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žåçãªåçèšç»æ³ïŒDynamic Programming, DPïŒã®åé¡ã«è©²åœããŸãã以äžã«ããã®è§£æ³ã®éçšãšçµæã説æããŸãã
### 1. åé¡ã®å®çŸ©
- æåå1: ããã°ããã (kanbarinjo)
- æåå2: ããããã±ã (ringonpaku)
### 2. å¹ççãªè§£æ³: åšæè§åïŒDynamic Programming, DPïŒ
- DPããŒãã«ãçšããŠè§£ããŸãã
- DPããŒãã«ã®åèŠçŽ `dp[i][j]` ã¯ãæåå1ã®æåã® `i` æåãšæåå2ã®æåã® `j` æåã®æé·å
±ééšåæååã®é·ããè¡šããŸãã
### 3. DPããŒãã«ã®åæå
- `dp` ããŒãã«ã®åæå€ã¯å
šãŠ 0 ã«ããŸãã
- `dp[0][0]` 㯠0 ã«ããŸãïŒç©ºæååã®æé·å
±ééšå㯠0ïŒã
### 4. DPããŒãã«ã®æŽæ°ã«ãŒã«
- `dp[i][j]` ã¯ä»¥äžã®ã«ãŒã«ã§æŽæ°ãããŸãïŒ
- æåå1ã® `i-1` çªç®ã®æåãšæåå2ã® `j-1` çªç®ã®æåãäžèŽããå ŽåïŒ
- `dp[i][j] = dp[i-1][j-1] + 1`
- äžèŽããªãå ŽåïŒ
- `dp[i][j] = max(dp[i-1][j], dp[i][j-1])`
### 5. DPããŒãã«ã®æ§ç¯
- æåå1ãšæåå2ãé次æ¯èŒããDPããŒãã«ãæŽæ°ããŸãã
### 6. 解ã®ååŸ
- æçµç㪠`dp` ããŒãã«ã®å³äžã®èŠçŽ (`dp[m][n]`) ãçããšãªããŸãã
### 7. äŸã®å
·äœçãªèšç®
- æåå1: ããã°ããã (kanbarinjo)
- æåå2: ããããã±ã (ringonpaku)
| | 0 | ã | ã | ã | ã | ã± | ã |
|---|---|---|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| ã | 0 | 0 | 1 | 1 | 1 | 1 | 1 |
| ã° | 0 | 0 | 1 | 1 | 1 | 1 | 1 |
| ã | 0 | 1 | 1 | 1 | 1 | 1 | 1 |
| ã | 0 | 1 | 2 | 2 | 2 | 2 | 2 |
| ã | 0 | 1 | 2 | 3 | 3 | 3 | 3 |
| ã | 0 | 1 | 2 | 3 | 3 | 3 | 3 |
| ã | 0 | 1 | 2 | 3 | 3 | 3 | 3 |
| ã« | 0 | 1 | 2 | 3 | 4 | 4 | 4 |
| ã | 0 | 1 | 2 | 3 | 4 | 5 | 5 |
| ã± | 0 | 1 | 2 | 3 | 4 | 5 | 5 |
| ã | 0 | 1 | 2 | 3 | 4 | 5 | 5 |
### 8. çµæ
- æçµç㪠`dp` ããŒãã«ã®å³äžã®èŠçŽ 㯠5 ã§ãã
### 9. çã
- 2ã€ã®æåå `ããã°ããã` ãš `ããããã±ã` ã®é£ç¶ããæé·å
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解æéçšïŒ
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2. æ°Žææ¥ããæ°ããŠ1æ¥åŸã¯æšææ¥ã
3. æšææ¥ããæ°ããŠ1æ¥åŸã¯éææ¥ã
4. éææ¥ããæ°ããŠ1æ¥åŸã¯åææ¥ã
5. åææ¥ããæ°ããŠ1æ¥åŸã¯æ¥ææ¥ã
6. æ¥ææ¥ããæ°ããŠ1æ¥åŸã¯æææ¥ã
7. æææ¥ããæ°ããŠ1æ¥åŸã¯ç«ææ¥ïŒ1é±éç®ïŒã
8. ç«ææ¥ããæ°ããŠ1æ¥åŸã¯æ°Žææ¥ïŒ2é±éç®ïŒã
9. æ°Žææ¥ããæ°ããŠ1æ¥åŸã¯æšææ¥ïŒ3é±éç®ïŒã
10. æšææ¥ããæ°ããŠ1æ¥åŸã¯éææ¥ïŒ4é±éç®ïŒã
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- ãªãŒãã³ãã¬ãŒã¹ `{` ã«å¯Ÿå¿ããã¯ããŒãºãã¬ãŒã¹ `}` ãååšããŸãã
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以äžã®æã¯ããæ°åŒãèªç¶èšèªã§è¡šãããã®ã§ããå
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\[
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\]
ãã®åŒã®èšç®æé ã¯ä»¥äžã®éãã§ãïŒ
1. \(5\) ã \(2\) ã§å²ããŸãïŒ \(5 \div 2 = 2.5\)
2. \(2.5\) ã« \(15\) ã足ããŸãïŒ \(2.5 + 15 = 17.5\)
3. \(17.5\) ã« \(3\) ãæããŸãïŒ \(17.5 \times 3 = 52.5\)
4. æåŸã« \(52.5\) ã \(4\) ã§å²ããŸãïŒ \(52.5 \div 4 = 13.125\)
æçµçãªèšç®çµæ㯠\(13.125\) ãšãªããŸãã |
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- Eyes are blue
- Hair is dark green
- Grounded with wide feet (which could be interpreted as roots or feet touching the ground)
- Enjoy admiring the color of the sky
These characteristics suggest you might be describing a tree. Trees have green leaves (or hair in this case), blue eyes (which could be metaphorical for the sky or the color of the leaves), and they are rooted in the ground, much like the description of having "wide" feet grounded in the earth. Trees also often enjoy the natural world and the beauty of the sky.
So, a fitting answer to this riddle would be: "You are a tree." |
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