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### 解æ³ã®æé
1. **åçèšç»æ³ããŒãã«ã®åæå**:
- 2ã€ã®æåå `s1` ãš `s2` ãæ¯èŒããããã®2次å
é
å `dp` ãçšæããŸãã`dp[i][j]` 㯠`s1` ã®æåãã `i-1` çªç®ã®æååãš `s2` ã®æåãã `j-1` çªç®ã®æååã®æé·å
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3. **DPããŒãã«ã®æŽæ°**:
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4. **æ倧å€ã®æ¢çŽ¢**:
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åã®äžã§æ倧ã®å€ãååŸããŸãããããé£ç¶ããæé·å
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### ãµã³ãã«ã³ãŒã (Python)
```python
def longest_common_substring(s1, s2):
m, n = len(s1), len(s2)
# dp[i][j] 衚瀺 s1[0:i] ãš s2[0:j] ã®æé·å
±ééšåæååã®é·ã
dp = [[0] * (n + 1) for _ in range(m + 1)]
max_len = 0 # æé·å
±ééšåæååã®é·ã
# DPããŒãã«ã®æŽæ°
for i in range(1, m + 1):
for j in range(1, n + 1):
if s1[i - 1] == s2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
max_len = max(max_len, dp[i][j])
else:
dp[i][j] = 0
return max_len
# ãã¹ã
s1 = "ã»ãã®ããã«"
s2 = "ãããããš"
print("é£ç¶ããæé·å
±ééšåæååã®é·ã:", longest_common_substring(s1, s2))
```
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Subsets and Splits