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èŠãªã ã䜿ã£ãŠãä»æ¥ã®å€ãã¯ããæºåããŠãã ããã | NIGHT DINNER PLAN WITH THE AVAILABLE TOOLS AND INGREDIENTS
Given the available ingredients and tools, we can prepare a simple and nutritious dinner consisting of steamed rice, a basic egg dish, and a quick stir-fried vegetable dish using the remaining ingredients. Here's a plan:
1. **Cook the Rice:**
- Use the rice cooker to cook the 500g of rice. Follow the instructions on the rice cooker for the best results.
2. **Prepare a Basic Egg Dish (Soft-Boiled Eggs):**
- Since a proper egg dish requires a pan or a wok, we can prepare soft-boiled eggs as a simple egg dish.
- Place a small pot of water on the stove and bring it to a boil.
- Gently place one egg at a time into the boiling water and let it cook for about 6-7 minutes for a soft-boiled egg.
- Remove the eggs with a slotted spoon, let them cool slightly, and then peel off the shells.
- Slice the eggs and place them in a serving dish with a little bit of salt for seasoning.
3. **Stir-Fried Vegetables (Optional):**
- If you have any vegetables at home, you can quickly stir-fry them. However, with the given ingredients, this might be challenging as we don't have a wok or a pan. We can skip this step if no vegetables are available.
4. **Budget Consideration:**
- With the remaining 800 yen, we can buy some additional vegetables or condiments if needed, but based on the given list, we are unable to purchase any additional items.
This plan will provide a simple, quick, and nutritious dinner using the available ingredients and tools. Enjoy your meal! |
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2ã€ã®æååã§é£ç¶ããæé·å
±ééšåæååã®é·ããæ±ããã | ãã®åé¡ã¯ãé£ç¶ããæé·å
±ééšåæåååé¡ãã«è©²åœããŸãããã®åé¡ã解ãããã«ã¯ãåçèšç»æ³ãçšããããšãäžè¬çã§ãã以äžã«Pythonã§è§£ãæ¹æ³ã瀺ããŸãã
### 解æ³
1. **åçèšç»æ³** ãçšããã
2. 2次å
ã®é
åãäœããåäœçœ®ã§ã®æé·å
±ééšåæååã®é·ããä¿åããã
3. æçµçãªçµæã¯ãé
åã®å³äžã®èŠçŽ ã«æ ŒçŽãããŸãã
### Pythonã³ãŒã
```python
def longest_common_subsequence(s1, s2):
# s1ãšs2ã®é·ããååŸ
m, n = len(s1), len(s2)
# 2次å
ã®é
åãåæå
dp = [[0] * (n + 1) for _ in range(m + 1)]
# dpé
åãæŽæ°ãã
for i in range(1, m + 1):
for j in range(1, n + 1):
if s1[i - 1] == s2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
else:
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
# æçµçãªçµæãè¿ã
return dp[m][n]
# ãã¹ãçšã®æåå
s1 = "ãããã°ãªã§"
s2 = "ã°ãªãªãã§ãã·ã"
# åŠç
result = longest_common_subsequence(s1, s2)
print("é£ç¶ããæé·å
±ééšåæååã®é·ã:", result)
```
### 説æ
1. **dpé
å** ãäœæããŸãã`dp[i][j]` 㯠`s1` ã®å `i` æåãš `s2` ã®å `j` æåã®æé·å
±ééšåæååã®é·ããè¡šããŸãã
2. `s1` ãš `s2` ã®åæåãæ¯èŒããåãæåã§ããã°ãåã®æåã®æ倧é·ãã«1ãå ããå€ã `dp[i][j]` ã«èšå®ããŸãã
3. ç°ãªãæåã§ããã°ãåã®æåã®æ倧é·ãã `dp[i][j]` ã«èšå®ããŸãã
4. æçµçã« `dp[m][n]` ãçãã«ãªããŸãã
### å®è¡çµæ
å®è¡ãããšã以äžã®ãããªçµæãåŸãããŸãïŒ
```
é£ç¶ããæé·å
±ééšåæååã®é·ã: 3
```
ããã¯ã"ã°ãªã§" ãšããæååã2ã€ã®æååã®é£ç¶ããæé·å
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- 次㮠`{` 㯠`}` ã§éããããŠããŸãã
- 次㮠`(` 㯠`)` ã§éããããŠããŸãã
- æåŸã® `(` 㯠`)` ã§éããããŠããŸãã
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以äžã®æã¯ããæ°åŒãèªç¶èšèªã§è¡šãããã®ã§ããå
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\]
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3. ãã®çµæã«15ãæããŸãïŒ\(\left( \frac{5}{8} + 27 \right) \times 15\)
4. æåŸã«ããã®çµæã5ã§å²ããŸãïŒ\(\left( \left( \frac{5}{8} + 27 \right) \times 15 \right) \div 5\)
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