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Given the limited resources, a simple yet delicious dinner plan using the available ingredients in the freezer and pantry can be crafted. Here's a straightforward meal plan:
1. **Preparation of Frozen Dumplings**
- **Ingredients**: å·åé€å Ã10å (10䞪å·å»é¥ºå)
- **Steps**:
1. Remove the frozen dumplings from the freezer.
2. Place the dumplings in a microwave-safe dish.
3. Cover the dish with a damp paper towel or a lid to prevent the top of the dumplings from drying out.
4. Microwave the dumplings for 2-3 minutes, or until they are heated through.
5. Alternatively, you can use the å·åé€å with the çµåã¬ã³ãž (electronic oven). Place the dumplings directly on a microwave-safe plate, cover with a damp paper towel, and microwave for 3-4 minutes, or until they are heated through.
6. Season with å¡© (salt), è¡æ€ (pepper), and or use a small amount of the available 調å³æ (seasonings) like é
±æ²¹ (soy sauce) to taste.
2. **Side Dishes**
- Since there are no fresh vegetables available, you can prepare a simple side dish using the available seasonings.
- **Ingredients**: å·åé€å (Frozen dumplings) (if needed, you can add more from the freezer)
- **Steps**:
1. If you choose to add more dumplings, repeat the microwaving process as described above.
2. While the dumplings are heating up, you can make a simple soy sauce and vinegar dressing to pour over the dumplings.
3. Mix equal parts of é
±æ²¹ (soy sauce) and é (vinegar) in a small bowl to create a light dressing.
4. Once the dumplings are ready, pour the dressing over them for added flavor.
3. **Conclusion**
- This meal is quick, easy, and utilizes the available resources effectively. The å·åé€å (frozen dumplings) are a convenient and delicious choice for a quick dinner. Enjoy your meal!
This meal plan ensures that you make the most of the available ingredients and resources, providing a satisfying and flavorful dinner. |
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äŸã§ãïŒ
```python
def longest_common_subsequence(str1, str2):
m = len(str1)
n = len(str2)
# ããŒãã«ãåæå
dp = [[0] * (n + 1) for _ in range(m + 1)]
# ããŒãã«ãæŽæ°
for i in range(1, m + 1):
for j in range(1, n + 1):
if str1[i - 1] == str2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
else:
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
# æé·å
±ééšåæååã®é·ããè¿ã
return dp[m][n]
# ã€ã³ãããæåå
str1 = "ããããããã"
str2 = "ããããããã"
# åŠç
result = longest_common_subsequence(str1, str2)
print(f"é£ç¶ããæé·å
±ééšåæååã®é·ãã¯: {result}")
```
ãã®ã³ãŒãã¯ä»¥äžã®æé ã§åäœããŸãïŒ
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±ééšåæååã®é·ããè¡šããŸãã
2. `dp`ããŒãã«ãæŽæ°ããŸããæåãäžèŽããå Žåã¯ãå·Šäžã«ããå€ã«1ãå ããŸããäžèŽããªãå Žåã¯ãå·Šãšäžã®å€ã®å€§ããæ¹ãæ¡çšããŸãã
3. æçµçãª`dp`ããŒãã«ã®å³äžã®å€ãæ±ããçãã§ãã
å®è¡çµæã¯æ¬¡ã®ããã«ãªããŸãïŒ
```
é£ç¶ããæé·å
±ééšåæååã®é·ãã¯: 5
```
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2. `{` 㯠`}` ã§éããããŸãã
3. `(` 㯠`)` ã§éããããŸãã
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\[
\left( \left( \frac{5}{4} \right) + 25 \right) \times 13 \div 7
\]
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