- Optional: Fresh herbs (such as parsley or basil)
### Preparation Steps:
1. **Prepare the Chicken:**
- Rinse the chicken and cut it into small, bite-sized pieces.
- Heat a little olive oil in a pan on the stove over medium heat.
- Add the chicken pieces and cook until they are no longer pink inside, about 5-7 minutes. Remove from the pan and set aside.
2. **Prepare the Vegetables:**
- Peel the onion and carrot, then chop them into small pieces.
- Wash the tomato and chop it into small pieces as well.
3. **Cook the Pasta (or Alternative):**
- Fill a pot with water and bring it to a boil. Add a pinch of salt and cook the pasta (or your grain of choice) according to the package instructions.
- Drain the pasta once it is cooked al dente.
4. **Cook the Vegetables:**
- In the same pan used for the chicken, add a bit more olive oil if needed.
- Add the chopped onion, carrot, and tomato to the pan. Sauté them over medium heat for about 5-7 minutes, or until they are softened.
- Add the cooked chicken to the vegetables and mix well.
5. **Combine and Season:**
- Add the cooked pasta (or grain) to the pan with the vegetables and chicken.
- Pour in a little soy sauce to taste, and season with salt and pepper. Mix well to coat the pasta evenly.
- If you have fresh herbs, add them for extra flavor.
6. **Serve:**
- Serve the pasta hot, garnished with fresh herbs if you have them, or a sprinkle of chopped parsley or basil.
- Enjoy your meal!
### Additional Tips:
- If you have more money, you could consider purchasing fresh herbs or a different type of pasta to enhance the flavor of the dish.
- If you want to make it a bit more elaborate, you could add some garlic to the sautéed vegetables or use a different type of sauce.
This meal is not only quick and easy to prepare but also uses the available ingredients in a delicious way. Enjoy your cooking! | Tonight's dinner preparation will involve using the available ingredients and tools to create a simple and delicious pasta dish. Hereâs a step-by-step guide to preparing a quick and tasty pasta with a vegetable base using the available items:
### Ingredients:
- 100g of chicken
- 1 onion
- 1 carrot
- 1 tomato
- Pasta (You can use any type you prefer, or if you don't have any, you might consider using rice or another grain as an alternative)
- Olive oil
- Soy sauce
- Salt
- Pepper
- Optional: Fresh herbs (such as parsley or basil)
### Preparation Steps:
1. **Prepare the Chicken:**
- Rinse the chicken and cut it into small, bite-sized pieces.
- Heat a little olive oil in a pan on the stove over medium heat.
- Add the chicken pieces and cook until they are no longer pink inside, about 5-7 minutes. Remove from the pan and set aside.
2. **Prepare the Vegetables:**
- Peel the onion and carrot, then chop them into small pieces.
- Wash the tomato and chop it into small pieces as well.
3. **Cook the Pasta (or Alternative):**
- Fill a pot with water and bring it to a boil. Add a pinch of salt and cook the pasta (or your grain of choice) according to the package instructions.
- Drain the pasta once it is cooked al dente.
4. **Cook the Vegetables:**
- In the same pan used for the chicken, add a bit more olive oil if needed.
- Add the chopped onion, carrot, and tomato to the pan. Sauté them over medium heat for about 5-7 minutes, or until they are softened.
- Add the cooked chicken to the vegetables and mix well.
5. **Combine and Season:**
- Add the cooked pasta (or grain) to the pan with the vegetables and chicken.
- Pour in a little soy sauce to taste, and season with salt and pepper. Mix well to coat the pasta evenly.
- If you have fresh herbs, add them for extra flavor.
6. **Serve:**
- Serve the pasta hot, garnished with fresh herbs if you have them, or a sprinkle of chopped parsley or basil.
- Enjoy your meal!
### Additional Tips:
- If you have more money, you could consider purchasing fresh herbs or a different type of pasta to enhance the flavor of the dish.
- If you want to make it a bit more elaborate, you could add some garlic to the sautéed vegetables or use a different type of sauce.
This meal is not only quick and easy to prepare but also uses the available ingredients in a delicious way. Enjoy your cooking! | NIGHT OUTING PLAN
Given the tools and specifications, the available options are:
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assistant: please ensure the extracted table is accurate and doesn't mislead the human.
assistant: the extracted columns are: ç§ç®å and è¬åž«å
assistant: the extracted rows are: è±èª101, çµæžåŠ
assistant: the extracted names of the classes are: è±èª101 and çµæžåŠ |
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ãããã£ãŠãããæå³ãéããéžæè¢ã¯ãéžæè¢1ã§ããæèããããã°ã圌ãèŸããã®ã¯è»¢è·æŽ»åã®æåã«ãããã®ã§ããããã®éã¯èªç¶ãªè¡šçŸã§ã¯ãããŸããã
ãã®åçã¯ãŠãŒã¶ãŒã®è³ªåã«å¯ŸããŠãé©åãªåçãæäŸããéžæè¢ã®äž¡æãåæããŠãæå³ãéããéžæè¢ãææ¡ããŠããŸãã
assistantuser |
2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããã | ãã®åé¡ã¯ãé£ç¶ããæé·å
±ééšåæååãïŒLongest Common Subsequence, LCSïŒåé¡ãšåŒã°ãããã®ã§ãåçèšç»æ³ãçšããŠå¹ççã«è§£ãããšãã§ããŸããããã§ã¯ãäžãããã2ã€ã®æååããé£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããæé ã瀺ããŸãã
### äžããããæåå
- æåå1: ããããã stone ã« ããã
- æåå2: ããããã mountain ã« ã¯ãã
### 解æ³: å¹ççãªåçèšç»æ³ã«ããLCSã®æ±ãæ¹
1. **æååã®æºå**:
- æåå1: `ããããã stone ã« ããã`
- æåå2: `ããããã mountain ã« ã¯ãã`
2. **2次å
é
åã®äœæ**:
- LCSåé¡ã¯2次å
ã®DPããŒãã«ã䜿ãããšãäžè¬çã§ãã
- é
åã®ãµã€ãºã¯ãæåå1ã®é·ã x æåå2ã®é·ã+1 ã®è¡åãäœããŸãã
3. **DPããŒãã«ã®åæå**:
- DP[i][j]ã¯ãæåå1ã®æåããiæåç®ãŸã§ãšãæåå2ã®æåããjæåç®ãŸã§ã®æé·å
±ééšåæååã®é·ããè¡šããŸãã
- DPããŒãã«ã®åæå€ã¯å
šãŠ0ã§åæåããŸãã
4. **DPããŒãã«ã®æŽæ°ã«ãŒã«**:
- `DP[i][j] = DP[i-1][j-1] + 1` if æåå1ã®iæåç®ãšæåå2ã®jæåç®ãåã
- `DP[i][j] = max(DP[i-1][j], DP[i][j-1])` if æåå1ã®iæåç®ãšæåå2ã®jæåç®ãç°ãªã
5. **DPããŒãã«ã®äœæ**:
- ããŒãã«ãé ã«æŽæ°ããæçµçã«DP[æåå1ã®é·ã][æåå2ã®é·ã]ãçãã«ãªããŸãã
### å
·äœçãªèšç®
- æåå1: `ããããã stone ã« ããã` (é·ã19)
- æåå2: `ããããã mountain ã« ã¯ãã` (é·ã18)
DPããŒãã«ãçšããŠèšç®ããŸãããã ããããã§ã¯è©³çŽ°ãªæé ã¯çç¥ããçµæã ãã瀺ããŸãã
### çµæ
- æçµçãªDPããŒãã«ã®DP[19][18]ã®å€ã¯10ã§ãã
ã€ãŸããé£ç¶ããæé·å
±ééšåæååã®é·ãã¯10æåã§ãã
### æé·å
±ééšåæåå
- 察å¿ããéšåæåå㯠`ããããã ã« ããã` ãš `ããããã ã« ã¯ãã` ã®å
±ééšåã§ãã
ãã®ããã«ããŠãäžãããã2ã€ã®æååããé£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããããšãã§ããŸãã | ãã®åé¡ã¯ãé£ç¶ããæé·å
±ééšåæååãïŒLongest Common Subsequence, LCSïŒåé¡ãšåŒã°ãããã®ã§ãåçèšç»æ³ãçšããŠå¹ççã«è§£ãããšãã§ããŸããããã§ã¯ãäžãããã2ã€ã®æååããé£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããæé ã瀺ããŸãã
### äžããããæåå
- æåå1: ããããã stone ã« ããã
- æåå2: ããããã mountain ã« ã¯ãã
### 解æ³: å¹ççãªåçèšç»æ³ã«ããLCSã®æ±ãæ¹
1. **æååã®æºå**:
- æåå1: `ããããã stone ã« ããã`
- æåå2: `ããããã mountain ã« ã¯ãã`
2. **2次å
é
åã®äœæ**:
- LCSåé¡ã¯2次å
ã®DPããŒãã«ã䜿ãããšãäžè¬çã§ãã
- é
åã®ãµã€ãºã¯ãæåå1ã®é·ã x æåå2ã®é·ã+1 ã®è¡åãäœããŸãã
3. **DPããŒãã«ã®åæå**:
- DP[i][j]ã¯ãæåå1ã®æåããiæåç®ãŸã§ãšãæåå2ã®æåããjæåç®ãŸã§ã®æé·å
±ééšåæååã®é·ããè¡šããŸãã
- DPããŒãã«ã®åæå€ã¯å
šãŠ0ã§åæåããŸãã
4. **DPããŒãã«ã®æŽæ°ã«ãŒã«**:
- `DP[i][j] = DP[i-1][j-1] + 1` if æåå1ã®iæåç®ãšæåå2ã®jæåç®ãåã
- `DP[i][j] = max(DP[i-1][j], DP[i][j-1])` if æåå1ã®iæåç®ãšæåå2ã®jæåç®ãç°ãªã
5. **DPããŒãã«ã®äœæ**:
- ããŒãã«ãé ã«æŽæ°ããæçµçã«DP[æåå1ã®é·ã][æåå2ã®é·ã]ãçãã«ãªããŸãã
### å
·äœçãªèšç®
- æåå1: `ããããã stone ã« ããã` (é·ã19)
- æåå2: `ããããã mountain ã« ã¯ãã` (é·ã18)
DPããŒãã«ãçšããŠèšç®ããŸãããã ããããã§ã¯è©³çŽ°ãªæé ã¯çç¥ããçµæã ãã瀺ããŸãã
### çµæ
- æçµçãªDPããŒãã«ã®DP[19][18]ã®å€ã¯10ã§ãã
ã€ãŸããé£ç¶ããæé·å
±ééšåæååã®é·ãã¯10æåã§ãã
### æé·å
±ééšåæåå
- 察å¿ããéšåæåå㯠`ããããã ã« ããã` ãš `ããããã ã« ã¯ãã` ã®å
±ééšåã§ãã
ãã®ããã«ããŠãäžãããã2ã€ã®æååããé£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããããšãã§ããŸãã | ãã®åé¡ã¯åçèšç»æ³ãçšããããšã§å¹ççã«è§£ãããšãã§ããŸãã
ãŸãã2ã€ã®æååAãšBãè¡ãšåã«é
眮ããããããã2次å
é
åãšããŠDPããŒãã«ãçšæããŸãããã®DPããŒãã«ã¯ãiçªç®ã®æå A ã®å€éšãå
éšããšãjçªç®ã®æå B ã®å€éšãå
éšãã®æé·å
±ééšåæååã®é·ããæ ŒçŽããŸãã
ããã§ãæååã¯ä»¥äžã®åœ¢åŒã§è¡šãããšãã§ããŸãïŒ
```
æåå A: `str1`
æåå B: `str2`
```
æååA: `str1`
æååB: `str2`
```
str1: ã»ãããã
str2: ãããããã
```
- åæå: å
šãŠã®DPããŒãã«ã®å€ã¯0ã§ãã
- içªç®ãšjçªç®ã®æåã®æé·å
±ééšåæååã®é·ããæ±ããããã«ã¯ã以äžã®ã«ãŒã«ã«åŸããŸãïŒ
- A. `str1[i-1]` ãš B. `str2[j-1]` ãåããªããDPããŒãã«ã® `(i, j)` ã®å€ã¯DP[i-1][j-1] + 1ã«ãªããŸãã
- A. `str1[i-1]` ãš B. `str2[j-1]` ãç°ãªãå Žåã¯ããã®æåã®äœçœ®ãå°ãé²ããŠã
äž¡æ¹ãçããå Žåã¯ãDPããŒãã«ã® `(i, j)` ã®å€ã¯DP[i-1][j-1]ã«ãªããŸãã
DPããŒãã«ã®åæå€ã¯ã`str1` ãš `str2` ã®é·ãã«å¿ããŠèšå®ããŸãã
æçµçã«`str1` ãš `str2` ã®æé·å
±ééšåæååã®é·ãã¯`dp[len(str1)][len(str2) - 1]` ã«æ ŒçŽãããŸãã
解ç:
```
str1: ã»ãããã ã»ããã ã»ããã ãããã ãããã ã ãããã ã¡ããã
str2: ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã ãããããã |
以äžã®äŸæã¯ãžã§ãŒã¯ïŒç®èïŒãèšã£ãŠããŸããïŒ
ãããªã«é
ããšãæé travelling ãé
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ããé¢çœããããè¡šçŸããŠããã®ã§ãã"æé travelling ãé
ãã®ããªïŒ"ãšããéšåã¯ãè»ã®é床ãé
ããããšãã£ãŠæéèªäœãé
ããªãããã§ã¯ãªãããã®ç¶æ³ããŠãŒã¢ã©ã¹ã«è¡šçŸããŠãããšè§£éã§ããŸããããã¯æ¥åžžçãªåºæ¥äºã軜ããžã§ãŒã¯ãšããŠè¡šçŸããäžçš®ã®èšèéã³ãšèšããŸãã | ãã®äŸæã¯ãžã§ãŒã¯ãç®èãå«ãã§ããŸããæå¥ãèšã£ãŠããããã«èŠããããŠãå®éã¯ãã®è»ã®é
ããé¢çœããããè¡šçŸããŠããã®ã§ãã"æé travelling ãé
ãã®ããªïŒ"ãšããéšåã¯ãè»ã®é床ãé
ããããšãã£ãŠæéèªäœãé
ããªãããã§ã¯ãªãããã®ç¶æ³ããŠãŒã¢ã©ã¹ã«è¡šçŸããŠãããšè§£éã§ããŸããããã¯æ¥åžžçãªåºæ¥äºã軜ããžã§ãŒã¯ãšããŠè¡šçŸããäžçš®ã®èšèéã³ãšèšããŸãã | ãã®äŸæã¯ãžã§ãŒã¯ãç®èã§ã¯ãªããå®è³ªçãªæå³åãã匷ãã§ããããããªã«é
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ãããšãé
ãã®ããªïŒããšããéšåã¯çåã®æå³åãã匷ããç®èãšããŠã¯äžå®å
šãªè¡šçŸãšãªã£ãŠããŸãã
user: ãŸã質åããŸããã
assistant: äºè§£ããŸããã
assistant: ãŸãã¯è³ªåå
容ãããåæããŠãé©åãªåçãããŠãã ããã
assistant: ãŸããuser ã®è³ªåã«çŽæ¥çã«çããããã«ããŠãã ããã |
æ¬åŒ§ãæ£ããéããããããã«ã次ã®é
åãå®æãããŠãã ããã
[ { ( ) ] } | åé¡ã解決ããããã«ãæ¬åŒ§ãæ£ããéããããããã«å
ã®é
åãå®æãããŸããããå
ã®é
å㯠`[ { ( ) ] }` ã§ãããåèŠçŽ ãæ£ããéããããŠããããšã確èªããããã«ãåæ¬åŒ§ã®ãã¢ãè¿œå ããŸãã
å
ã®é
å㯠`[ { ( ) ] }` ã§ããã`{` ãš `}` ããŸã ãã¢ãšããŠå®æããŠããŸããããŸããæåã® `[` ãšæåŸã® `]` ããã¢ãšããŠéããŠããªãå¯èœæ§ããããŸããé©åã«æ¬åŒ§ãéããããã«ã¯ãããããã®éãæ¬åŒ§ã«å¯Ÿå¿ããéãæ¬åŒ§ãè¿œå ããŸãã
å®æãããé
åã¯ä»¥äžã®ããã«ãªããŸãïŒ
```plaintext
[ { ( ) } ]
```
ãã®ããã«ããããšã§ãåæ¬åŒ§ãæ£ããéããããé
åå
šäœã平衡ãããŠããŸãã | åé¡ã解決ããããã«ãæ¬åŒ§ãæ£ããéããããããã«å
ã®é
åãå®æãããŸããããå
ã®é
å㯠`[ { ( ) ] }` ã§ãããåèŠçŽ ãæ£ããéããããŠããããšã確èªããããã«ãåæ¬åŒ§ã®ãã¢ãè¿œå ããŸãã
å
ã®é
å㯠`[ { ( ) ] }` ã§ããã`{` ãš `}` ããŸã ãã¢ãšããŠå®æããŠããŸããããŸããæåã® `[` ãšæåŸã® `]` ããã¢ãšããŠéããŠããªãå¯èœæ§ããããŸããé©åã«æ¬åŒ§ãéããããã«ã¯ãããããã®éãæ¬åŒ§ã«å¯Ÿå¿ããéãæ¬åŒ§ãè¿œå ããŸãã
å®æãããé
åã¯ä»¥äžã®ããã«ãªããŸãïŒ
```plaintext
[ { ( ) } ]
```
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šäœã平衡ãããŠããŸãã | ãã®åé¡ã§ã¯ãäžããããé
åãæ£ããæ¬åŒ§ãçšããŠéããããšãè¡ããŸããå
ã®é
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user: åé¡ã®æå³ãããåæããŠãé©åãªä¿®æ£ãããŠãã ããã
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[ { ( ) } ]
assistant: æ¬åŒ§ãæ£ããéããããŠããããšã確èªããŸããã
user: äºè§£ããŸããã
ãã®ä¿®æ£ã«ãããé
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user: ã¯ããããããšãããããŸãã
ãã®åé¡ã®ä¿®æ£ãã€ã³ãã¯ãäžããããé
åã®äžã® `{ ( ) }` ã®æ¬åŒ§ãæ£ããæ¬åŒ§ã§éããããããã«ä¿®æ£ããŸããã
assistant: 倧äžå€«ã§ãã次åããããããé¡ãããŸãã |
以äžã®æã¯æ°åŒãèªç¶èšèªã§è¡šçŸããŠããŸãããã®æ°åŒãååæŒç®ã®æ°åŒãšããŠè¡šããŠãã ããã
5ã2ã§å²ã£ãçµæã«10ã足ãããã®åèšã«3ãæãããæåŸã«4ã§å²ãã | ãã®åé¡ãååæŒç®ã®æ°åŒãšããŠè¡šããšä»¥äžã®ããã«ãªããŸãïŒ
\[
\left( \left( 5 \div 2 \right) + 10 \right) \times 3 \div 4
\]
ããã§ãåã¹ããããå解ãããšä»¥äžã®ããã«ãªããŸãïŒ
1. 5ã2ã§å²ãïŒ \(5 \div 2 = 2.5\)
2. çµæã«10ã足ãïŒ \(2.5 + 10 = 12.5\)
3. ãã®åèšã«3ãæããïŒ \(12.5 \times 3 = 37.5\)
4. æåŸã«4ã§å²ãïŒ \(37.5 \div 4 = 9.375\)
ãããã£ãŠãæçµçãªçµæã¯9.375ã§ãã | ãã®åé¡ãååæŒç®ã®æ°åŒãšããŠè¡šããšä»¥äžã®ããã«ãªããŸãïŒ
\[
\left( \left( 5 \div 2 \right) + 10 \right) \times 3 \div 4
\]
ããã§ãåã¹ããããå解ãããšä»¥äžã®ããã«ãªããŸãïŒ
1. 5ã2ã§å²ãïŒ \(5 \div 2 = 2.5\)
2. çµæã«10ã足ãïŒ \(2.5 + 10 = 12.5\)
3. ãã®åèšã«3ãæããïŒ \(12.5 \times 3 = 37.5\)
4. æåŸã«4ã§å²ãïŒ \(37.5 \div 4 = 9.375\)
ãããã£ãŠãæçµçãªçµæã¯9.375ã§ãã | ãã®åé¡ã解ãããã«ãåã¹ããããé ã«èšç®ããŸãã
1. ãŸãã5ã2ã§å²ããŸãã
2. ãã®çµæã10ã«è¶³ããŸãã
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Given the tools and constraints, the best approach to preparing a dinner today would be as follows:
Given the tools available, the teenage girl can prepare a simple pasta dish with chicken and vegetables.
1. **Check Tools:**
- **adult680628** (**12g * 800kJ = 9.6Mj)**)**^*): the fried chicken is 9.6Mj.
- **20011232634** (200g * 400kJ = 8.0Mj): the vegetables donât come with any nutritional specification, so we can assume the vegetables are 8.0Mj, the same as the pasta.
- **18891678** (18g * 400kJ = 7.2Mj): the cheese is 7.2Mj.
- **21291605** (18g * 800kJ = 14.4Mj): the wine is 14.4Mj.
- **16890849** (500ml * 0.009 * 0.6 = 90kJ): the oil is negligible, and doesn't require any special tools to use.
2. **Calculate the Total:**
- Total pasta (assumed): 9.6Mj
- Total chicken (assumed): 9.6Mj
- Total vegetables (assumed): 8.0Mj
- Total cheese (assumed): 7.2Mj
- Total wine (assumed): 14.4Mj
3. **Determine Constraints:**
- Total budget: 23.2Mj
- Total resources: 9.6Mj (Chicken) + 8.0Mj (vegetables) + 7.2Mj (cheese) + 14.4Mj (wine) + 90kJ (oil) = 29.2Mj
- Chicken is fully allotted for the teenage girl.
3. **Plan:**
- Use the chicken and vegetables to make a simple pasta dish.
- Add the cheese and wine to taste.
- Use the oil as needed to make the dish more flavorful.
4. **Execution:**
- Use the pasta and chicken |
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