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58af81c202f8a9effe885ebcee356570 | q3. find the value of.
(v) | question | careers360.com | 2020.45 | [
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e27e31ff89819447b1abb1045426b93a | 2. solve :
(a)
(b)
(c)
(d)
(e)
(f)
(g)
( h)
(i) | question | careers360.com | 2020.16 | [
{
"text": "72",
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}
] |
e8bc58815410bc984e5d9b892ead0cce | q : 3 simplify.
(iii) | question | careers360.com | 2020.10 | [
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] |
b070e177444d66e95b13dfecdea93def | 5. in the given figure, the arms of two angles are parallel. if , then find
| question | careers360.com | 2020.10 | [
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"text": "235",
"name": "",
"is_accepted": true
}
] |
0eadf0103f028da7dd3720bc26e7e290 | 1. find:
(i) 0.2 × 6 (ii) 8 × 4.6 (iii) 2.71 × 5 (iv) 20.1 × 4
(v) 0.05 × 7 (vi) 211.02 × 4 (vii) 2 × 0.86 | question | careers360.com | 2020.16 | [
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] |
2ec405911f140b93f78a46cd24e3b4e1 | 3. find the value of.
(iv) | question | careers360.com | 2020.45 | [
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"name": "",
"is_accepted": true
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a8bdf7cba5d4425cc4fed7f6e5df4247 |
5 1 4 7 3 9 8 5 7 2 6 3 1 5 8 6 3 8 5 2 2 4 3 4 9 6
how many even numbers are there in the sequence which are immediately preceded by an odd number & immediately followed by an even number?
option 1) 1option 2) 2option 3) 3option 4) 6option 5) 4
| question | careers360.com | 2020.50 | [
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"name": "",
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}
] |
f6e79b8135ebc869bf3d4728722c9741 | q.7. find r if
(ii) | question | careers360.com | 2020.16 | [
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}
] |
33f23cc9b23cd5a790aa160f04f28884 | q. 2. add:
(i) | question | careers360.com | 2020.45 | [
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"is_accepted": true
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] |
e167ac4fc0038e676446aa330029bc69 | q 7. which of the following materials fall in the category of a “pure substance”?
(a) ice
(b) milk
(c) iron
(d) hydrochloric acid
(e) calcium oxide
(f) mercury
(g) brick
(h) wood
(i) air | question | careers360.com | 2020.10 | [
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09d44ff6e35a920a4f4c6f0a5fa56b0b | q.1. find the value of:
| question | careers360.com | 2020.05 | [
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f685648016af2224dddf7e42de4e5ee0 |
5 1 4 7 3 9 8 5 7 2 6 3 1 5 8 6 3 8 5 2 2 4 3 4 9 6
how many odd numbers are there in the sequence which are immediately preceded & also immediately followed by an even number?
option 1) 5option 2) 2option 3) 3option 4) 4option 5) 1
| question | careers360.com | 2020.10 | [
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}
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37c4eb32d0b5064326976a80b2f02bd3 | q. 2. which out of the following are expressions with numbers only?
(a)
(b)
(c)
(d)
(e)
(f)
(g) | question | careers360.com | 2020.45 | [
{
"text": "81",
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}
] |
fe7732ade218aa76beceb53e8895c355 | conjugate base for bronsted acids and are :option 1) and , respectivelyoption 2) and , respectivelyoption 3) and , respectivelyoption 4) and , respectively | question | careers360.com | 2020.10 | [
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] |
21fd1efc7f785ca12b72f0bd4a847195 | 7.15 why is a liquid and a gas ? | question | careers360.com | 2020.45 | [
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] |
4e7e88cd9b6fc213549bf23ac191b149 | 1. solve
(g) (h) (i)
(j) (k) (l)
(m) (n) | question | careers360.com | 2020.05 | [
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] |
02f8f381093c02e974404e7cae8922b8 | 5. how quickly can you do this? fill appropriate sign.
(a)
(b)
(c)
(d)
(e)
(f)
(g)
(h)
(i)
(j)
(k) | question | careers360.com | 2020.05 | [
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32aaee317e632b4faab994748d2e8700 | 2. compare the fractions and put an appropriate sign.
(a)
(b)
(c)
(d) | question | careers360.com | 2020.16 | [
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] |
d4f18ae45c740296ca3554c50b1684e6 | the temporary hardness of a water sample is due to compound x. boiling this sample converts x to compound y. x and y, respectively, are:
option 1) and
option 2) and option 3) and option 4) and cao | question | careers360.com | 2020.10 | [
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348fb2bfdeb6902347d34fb408052ad5 | 11. match the terms in column i with those in column ii:
column i column ii
(a) compound epithelium (i) alimentary canal
(b) compound eye (ii) cockroach
(c) septal nephridia (iii) skin
(d) open circulatory system (iv) mosaic vision
(e) typhlosole (v) earthworm
(f) osteocytes (vi) phallomere
(g) genitalia (vii) bone | question | careers360.com | 2020.16 | [
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f8da441a240b73f43a011f8c8cd9bd98 | q : 1 multiply the binomials.
(v) and | question | careers360.com | 2021.04 | [
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] |
b135eac0c8f80ecfb73c8f34a232242a | q. 2. which out of the following are expressions with numbers only?
(a)
(b)
(c)
(d)
(e)
(f)
(g) | question | careers360.com | 2020.45 | [
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}
] |
8f4bbbe89e453765bfe05e1bdb64c7f7 | q : 8 let . verify that,
(i) | question | careers360.com | 2020.16 | [
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f8848e07df5ff7bce957f6a7f8037d52 | 1. fill in these boxes:
| question | careers360.com | 2020.16 | [
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b50c7b2dd804f4c7799ebea3b51ba059 | 2. take any point o in the interior of a triangle pqr. is
(i) ?
(ii) ?
(iii) ?
| question | careers360.com | 2020.05 | [
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519f5871a0b288e60fcb19f5c1e63c8a | q. 19. if a and b are any two events such that then
(a)
(b)
(c)
(d) | question | careers360.com | 2020.16 | [
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e3428bcf857e31b0f20cf659134d5540 | q20 integrate the functions | question | careers360.com | 2020.10 | [
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11ea019d47d0e1dd20d35cab5b29627c | 1. solve:
(i) (ii) (iii) (iv)
(v) (vi) (vii) | question | careers360.com | 2020.16 | [
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ac78c3f94c2444c329d209fda715e250 | 3. find:
| question | careers360.com | 2020.05 | [
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23bbffa7ee6a2f73bb22a75c4296e3bf | is a square root of | question | careers360.com | 2020.45 | [
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eed1eaf467107d2fea743e399b6ce0f9 | in the given figure, given that vbb supply can vary from 0 to 5.0 v, , the minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively :
option 1) 25 and 3.5 v
option 2) 25 and 2.8 v
option 3) 20 and 2.8 v
option 4) 20 and 3.5 v | question | careers360.com | 2020.50 | [
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bb18649ec0059a40670b34da44da8d17 | define species | question | careers360.com | 2020.45 | [
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aeda01e2324b2f34cb7e5c5d7b9a53fd | 2. find :
(iii) | question | careers360.com | 2020.05 | [
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b742812cbc5a44c4fa71911a72e8ddae | 3. identify the error, if any
this is
this is
this is
| question | careers360.com | 2020.05 | [
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4f9ea0d092e6cb27f098c701ff0205d2 | q : 4 simplify.
(iii) | question | careers360.com | 2020.10 | [
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cea501a6fa94079123b24872813b0fd2 | the group number, number of valence electrons, and valency of an element with atomic number 15, respectively, are:
option 1)
and
option 2)
and
option 3)
and
option 4)
and
| question | careers360.com | 2020.10 | [
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0c6a1f667dd0637d348c2a38ef45f64a | sir/ madam, which nift has top ranking for b ftech course and it's placement. please give it's order of choices | sir/ madam, which nift has top ranking for b ftech course and it's placement. please give it's order of choices | careers360.com | 2021.17 | [
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"text": " \n\n\nhi p rajendran,\n\nthere are many nift colleges in india. here are some colleges of nift according to ranking :\n\nrank college \n\n 1 nift delhi\n\n 2 nift mumbai\n\n 3 nift bangalore\n\n 4 pearl academy\n\n 5 nift chennai\n\n 6 nift patna\n\n 7 nift kolkata\n\n 8 nift hyderabad\n\n 9 nift gandhinagar\n\nconsidering placement all nift undergoing centralize placement. all the major national and international company visited on campus. an average ctc is between 2.5 lpa -6.5 lpa. they have some major recruiters. nift gandhinagar has highest package of 11.5 lpa. last year. \n\n",
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7e030e1394c11aafbcd72a73ba01745f | q9. expand using binomial theorem | question | careers360.com | 2020.16 | [
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2893b120d05eff9f47816231040d388b | which is the larger fraction?
(i) or
(ii) or
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a278750ab320ba9e9eb0943d41e55eb3 | q : 4 simplify.
(vi) | question | careers360.com | 2020.29 | [
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(ii) from
(iii) from
(iv) from
(v) from
(vi) from
(vii) from
(viii) from | question | careers360.com | 2020.05 | [
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fe6423c1e88164a701e20f98e745528e | 2. compare the fractions and put an appropriate sign.
(a)
(b)
(c)
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b348ee1b9cd3de943e5ba39d85f7427c | q. 2. add:
(i)
(ii)
(iii)
(iv)
(v)
vi)
(vii)
(viii)
(ix)
(x) | question | careers360.com | 2020.05 | [
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77de71b6b1c7114dcefd509f1a976734 |
5 1 4 7 3 9 8 5 7 2 6 3 1 5 8 6 3 8 5 2 2 4 3 4 9 6
how many odd numbers are there in the sequence which are immediately preceded & also immediately followed by an even number?
option 1) 5option 2) 2option 3) 3option 4) 4option 5) 1
| question | careers360.com | 2020.50 | [
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219a1882af343e413d6a0389638fdbc0 | q7. find x and y, if
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c6c0619a8767baffd7dc31031bc2c09a | 1. solve
(a) (b) (c)
(d) (e) (f)
| solve (a) 2/3 + 1/ 7 exercise 7.6 que. 1 | careers360.com | 2020.05 | [
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(a)
(b)
(c)
(d)
(e)
(f)
(g) | question | careers360.com | 2020.45 | [
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b7c853a456332e5f9049c7ec695da069 | q : 1 multiply the binomials.
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a31c5b4ee6f8ae0e499ed1b55768d32d | 5. find:
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ff2a5349d096e00fea476dbb10502a21 | html file: (i deleted all the codes like !doctype html, body tag an so on for sake of time and getting into main point)
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item 4
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item 1
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item 1
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flexbox file:
.container {
display: flex;
flex-wrap: wrap;
flex-direction: column;
height: 280px;
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{
"text": "it might be too much content for flexbox to manage on element of the smaller height. if you still want to use flex-direction with column. basically, you can increase the value of height to avoid overflow issue.\ncss\n.container {\n display: flex;\n flex-wrap: wrap;\n flex-direction: column;\n height: 280px; //increase this value\n}\n\nor as michael wells said, using flex-direction with row instead and removing height property can also fix overflow issue.\ncss\n.container {\n display: flex;\n flex-wrap: wrap;\n flex-direction: row;\n}",
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fb566cd984cad83225fee1d4218cb64b | UN PETIT JEU CON ARRIVER AU MILLIARD DE MESSAGES
JE COMMENCE
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"is_accepted": false
},
{
"text": "17443",
"name": "",
"is_accepted": false
},
{
"text": "17444",
"name": "",
"is_accepted": false
},
{
"text": "17445",
"name": "",
"is_accepted": false
},
{
"text": "17446",
"name": "",
"is_accepted": false
},
{
"text": "17447",
"name": "",
"is_accepted": false
},
{
"text": "17448",
"name": "",
"is_accepted": false
},
{
"text": "17449",
"name": "",
"is_accepted": false
},
{
"text": "17450",
"name": "",
"is_accepted": false
},
{
"text": "17451",
"name": "",
"is_accepted": false
},
{
"text": "17452",
"name": "",
"is_accepted": false
},
{
"text": "17453",
"name": "",
"is_accepted": false
},
{
"text": "17454",
"name": "",
"is_accepted": false
},
{
"text": "17455",
"name": "",
"is_accepted": false
},
{
"text": "17456",
"name": "",
"is_accepted": false
},
{
"text": "17457",
"name": "",
"is_accepted": false
},
{
"text": "17458",
"name": "",
"is_accepted": false
},
{
"text": "17459",
"name": "",
"is_accepted": false
},
{
"text": "17460",
"name": "",
"is_accepted": false
},
{
"text": "17461",
"name": "",
"is_accepted": false
},
{
"text": "17462",
"name": "",
"is_accepted": false
},
{
"text": "17463",
"name": "",
"is_accepted": false
},
{
"text": "17464",
"name": "",
"is_accepted": false
},
{
"text": "17465",
"name": "",
"is_accepted": false
},
{
"text": "17466",
"name": "",
"is_accepted": false
},
{
"text": "17467",
"name": "",
"is_accepted": false
},
{
"text": "17468",
"name": "",
"is_accepted": false
},
{
"text": "17431",
"name": "",
"is_accepted": false
},
{
"text": "17469 zut rater une page",
"name": "",
"is_accepted": false
},
{
"text": "17470",
"name": "",
"is_accepted": false
},
{
"text": "17471",
"name": "",
"is_accepted": false
},
{
"text": "17472",
"name": "",
"is_accepted": false
},
{
"text": "17473",
"name": "",
"is_accepted": false
},
{
"text": "17474",
"name": "",
"is_accepted": false
},
{
"text": "17475",
"name": "",
"is_accepted": false
},
{
"text": "17476",
"name": "",
"is_accepted": false
},
{
"text": "17477",
"name": "",
"is_accepted": false
},
{
"text": "17478",
"name": "",
"is_accepted": false
},
{
"text": "17479",
"name": "",
"is_accepted": false
}
] |
ea1f48472b01b8a928f5ad7db81ef054 | 1
Le but est de battre le jeu qui se trouve sur un autre forum où ils en sont déjà à plus de 18341 par contre on n'a pas le droit de jouer 2 fois de suite. | Petit Jeu... | doctissimo.fr | 2020.50 | [
{
"text": "21529",
"name": "",
"is_accepted": false
},
{
"text": "21530",
"name": "",
"is_accepted": false
},
{
"text": "21531",
"name": "",
"is_accepted": false
},
{
"text": "21532",
"name": "",
"is_accepted": false
},
{
"text": "21533",
"name": "",
"is_accepted": false
},
{
"text": "21 534",
"name": "",
"is_accepted": false
},
{
"text": "21535",
"name": "",
"is_accepted": false
},
{
"text": "21 536",
"name": "",
"is_accepted": false
},
{
"text": "21537",
"name": "",
"is_accepted": false
},
{
"text": "21 538",
"name": "",
"is_accepted": false
},
{
"text": "21538",
"name": "",
"is_accepted": false
},
{
"text": "21539",
"name": "",
"is_accepted": false
},
{
"text": "21 540",
"name": "",
"is_accepted": false
},
{
"text": "21541",
"name": "",
"is_accepted": false
},
{
"text": "21 542",
"name": "",
"is_accepted": false
},
{
"text": "21543",
"name": "",
"is_accepted": false
},
{
"text": "21 544",
"name": "",
"is_accepted": false
},
{
"text": "21545",
"name": "",
"is_accepted": false
},
{
"text": "21 546",
"name": "",
"is_accepted": false
},
{
"text": "21547",
"name": "",
"is_accepted": false
},
{
"text": "21 548",
"name": "",
"is_accepted": false
},
{
"text": "21 549",
"name": "",
"is_accepted": false
},
{
"text": "21550",
"name": "",
"is_accepted": false
},
{
"text": "21551",
"name": "",
"is_accepted": false
},
{
"text": "21552",
"name": "",
"is_accepted": false
},
{
"text": "21553",
"name": "",
"is_accepted": false
},
{
"text": "21 554\n\nbon ap'",
"name": "",
"is_accepted": false
},
{
"text": "21555 Bon ap' à toi aussi !",
"name": "",
"is_accepted": false
},
{
"text": "21556",
"name": "",
"is_accepted": false
},
{
"text": "21557",
"name": "",
"is_accepted": false
},
{
"text": "21558",
"name": "",
"is_accepted": false
},
{
"text": "21559",
"name": "",
"is_accepted": false
},
{
"text": "21560",
"name": "",
"is_accepted": false
},
{
"text": "21561",
"name": "",
"is_accepted": false
},
{
"text": "21 562",
"name": "",
"is_accepted": false
},
{
"text": "21563",
"name": "",
"is_accepted": false
},
{
"text": "21564",
"name": "",
"is_accepted": false
},
{
"text": "21 565",
"name": "",
"is_accepted": false
},
{
"text": "21566... questions...",
"name": "",
"is_accepted": false
},
{
"text": "21 567",
"name": "",
"is_accepted": false
},
{
"text": "21568",
"name": "",
"is_accepted": false
},
{
"text": "21569",
"name": "",
"is_accepted": false
},
{
"text": "21 570",
"name": "",
"is_accepted": false
},
{
"text": "21571",
"name": "",
"is_accepted": false
},
{
"text": "21572",
"name": "",
"is_accepted": false
},
{
"text": "21573",
"name": "",
"is_accepted": false
},
{
"text": "21574",
"name": "",
"is_accepted": false
},
{
"text": "21575",
"name": "",
"is_accepted": false
},
{
"text": "21 576",
"name": "",
"is_accepted": false
},
{
"text": "21577",
"name": "",
"is_accepted": false
},
{
"text": "21 578",
"name": "",
"is_accepted": false
}
] |
e3b7bca0116b7d33a5f979a421cb6a2e | 1
Le but est de battre le jeu qui se trouve sur un autre forum où ils en sont déjà à plus de 18341 par contre on n'a pas le droit de jouer 2 fois de suite. | Petit Jeu... | doctissimo.fr | 2020.50 | [
{
"text": "13047",
"name": "",
"is_accepted": false
},
{
"text": "13048",
"name": "",
"is_accepted": false
},
{
"text": "13049",
"name": "",
"is_accepted": false
},
{
"text": "13050",
"name": "",
"is_accepted": false
},
{
"text": "13051 mon année de naissance 51",
"name": "",
"is_accepted": false
},
{
"text": "13052",
"name": "",
"is_accepted": false
},
{
"text": ":hello: \n13053",
"name": "",
"is_accepted": false
},
{
"text": "13054",
"name": "",
"is_accepted": false
},
{
"text": "13055",
"name": "",
"is_accepted": false
},
{
"text": "13056",
"name": "",
"is_accepted": false
},
{
"text": "13057",
"name": "",
"is_accepted": false
},
{
"text": "13058",
"name": "",
"is_accepted": false
},
{
"text": "13 059",
"name": "",
"is_accepted": false
},
{
"text": "13060",
"name": "",
"is_accepted": false
},
{
"text": "13061",
"name": "",
"is_accepted": false
},
{
"text": "13062",
"name": "",
"is_accepted": false
},
{
"text": "13063",
"name": "",
"is_accepted": false
},
{
"text": "13064",
"name": "",
"is_accepted": false
},
{
"text": "13065",
"name": "",
"is_accepted": false
},
{
"text": "13066",
"name": "",
"is_accepted": false
},
{
"text": "13 067",
"name": "",
"is_accepted": false
},
{
"text": "13068",
"name": "",
"is_accepted": false
},
{
"text": "13069",
"name": "",
"is_accepted": false
},
{
"text": "13070",
"name": "",
"is_accepted": false
},
{
"text": "13 071",
"name": "",
"is_accepted": false
},
{
"text": "13 072",
"name": "",
"is_accepted": false
},
{
"text": "13073",
"name": "",
"is_accepted": false
},
{
"text": "13074",
"name": "",
"is_accepted": false
},
{
"text": "13075",
"name": "",
"is_accepted": false
},
{
"text": "13 076",
"name": "",
"is_accepted": false
},
{
"text": "13 077",
"name": "",
"is_accepted": false
},
{
"text": "13078...",
"name": "",
"is_accepted": false
},
{
"text": "13079",
"name": "",
"is_accepted": false
},
{
"text": "13 080",
"name": "",
"is_accepted": false
},
{
"text": "13 081",
"name": "",
"is_accepted": false
},
{
"text": "13082",
"name": "",
"is_accepted": false
},
{
"text": "13083",
"name": "",
"is_accepted": false
},
{
"text": "13084",
"name": "",
"is_accepted": false
},
{
"text": "13085",
"name": "",
"is_accepted": false
},
{
"text": "13086",
"name": "",
"is_accepted": false
},
{
"text": "13087",
"name": "",
"is_accepted": false
},
{
"text": "13088",
"name": "",
"is_accepted": false
},
{
"text": "13089",
"name": "",
"is_accepted": false
},
{
"text": "13090",
"name": "",
"is_accepted": false
},
{
"text": "13091",
"name": "",
"is_accepted": false
},
{
"text": "13092",
"name": "",
"is_accepted": false
},
{
"text": "13093",
"name": "",
"is_accepted": false
},
{
"text": "13094",
"name": "",
"is_accepted": false
},
{
"text": "13095",
"name": "",
"is_accepted": false
},
{
"text": "13096",
"name": "",
"is_accepted": false
},
{
"text": "13097",
"name": "",
"is_accepted": false
}
] |
c427be25007fd9dbd42bf45cf0c823d6 | 1
Le but est de battre le jeu qui se trouve sur un autre forum où ils en sont déjà à plus de 18341 par contre on n'a pas le droit de jouer 2 fois de suite. | Petit Jeu... | doctissimo.fr | 2020.50 | [
{
"text": "1445",
"name": "",
"is_accepted": false
},
{
"text": "1446",
"name": "",
"is_accepted": false
},
{
"text": "1447",
"name": "",
"is_accepted": false
},
{
"text": "1448",
"name": "",
"is_accepted": false
},
{
"text": "1449",
"name": "",
"is_accepted": false
},
{
"text": "1450",
"name": "",
"is_accepted": false
},
{
"text": "1451...",
"name": "",
"is_accepted": false
},
{
"text": "1452 :bounce:",
"name": "",
"is_accepted": false
},
{
"text": "1453",
"name": "",
"is_accepted": false
},
{
"text": "1454\nà demain",
"name": "",
"is_accepted": false
},
{
"text": "1455 bye bye",
"name": "",
"is_accepted": false
},
{
"text": "1456",
"name": "",
"is_accepted": false
},
{
"text": "1457",
"name": "",
"is_accepted": false
},
{
"text": "1458",
"name": "",
"is_accepted": false
},
{
"text": "1459",
"name": "",
"is_accepted": false
},
{
"text": "1500 wahouuuuuuuuuuuuuuuuuu",
"name": "",
"is_accepted": false
},
{
"text": "ah non raté LOL 1460",
"name": "",
"is_accepted": false
},
{
"text": "lol 1461",
"name": "",
"is_accepted": false
},
{
"text": "1462",
"name": "",
"is_accepted": false
},
{
"text": "1463",
"name": "",
"is_accepted": false
},
{
"text": "1464",
"name": "",
"is_accepted": false
},
{
"text": "1465",
"name": "",
"is_accepted": false
},
{
"text": "1466",
"name": "",
"is_accepted": false
},
{
"text": "1467",
"name": "",
"is_accepted": false
},
{
"text": "1468 lodilodi :hello:",
"name": "",
"is_accepted": false
},
{
"text": "1469",
"name": "",
"is_accepted": false
},
{
"text": "1470",
"name": "",
"is_accepted": false
},
{
"text": "1471 coucou",
"name": "",
"is_accepted": false
},
{
"text": "1472 hi hi",
"name": "",
"is_accepted": false
},
{
"text": "1473",
"name": "",
"is_accepted": false
},
{
"text": "1474",
"name": "",
"is_accepted": false
},
{
"text": "1475",
"name": "",
"is_accepted": false
},
{
"text": "1476",
"name": "",
"is_accepted": false
},
{
"text": "1477",
"name": "",
"is_accepted": false
},
{
"text": "1478",
"name": "",
"is_accepted": false
},
{
"text": "1479",
"name": "",
"is_accepted": false
},
{
"text": "1480",
"name": "",
"is_accepted": false
},
{
"text": "1481",
"name": "",
"is_accepted": false
},
{
"text": "1482",
"name": "",
"is_accepted": false
},
{
"text": "1482",
"name": "",
"is_accepted": false
},
{
"text": "1483",
"name": "",
"is_accepted": false
},
{
"text": "1482\nC'est comme ça que ça marche je crois Biz",
"name": "",
"is_accepted": false
},
{
"text": "1484",
"name": "",
"is_accepted": false
},
{
"text": "1485",
"name": "",
"is_accepted": false
},
{
"text": "1486",
"name": "",
"is_accepted": false
},
{
"text": "1487",
"name": "",
"is_accepted": false
},
{
"text": "1488",
"name": "",
"is_accepted": false
},
{
"text": "1489",
"name": "",
"is_accepted": false
},
{
"text": "1490",
"name": "",
"is_accepted": false
},
{
"text": "1491",
"name": "",
"is_accepted": false
},
{
"text": "1492",
"name": "",
"is_accepted": false
}
] |
0ac552c1af930bb5179fcb34ee96eb11 | 1
Le but est de battre le jeu qui se trouve sur un autre forum où ils en sont déjà à plus de 18341 par contre on n'a pas le droit de jouer 2 fois de suite. | Petit Jeu... | doctissimo.fr | 2020.50 | [
{
"text": "23007",
"name": "",
"is_accepted": false
},
{
"text": "23008 fais de beaux rêves :hello:",
"name": "",
"is_accepted": false
},
{
"text": "merci des bêtises",
"name": "",
"is_accepted": false
},
{
"text": "j'ai rattrapé hihihih",
"name": "",
"is_accepted": false
},
{
"text": "merci :hello:",
"name": "",
"is_accepted": false
},
{
"text": "23009",
"name": "",
"is_accepted": false
},
{
"text": "23010",
"name": "",
"is_accepted": false
},
{
"text": "23 011",
"name": "",
"is_accepted": false
},
{
"text": "23012",
"name": "",
"is_accepted": false
},
{
"text": "23 013",
"name": "",
"is_accepted": false
},
{
"text": "23014.",
"name": "",
"is_accepted": false
},
{
"text": "23015",
"name": "",
"is_accepted": false
},
{
"text": "23016",
"name": "",
"is_accepted": false
},
{
"text": "23017.",
"name": "",
"is_accepted": false
},
{
"text": "23018",
"name": "",
"is_accepted": false
},
{
"text": "23019",
"name": "",
"is_accepted": false
},
{
"text": "23 020",
"name": "",
"is_accepted": false
},
{
"text": "23021",
"name": "",
"is_accepted": false
},
{
"text": "23022",
"name": "",
"is_accepted": false
},
{
"text": "23023",
"name": "",
"is_accepted": false
},
{
"text": "230024",
"name": "",
"is_accepted": false
},
{
"text": "23025",
"name": "",
"is_accepted": false
},
{
"text": "23026",
"name": "",
"is_accepted": false
},
{
"text": "23027",
"name": "",
"is_accepted": false
},
{
"text": "23028",
"name": "",
"is_accepted": false
},
{
"text": "23029",
"name": "",
"is_accepted": false
},
{
"text": "23030 % lol",
"name": "",
"is_accepted": false
},
{
"text": "23031",
"name": "",
"is_accepted": false
},
{
"text": "23032",
"name": "",
"is_accepted": false
},
{
"text": "23033",
"name": "",
"is_accepted": false
},
{
"text": "23034.",
"name": "",
"is_accepted": false
},
{
"text": "23035",
"name": "",
"is_accepted": false
},
{
"text": "23036",
"name": "",
"is_accepted": false
},
{
"text": "23037",
"name": "",
"is_accepted": false
},
{
"text": "23038",
"name": "",
"is_accepted": false
},
{
"text": "23039",
"name": "",
"is_accepted": false
},
{
"text": "23038",
"name": "",
"is_accepted": false
},
{
"text": "lol 23039",
"name": "",
"is_accepted": false
},
{
"text": "lol 23040 % lol",
"name": "",
"is_accepted": false
},
{
"text": "23041",
"name": "",
"is_accepted": false
},
{
"text": "23042",
"name": "",
"is_accepted": false
},
{
"text": "23043",
"name": "",
"is_accepted": false
},
{
"text": "23044.",
"name": "",
"is_accepted": false
},
{
"text": "23045",
"name": "",
"is_accepted": false
},
{
"text": "23046",
"name": "",
"is_accepted": false
},
{
"text": "23047",
"name": "",
"is_accepted": false
},
{
"text": "23048 et ainsi de suite lol",
"name": "",
"is_accepted": false
},
{
"text": "23049",
"name": "",
"is_accepted": false
},
{
"text": "23050. merci",
"name": "",
"is_accepted": false
},
{
"text": "23051 de rien",
"name": "",
"is_accepted": false
},
{
"text": "23052 j'insiste ! lol",
"name": "",
"is_accepted": false
}
] |
2b87a4262ec016545f581ea09eec6b2a | no any | where is the largest cinema hall in the world. | onlinegkguide.com | 2019.47 | [
{
"text": "Colosseum Kino",
"name": "",
"is_accepted": false
}
] |
07a34bcbab018a5c3cbc453bb132f8ae | Who among the following was the advocate at the famous ‘I.N.A. trials?
A. Subhash Chandra Bose
B. Rajagopalachari
C. Asaf Ali
D. Bhulabhai Desai | Who among the following was the advocate at the famous ‘I.N.A. trials? | onlinegkguide.com | 2019.47 | [
{
"text": "Bhulabhai Desai",
"name": "",
"is_accepted": false
}
] |
cbfbc8ff610e18d4521eabc1c404f520 | i was double billed from november 2016 to march 2019.
i called on feb 23, 2019 reference # (edited as per community guidelines) was the person i spoke with.
has been getting double billed since nov 2016
there were two accounts getting billed.
account # (edited as per community guidelines)
account # (edited as per community guidelines)
called again mon mar 18, 2019 spoke to (edited as per community guidelines)
transferred to accounts receivable spoke to (edited as per community guidelines)
transferred to billing needed credit before check can be issued spoke with (edited as per community guidelines)
told me to call back in a week
when i called back i had a person tell me that i had no recourse and could not get my money back.
i quit calling after that.
below are the transactions from 10/10/2017 to 3/18/2019
i can get the rest of the bank statements to november 2016.
-70.00 1011epayj 3/18/2019
-70.00 8011epayz 3/7/2019
-70.00 5011epayd 2/13/2019
-70.00 6011epayv 2/5/2019
-70.00 2011epayy 1/14/2019
-70.00 2011epayp 1/4/2019
-70.00 8011epayu 12/14/2018
-70.00 2011epaym 12/6/2018
-70.00 8011epayq 11/14/2018
-70.00 4011epayh 11/6/2018
-70.00 0011epaym 10/16/2018
-70.00 7011epaye 10/9/2018
-70.00 9011epayg 9/13/2018
-70.00 9011epayx 9/5/2018
-70.00 3011epayb 8/14/2018
-70.00 8011epays 8/6/2018
-70.00 5011epayx 7/16/2018
-70.00 2011epayo 7/5/2018
-70.00 2011epayr 6/12/2018
-70.00 3011epayi 6/4/2018
-70.00 0011epayo 5/15/2018
-70.00 0011epayf 5/7/2018
-70.00 2011epayi 4/12/2018
-70.00 3011epayz 4/3/2018
-70.00 8011epayh 3/16/2018
-70.00 5011epayx 3/6/2018
-70.00 4011epayc 2/13/2018
-70.00 6011epayt 2/5/2018
-70.00 1001epayq 1/12/2018
-70.00 4011epayn 1/3/2018
-70.00 9011epayt 12/14/2017
-70.00 0011epayj 12/5/2017
-70.00 1011epayo 11/13/2017
-70.00 3011epayh 11/6/2017
-70.00 0011epayl 10/16/2017
-70.00 9011epaye 10/10/2017
i want to get my money back. when i called i felt like i was getting the run around and being told that i had no recourse and could not get my money made me feel very bad about at&t.
thanks,
brent (edited as per community guidelines) | double billed from november 2016 to march 2019 | att.com | 2021.43 | [
{
"text": "this forum is not customer support. no one here will be able to help you. it is also a public forum, please remove your personal information. i hate to be the bearer of bad news but you likely won’t get anything back except 3 months worth. it is your responsibility to report billing errors within 3 months. how you managed to not notice double payments for years is on you. you can escalate to corporate by filing an fcc or bbb complaint. if they can’t or won’t refund, no one will.",
"name": "",
"is_accepted": false
},
{
"text": "have to agree with sandblaster, at&t's terms and conditions require you to notify them with a certain period (i thought it was 60 days, not 3 months). so the most you'll will get per their policies is the period covered by that. \n ",
"name": "",
"is_accepted": false
}
] |
ccf026e2a553e3d9cc825c0b9ddf4997 | bonsoir,
après avoir lancer l'émulateur avec succès, je me retrouve avec cette erreur une fois la config de dofus modifiée (image si dessous)
j’espère que vous saurez aider un vieux joueur nostalgique, merci d'avance !
la config :
| erreur impossible de verifier les mises à jour (cyonemu 2.9) | funky-emu.net | 2021.43 | [
{
"text": "salut, \n \n\ntu as voulu rediriger tes langs pour ton serveur privé ? parce que là, tu as modifié l'adresse des ftp de base d'ankama et si ta redirection est mauvaise ca doit venir de là. \n \n\n \n\n\n\n\n\n\n\n\n\n\n \n \n\n-> \n \n\n \n\n\n\n(si c'est bien ta redirection)\n\n\n\n\n\n\n \n",
"name": "",
"is_accepted": false
}
] |
9266e86b4b632aa37b0b846fb981a3a2 | Lewis Steele and Catherine Blevins appear to have been born on Kentucky in 1814 and travelled to Alabama with their families soon after. They later married in Tennessee, Georgia or Alabama. I have not been able to connect Catherine to any Blevins line, but i believe she is somehow related to Cornblossom, the wife of Jacob Troxell. | Looking for the parents of Catherine Blevins, b. 1814, who married Lewis Steele in DeKalb Co Alabama. | wikitree.com | 2020.40 | [
{
"text": "\nFifth generation children of [Jonathan Blevins Jr](http://www.wikitree.com/wiki/Blevins-640). and Catherine “Caty” (Troxel) Blevins:\n\n\n1. Timothy b. 1805\n\n\n2. Pleasant/Plesant b. 1806\n\n\n3. Jonathan III b. 1808\n\n\n4. Mary A. b. 1809\n\n\n5. Tarlton b. 1810\n\n\n6. Jacob b. 1811\n\n\n7. Ada b. 1812\n\n\n8. Catherine b. 1813\n\n\nFifth generation children of Jonathan Blevins Jr. and Sarah “Sally” Minton Blevins:\n\n\n9. Henley b. 1815\n\n\n10. Armstead b. 1820\n\n\n11. Isaac b. 1822\n\n\nFor more info email [LBlevins@sunflower.com](mailto:LBlevins@sunflower.com)\n\n",
"name": "",
"is_accepted": false
}
] |
a1e318579650de30b699c064e5824c6a |
Bon dia!els rentats nasals amb SSF 0,9%postcirurgia han de ser a gravetat O amb xeringa?
Moltes g
| doctoralia.es | 2020.29 | [
{
"text": "\n\n bon dia, si és amb pressió amb xeringa serà mes eficient per eliminar crostes nasals. \n\nSaludos\n \n",
"name": "",
"is_accepted": false
}
] |
|
0284950d81424b5166badffad1e9eb75 | a+b+c=\dfrac{\pi }{2}, then \tan a \tan b+\tan b \tan c+\tan a \tan c= | a+b+c=\dfrac{\pi }{2}, then \tan a \tan b+\tan b \tan c+\tan a \tan c= | findfilo.com | 2021.39 | [
{
"text": "given a+b+c=\\dfrac{\\pi }{2} \na+b=\\dfrac{\\pi }{2}-c \n\\rightarrow \\dfrac{\\tan a+\\tan b}{1-\\tan a \\tan b}=\\cot c=\\dfrac{1}{\\tan c} \n\\rightarrow \\tan a \\tan c+\\tan b \\tan c+\\tan a \\tan b=1",
"name": "",
"is_accepted": true
}
] |
71bae668b0f55904740c55980bfbc26e | match the columns. list i list ii a ovary wall 1food b double fertilization 2seeds c dormancy 3angiosperms d endosperm 4pericarp | match the columns. list i list ii a ovary wall 1food b double fertilization 2seeds c dormancy 3angiosperms d endosperm 4pericarp | findfilo.com | 2021.17 | [
{
"text": "ovary wall is also called as pericarp. the pericarp is the part of fruit enclosing the seeds that develop from the wall of the ovary. double fertilization is the characteristic feature of angiosperms, where triple fusion takes place and results in the formation of triploid endosperm for nourishing the zygote formed by fusion of male gamete with the egg cell, a process called double fertilization. dormancy is a mechanism, to prevent germination during unsuitable environmental conditions when the probability of seedling survival is low. endosperm formed in the ovule provides nourishment for the growing embryo. it gets depleted by the time embryo grows up to a seedling. \nso, the correct answer is option b.",
"name": "",
"is_accepted": true
}
] |
c5429679ef5f33d87714595c166205c4 | int(sin^2x-cos^2x)/(sin^2cos^2x)dxis equal to(a) tanx+cotx+c (b) tanx+cose cx+c(c) -tanx+cotx+c (d) tanx+secx+c | int(sin^2x-cos^2x)/(sin^2cos^2x)dxis equal to(a) tanx+cotx+c (b) tanx+cose cx+c(c) -tanx+cotx+c (d) tanx+secx+c | findfilo.com | 2021.39 | [
{
"text": "no answer",
"name": "",
"is_accepted": true
}
] |
473fad9e9f98367124c066369f383aa2 |
Necesito construir un array multidimensional con una tabla html
```
<!DOCTYPE html>
<html>
<body>
<?php
$ciutats = array
(
array('Tòquio','Japó','Àsia'),
array('Mèxic', 'DF', 'Amèrica'),
array('Nova York', 'EUA', 'Amèrica'),
array('Mumbai', 'India', 'Ásia'),
array('Seül', 'Corea', 'Àsia'),
array('Xangai', 'Xina', 'Àsia'),
array('Lagos', 'Nigeria', 'Àfrica'),
array('Buenos Aires', 'Argentina', 'Amèrica'),
array('el Caire', 'Seül', 'Corea'),
);
?>
</body>
</html>
```
| [HTML PHP Array multidimensional](/questions/206519/html-php-array-multidimensional)
====================================================================================
| stackoverflow.com | 2019.43 | [
{
"text": "\nPrueba a ver si esto te sirve ;)\n\n\n\n```\n<?php\n\n$ciutats = array(\n array('Tòquio','Japó','Àsia'),\n array('Mèxic', 'DF', 'Amèrica'),\n array('Nova York', 'EUA', 'Amèrica'),\n array('Mumbai', 'India', 'Ásia'),\n array('Seül', 'Corea', 'Àsia'),\n array('Xangai', 'Xina', 'Àsia'),\n array('Lagos', 'Nigeria', 'Àfrica'),\n array('Buenos Aires', 'Argentina', 'Amèrica'),\n array('el Caire', 'Seül', 'Corea'),\n);\n\n echo \"<table style=\\\"border-collapse: collapse; border: 1px solid black;\\\">\";\nfor ($r=0; $r < count($ciutats); $r++) { \n echo \"<tr>\";\n for ($ciutat=0; $ciutat < count($ciutats[$r]); $ciutat++) { \n echo \"<td style=\\\"text-align: center;width: 8em; border: 1px solid black; padding-left: 4px;\\\">\" . $ciutats[$r][$ciutat] . \"</td>\";\n }\n echo \"</tr>\";\n}\necho \"</table>\";\n?>\n\n```\n\nUtilizalo como base para tu ejercicio, Suerte :)\n\n\n\n> \n> Corrijo\n> \n> \n> \n> > \n> > Asi se añaden el encabezado que se me habia olvidado\n> > \n> > \n> > \n> \n> \n> \n\n\n\n```\n<?php\n\n$ciutats = array(\n array('Tòquio','Japó','Àsia'),\n array('Mèxic', 'DF', 'Amèrica'),\n array('Nova York', 'EUA', 'Amèrica'),\n array('Mumbai', 'India', 'Ásia'),\n array('Seül', 'Corea', 'Àsia'),\n array('Xangai', 'Xina', 'Àsia'),\n array('Lagos', 'Nigeria', 'Àfrica'),\n array('Buenos Aires', 'Argentina', 'Amèrica'),\n array('el Caire', 'Seül', 'Corea'),\n);\n\n echo \"<table style=\\\"border-collapse: collapse; border: 1px solid black;\\\">\";\n echo \"<tr style=\\\"width: 8em; border: 1px solid black; padding-left: 4px;\\\"><th>Ciudad</th><th>Pais</th><th>Continente</th><tr>\";\nfor ($r=0; $r < count($ciutats); $r++) { \n echo \"<tr>\";\n for ($ciutat=0; $ciutat < count($ciutats[$r]); $ciutat++) { \n echo \"<td style=\\\"text-align: center;\\\">\" . $ciutats[$r][$ciutat] . \"</td>\";\n }\n echo \"</tr>\";\n}\necho \"</tr>\";\n?>\n\n```\n\n",
"name": "",
"is_accepted": true
}
] |
7a4d639706a3faca6d12c23a8821b3e9 |
Добрый день, вроде нетривиальная задача, но что-то не могу въехать. В общем, у меня в цикле из БД вытаскиваются значения, нужно запихнуть их в ассоциативный массив, при чем посчитать повторы, я хочу это делать примерно так:
if ($str=='1') $mas['один'] +=1;
if ($str=='2') $mas['два'] +=1;
Ну и в этом духе. Но дело в том, что вместо того, чтобы увеличилось значение счетчика ассоциативного массива, добавляется еще дополнительная пара ключ=>значение, а нужно просто переписать, увеличив значение на единичку... Как это сделать?
| [Увеличение значения в ассоциативном массиве](/questions/655198/%d0%a3%d0%b2%d0%b5%d0%bb%d0%b8%d1%87%d0%b5%d0%bd%d0%b8%d0%b5-%d0%b7%d0%bd%d0%b0%d1%87%d0%b5%d0%bd%d0%b8%d1%8f-%d0%b2-%d0%b0%d1%81%d1%81%d0%be%d1%86%d0%b8%d0%b0%d1%82%d0%b8%d0%b2%d0%bd%d0%be%d0%bc-%d0%bc%d0%b0%d1%81%d1%81%d0%b8%d0%b2%d0%b5)
===============================================================================================================================================================================================================================================================================================================
| stackoverflow.com | 2021.10 | [
{
"text": "\nЕсли твой массив рождается уже в цикле и не назначен до него то было-бы не плохо его определять \n\n\n... цыкл ...\n\n\n\n```\nif(!isset($mas)){\n $mas = array();\n};\n\nif($str=='1'){\n if(!isset($mas['один'])){\n $mas['один'] = 1;\n }else{\n $mas['один'] +=1;\n };\n};\n\nif($str=='2'){\n if(!isset($mas['два'])){\n $mas['два'] = 1;\n }else{\n $mas['два'] +=1;\n };\n};\n\n```\n\n... // цыкл ...\n\n\n",
"name": "",
"is_accepted": false
}
] |
e62f5373e1d9f3ad7a54b2635a2b61c7 |
Quero que quando eu click nos radios faça a chamada da função, atualmente esta assim.
```
$("input[name='txtCategoria']").on('blur', function(){
var txtCategoria = $(this).val();
$.get('buscar_tipos.php?txtCategoria=' + txtCategoria,function(data){
$('#tipos').html(data);
});
});
```
Porem so quando eu clico no radio e clico em outra parte da pagina que aparece a consulta, queria que quando clica-se ja executa-se, tentei assim.
```
$("input[name='txtCategoria']").on("click", function(){
var txtCategoria = $(this).val();
$.get('buscar_tipos.php?txtCategoria=' + txtCategoria,function(data){
$('#tipos').html(data);
});
});
```
Mas não funcionou, alguém poderia me ajudar?
| [Alterar “on” para “click” em função JavaScript](/questions/192661/alterar-on-para-click-em-fun%c3%a7%c3%a3o-javascript)
========================================================================================================================
| stackoverflow.com | 2021.17 | [
{
"text": "\n`blur` quer dizer *\"quando o elemento perder o foco\"*. É isso que acontece quando clicas fora desse elemento, e a função corre. Porque ele \"perdeu o foco\".\n\n\nO mais semântico seria usar o [`change`](https://developer.mozilla.org/en-US/docs/Web/Events/change), que é quando o `input` mudar de valor. Assim, mesmo para quem navegue e mude o input com o teclado, a lógica vai funcionar.\n\n\n\n```\n$(\"input[name='txtCategoria']\").on(\"change\", function() {\n $.get('buscar_tipos.php?txtCategoria=' + this.value, function(data) {\n $('#tipos').html(data);\n });\n});\n\n```\n\n",
"name": "",
"is_accepted": true
}
] |
0bf9cb7bd9539effb144983e1a33e6af |
tengo un pequeño problema y no alcanzo a entender xsl.
El caso es que tengo un xml con una tienda, que contiene productos y por otro lado, clientes, los cuales tienen nombre, apellidos, 4 tipos de numero de telefono, y la lista de la compra.
Lo que es ordenar los clientes, con sus nombres y todo eso lo tengo listo.
Lo que me falta es el poder calcular el subtotal de cada producto que compran (cantidad * precioProducto)
La cantidad está en la lista de la compra y el precioProducto está en la lista de productos.
Mejor dejo el codigo que tengo puesto:
>
> ACLARACIÓN: El contenido completo del XML esta generado por un script
> java, tanto nombres como numeros tanto las facturas son ficticias.
>
>
>
XML:
```
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="factures.xsl"?>
<tenda>
<productes>
<producte preuUnitat='2.0'>Vi blanc botella 1L</producte>
<producte preuUnitat='5.0'>Vi blanc botella 2L</producte>
<producte preuUnitat='7.0'>Vi blanc garrafa 3L</producte>
<producte preuUnitat='10.0'>Vi blanc garrafa 5L</producte>
<producte preuUnitat='12.0'>Vi negre botella 1L</producte>
<producte preuUnitat='15.0'>Vi negre botella 2L</producte>
<producte preuUnitat='20.0'>Vi negre garrafa 3L</producte>
<producte preuUnitat='25.0'>Vi negre garrafa 5L</producte>
<producte preuUnitat='30.0'>Vi rosat botella 1L</producte>
<producte preuUnitat='50.0'>Vi rosat botella 2L</producte>
<producte preuUnitat='60.0'>Vi rosat garrafa 3L</producte>
<producte preuUnitat='70.0'>Vi rosat garrafa 5L</producte>
</productes>
<factures>
<factura numero="1">
<client>
<nom>Maria Josefa</nom>
<cognoms>Crespo Soto</cognoms>
<telefons>
<mobil tipus="feina">701 194 296</mobil>
</telefons>
</client>
<compra>
<producte id='n2'>9</producte>
<producte id='n3'>3</producte>
<producte id='r1'>4</producte>
<producte id='r2'>1</producte>
<producte id='r3'>2</producte>
</compra>
</factura>
<factura numero="2">
<client>
<nom>Manuela</nom>
<cognoms>Lara Rico</cognoms>
<telefons>
<mobil tipus="privat">665 852 593</mobil>
<fixe tipus="privat">943 213 214</fixe>
<fixe tipus="feina">979 427 658</fixe>
</telefons>
</client>
<compra>
<producte id='b1'>10</producte>
<producte id='b2'>6</producte>
<producte id='b3'>2</producte>
<producte id='b5'>9</producte>
<producte id='r3'>7</producte>
</compra>
</factura>
<factura numero="3">
<client>
<nom>Emilio</nom>
<cognoms>Santos</cognoms>
<telefons>
<mobil tipus="privat">725 215 087</mobil>
<fixe tipus="privat">810 696 902</fixe>
</telefons>
</client>
<compra>
<producte id='b2'>1</producte>
<producte id='b3'>3</producte>
<producte id='n2'>9</producte>
<producte id='n3'>4</producte>
<producte id='r1'>1</producte>
<producte id='r2'>1</producte>
</compra>
</factura>
</factures>
</tenda>
```
Y el XSL:
```
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"/>
<xsl:template match="compra">
<div class="listaCompra">
<xsl:for-each select="producte">
<div class="idProd"><xsl:value-of select="@id"/></div>
<div class="nomProd"><xsl:value-of select="/tenda/productes/producte/."/></div>
<div class="cantProd"><xsl:value-of select="."/></div>
<div class="precProd"><xsl:value-of select=". * $temp"/></div>
</xsl:for-each>
</div>
<xsl:variable name="temp">
<xsl:for-each select="/tenda/productes/producte">
<xsl:value-of select="@preuUnitat"/>
</xsl:for-each>
</xsl:variable>
</xsl:template>
</xsl:stylesheet>
```
Dejo tambien una captura de lo que tengo:
[](https://i.stack.imgur.com/dQzkd.png)
EDIT:
Ya lo solucioné todo. con un xsl:key pude hacerlo.
| [Ayuda con cálculo XSL](/questions/171222/ayuda-con-c%c3%a1lculo-xsl)
=====================================================================
| stackoverflow.com | 2020.29 | [
{
"text": "\nPuedes usar el siguiente XPath:\n\n\n\n```\n<span>\n <xsl:value-of select=\"sum(tenda/productes/producte/@preuUnitat)\"/>\n</span>\n\n```\n\nBueno ese Xpath suma y este multiplica la suma por la cantidad:\n\n\n\n```\n<span>\n <xsl:value-of select=\"sum(tenda/productes/producte/@preuUnitat)*count(tenda/productes/producte/@preuUnitat)\"/>\n</span>\n\n```\n\nPuedes jugar con eso y revisar [funciones numericas en XPath](https://www.w3.org/TR/xpath-functions-31/#numeric-functions)\n\n\n",
"name": "",
"is_accepted": false
}
] |
c16270a9095c111702029073c377103c |
Mi problema es que me han pedido que haga una clase de Python sobre Animales, en la que tiene como atributos el Nombre, la Fecha de Nacimiento, el Tipo, el Estado y el ID. La idea es que el programa tiene un menú y la primera opción es "Crear Animal", donde se pide al usuario introducir la información de los animales. La cosa es que si se escoge esta opcion 10 veces, la 10 deberá quedar guardado la información de los distintos animales. He probado definiendo funciones o métodos dentro de la clase, haciéndolo fuera, etc. Y lo único que consigo es que se guare el último animal introducido, no que se guarden todos. He probado con diccionarios, con tuplas y con listas, haciendo por ejemplo una lista de listas donde cada lista tenga el contenido de un animal. Pero como decía haga lo que haga y ponga donde lo ponga solo consigo almacenar el último introducido. Os adjuntaré el código de lo que tengo hecho, las frases de cortesía al usuario están en catalán pero imagino que se entenderá más o menos (soy principiante y sé que puede haber cosas mal). Gracias de antemano.
```
class Animal:
def __init__ (self, nom, datanaix, tipus, estat, id):
self.nom=nom
self.datanaix=datanaix
self.tipus=tipus
self.estat=estat
self.id=id
def getnom(self):
return self.nom
def getdatanaix(self):
return self.datanaix
def gettipus(self):
return self.tipus
def getestat(self):
return self.estat
def getid(self):
return self.id
```
Y aquí el menú:
```
sortir=False
while not sortir:
print("Escull una opció")
print("1. Crear Animal")
print("2. Crear Propietari")
print("3. Mostrar Animals")
print("4. Mostrar Animals per tipus")
print("5. Mostrar Propietaris")
print("6. Fer Log-in")
print("7. Sortir")
opcio=int(input("Introdueix la opció: "))
if opcio==1:
nom=input("Introdueix el nom: ")
nom=nom.lower()
datanaix=input("Introdueix la data de naixement: ")
tipus=input("Introdueix el tipus Gos (G), Conill (C) o Serp (S): ")
tipus=tipus.upper()
estat=input("Introdueix l'estat, es a dir, si té propietari: ")
id=tipus+"-"+nom
obj1=Animal(nom, datanaix, tipus, estat, id)
obj1.mostraranimal()
#obj1.omplediccionari() #no se si esta funcion se tendrá que usar o no
list=[]
list.append(Animal(nom, datanaix, tipus, estat, id))
```
| [¿Cómo hago objetos “ilimitados” de una clase?](/questions/357851/c%c3%b3mo-hago-objetos-ilimitados-de-una-clase)
=================================================================================================================
| stackoverflow.com | 2020.40 | [
{
"text": "\nDebes usar algún contenedor, una lista te vale, tu error es que **declaras una nueva lista en cada iteración del ciclo** y se la asignas a la variable `list`. Por tanto, como reasignas un nuevo objeto `list` (vacío) en cada iteración a la variable, la lista que generaste en la iteración anterior se queda sin referencias y el GC la destruye junto al objeto `Animal` que contenía. Al final solo queda viva y asociada a la variable la lista que se creo en la última iteración del ciclo.\n\n\n\n```\nsortir = False\nanimals = [] # <<<<< Declara aquí\nwhile not sortir:\n print(\"Escull una opció\")\n print(\"1. Crear Animal\")\n print(\"2. Crear Propietari\")\n print(\"3. Mostrar Animals\")\n print(\"4. Mostrar Animals per tipus\")\n print(\"5. Mostrar Propietaris\")\n print(\"6. Fer Log-in\")\n print(\"7. Sortir\")\n\n opcio = int(input(\"Introdueix la opció: \"))\n if opcio == 1:\n nom = input(\"Introdueix el nom: \")\n nom = nom.lower()\n datanaix = input(\"Introdueix la data de naixement: \")\n tipus = input(\"Introdueix el tipus Gos (G), Conill (C) o Serp (S): \")\n tipus = tipus.upper()\n estat = input(\"Introdueix l'estat, es a dir, si té propietari: \")\n id = tipus + \"-\" + nom\n obj1 = Animal(nom, datanaix, tipus, estat, id)\n obj1.mostraranimal()\n #obj1.omplediccionari() #no se si esta funcion se tendrá que usar o no\n animals.append(Animal(nom, datanaix, tipus, estat, id))\n\n```\n\nDos observaciones:\n\n\n* `list` es una función preconstruida en Python que además permite crear objetos de tipo `list`. No lo uses nunca como nombre de variable, tampoco otras [funciones builtin](https://docs.python.org/3/library/functions.html).\n\n\nComo mínimo es poco legible y confuso para otros desarrolladores que lean el código. Es fácil deducir con justificada razón, que ante cosas como `bar = foo(list)` a la función se le pasa una referenciara al builtin/tipo `list` y no un objeto `list`. Además, si llegaras a necesitar usar `list` en otra parte del código, tienes un problema, ahora `list` es un objeto `list`, se acabó el poder hacer cosas como : `nueva_lista = list(\"Hola\")`\n\n\nSi llega a ser necesario usar uno de esos nombres, raro, pero si se da el caso y por legibilidad es oportuno, la convención marca que se debe agregar un guion bajo al final: `list_`.\n* El uso de getters en Python no tiene generalmente mucho sentido dado que no existen los atributos privados, es más pitónico acceder directamente al atributo y no crear un método que simplemente lo retorna. Quiźas lo más parecido que hay en Python a getters y setters son las [propiedades](https://es.stackoverflow.com/a/328268/15089).\n\n\n",
"name": "",
"is_accepted": true
}
] |
491b011edb1601e6b4aa3248e63af61e |
soy un poco nuevo en pyhton y queria peguntar si alguno de ustedes sabe como dividir un string por tamaño en una lista, es decir que cada tantos caracteres se vayan guardando en una lista, por ejemplo:
x = '123456789' y para este ejemplo quisiera hacer esto
lista = ['12','34','56',78',9] cada dos caracteres se van guardando y el ultimo pues como solo es uno que se guarde solo tengo en codigo esto:
```
x = 'abcdefghijklmnñopqrstuvwxyz '
for i in range(0,len(x),5):
if i+5 < len(x):
for j in range(i,i+5):
lista.append(x[:i+5])
print(lista)
['abcde']
['abcde', 'abcde']
['abcde', 'abcde', 'abcde']
['abcde', 'abcde', 'abcde', 'abcde']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs', 'opqrs']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs', 'opqrs', 'opqrs']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs', 'opqrs', 'opqrs', 'tuvwx']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs', 'opqrs', 'opqrs', 'tuvwx', 'tuvwx']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs', 'opqrs', 'opqrs', 'tuvwx', 'tuvwx', 'tuvwx']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs', 'opqrs', 'opqrs', 'tuvwx', 'tuvwx', 'tuvwx', 'tuvwx']
['abcde', 'abcde', 'abcde', 'abcde', 'abcde', 'fghij', 'fghij', 'fghij',
'fghij', 'fghij', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'klmnñ', 'opqrs',
'opqrs', 'opqrs', 'opqrs', 'opqrs', 'tuvwx', 'tuvwx', 'tuvwx', 'tuvwx',
'tuvwx']
```
esa es la respuesta como les dije soy nuevo y si me pueden ayudar les agradeceria
| [DIVIDIR TEXTO POR TAMAÑO](/questions/339867/dividir-texto-por-tama%c3%91o)
===========================================================================
| stackoverflow.com | 2020.16 | [
{
"text": "\n\n```\nx = 'abcdefghijklmnñopqrstuvwxyz '\nlista=[]\nc=0\ncad = \"\"\nfor i in x: #itera todos los caracteres\n cad=cad + i #concatena\n c = c + 1\n if(c == 5):\n lista.append(cad)\n c = 0\n cad = \"\"\nlista.append(cad)\nprint(lista)\n\n\n\n\noutput:\n['abcde', 'fghij', 'klmnñ', 'opqrs', 'tuvwx', 'yz ']\n\n```\n\n",
"name": "",
"is_accepted": true
}
] |
4d1f497b0184173cda7a7fb2afaac376 | RusAme or UKUs
==============
| RusAme or UKUs
==============
| qfeast.com | 2020.10 | [
{
"text": "UKUs",
"name": "",
"is_accepted": false
},
{
"text": "RusAme",
"name": "",
"is_accepted": false
}
] |
c82a31b73533da3d0adf938f6bf14306 |
「vagrant up」が起動しなくなりました。
vagrant upを打ち込むと、下記のようなエラーが続きます。
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Checking if box 'puppetlabs/centos-7.2-64-nocm' is up to date...
==> default: Clearing any previously set forwarded ports...
==> default: Clearing any previously set network interfaces...
==> default: Preparing network interfaces based on configuration...
default: Adapter 1: nat
==> default: Forwarding ports...
default: 22 (guest) => 2222 (host) (adapter 1)
==> default: Booting VM...
==> default: Waiting for machine to boot. This may take a few minutes...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant
default: SSH auth method: private key
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Authentication failure. Retrying...
default: Warning: Authentication failure. Retrying...
default: Warning: Authentication failure. Retrying...
```
何が原因なのか見当つきません。
ご教示頂けますと幸いです。よろしくお願いします。
| vagrant upが起動しない
================
| teratail.com | 2021.21 | [
{
"text": "公開鍵が消えちゃった？ \n\n\n[こちらを参照](http://qiita.com/megane42/items/1d8ae7444d8c1b10bbd7)\n\n",
"name": "",
"is_accepted": false
}
] |
8c50cc83cececd84bcab69b8a2c4ad1f |
windows内に仮想サーバーを作り、その中にLinuxディストリビューションのCentOSとubuntuを入れたいと考えています。
vagrantを用いて、CentOSは既にインストールできている状況なのですが、ubuntuがうまく入らない状況となっています。CentOSの方のvagrantは切った状態で、ubuntuのディレクトリでvagrant upコマンドによりvagrant立ち上げを行いましたが、次の表示：
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Checking if box 'bento/ubuntu-17.10' is up to date...
==> default: Clearing any previously set forwarded ports...
==> default: Clearing any previously set network interfaces...
==> default: Preparing network interfaces based on configuration...
default: Adapter 1: nat
default: Adapter 2: hostonly
==> default: Forwarding ports...
default: 22 (guest) => 2222 (host) (adapter 1)
==> default: Booting VM...
==> default: Waiting for machine to boot. This may take a few minutes...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant
default: SSH auth method: private key
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
==> default: Machine booted and ready!
[default] GuestAdditions versions on your host (5.2.0) and guest (5.2.1) do not match.
Reading package lists...
Building dependency tree...
Reading state information...
dkms is already the newest version (2.3-3ubuntu3).
linux-headers-4.13.0-21-generic is already the newest version (4.13.0-21.24).
0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded.
Copy iso file C:\Program Files\Oracle\VirtualBox\VBoxGuestAdditions.iso into the box /tmp/VBoxGuestAdditions.iso
Mounting Virtualbox Guest Additions ISO to: /mnt
mount: /mnt: WARNING: device write-protected, mounted read-only.
Installing Virtualbox Guest Additions 5.2.1 - guest version is 5.2.1
Verifying archive integrity... All good.
Uncompressing VirtualBox 5.2.1 Guest Additions for Linux........
VirtualBox Guest Additions installer
Removing installed version 5.2.1 of VirtualBox Guest Additions...
Copying additional installer modules ...
Installing additional modules ...
VirtualBox Guest Additions: Building the VirtualBox Guest Additions kernel modules.
VirtualBox Guest Additions: Look at /var/log/vboxadd-setup.log to find out what went wrong
VirtualBox Guest Additions: Running kernel modules will not be replaced until the system is restarted
VirtualBox Guest Additions: Starting.
An error occurred during installation of VirtualBox Guest Additions 5.2.1. Some functionality may not work as intended.
In most cases it is OK that the "Window System drivers" installation failed.
Unmounting Virtualbox Guest Additions ISO from: /mnt
==> default: Checking for guest additions in VM...
==> default: Configuring and enabling network interfaces...
The following SSH command responded with a non-zero exit status.
Vagrant assumes that this means the command failed!
/sbin/ifdown 'eth1' || true
/sbin/ip addr flush dev 'eth1'
Remove any previous network modifications from the interfaces file
===================================================================
sed -e '/^#VAGRANT-BEGIN/,$ d' /etc/network/interfaces > /tmp/vagrant-network-interfaces.pre
sed -ne '/^#VAGRANT-END/,$ p' /etc/network/interfaces | tac | sed -e '/^#VAGRANT-END/,$ d' | tac > /tmp/vagrant-network-interfaces.post
cat \
/tmp/vagrant-network-interfaces.pre \
/tmp/vagrant-network-entry \
/tmp/vagrant-network-interfaces.post \
>
> /etc/network/interfaces
>
>
>
rm -f /tmp/vagrant-network-interfaces.pre
rm -f /tmp/vagrant-network-entry
rm -f /tmp/vagrant-network-interfaces.post
/sbin/ifup 'eth1'
Stdout from the command:
Stderr from the command:
bash: line 4: /sbin/ifdown: No such file or directory
bash: line 20: /sbin/ifup: No such file or directory
が出て、この状態でputtyからubuntuにアクセスしようとしてもタイムアウトしてアクセスできない状況です。
どうすれば解決できるでしょうか。
| Vagrantでのubuntuのダウンロード/インストール
=============================
| teratail.com | 2020.29 | [
{
"text": "私も、公式の boxの18.04で同じ現象発生しています。 ubuntu16.04では問題がなかったのですが 、17.10からネットワーク管理ツールが変更になったことの弊害と思われます。 \n\n\nいずれ vagrant側で対応するかもしれませんが、今できる対応としては \n\n\n1. 17.10以前の boxを使用する\n2. vagrant upしてエラーになった後、vagrant sshで中に入って手動で \n\napt-get update、 apt-get install -y ifupdown を実行して \n\n再度vagrant upや vagrant provisionを実行する。\n\n\nという方法しかないかと思います。\n\n",
"name": "",
"is_accepted": true
}
] |
e4855186dc33b584208479690a9d8a9f |
oracleでソートを行うと、数字、英字、ひらがな、カタカナの順番で表示されます。
これをひらがな、カタカナ、数字、英字の順番で表示させたいのですが、調べてもよい方法が見つかりません。
なにかよい方法はないでしょうか？
| oracleのソート順について
===============
| teratail.com | 2020.45 | [
{
"text": "システム側で対応しました\n\n",
"name": "",
"is_accepted": true
},
{
"text": "カタカナ、数字、英字でそれぞれ３つのSELECT文を作成して、 \n\nUNIONでくっつけるのはダメでしょうか？\n\n",
"name": "",
"is_accepted": false
},
{
"text": "これくらいしか \n\n\nselect 1 as sortkey1 \n\n,val1 \n\nfrom table1 \n\nwhere val1 between 'あ' and 'ん' \n\nunion all \n\nselect 2 as sortkey1 \n\n,val1 \n\nfrom table1 \n\nwhere val1 between 'ア' and 'ン' \n\nunion all \n\nselect 3 as sortkey1 \n\n,val1 \n\nfrom table1 \n\nwhere val1 between '0' and '9' \n\nunion all \n\nselect 4 as sortkey1 \n\n,val1 \n\nfrom table1 \n\nwhere val1 between 'A' and 'z' \n\norder by sortkey1,val1\n\n",
"name": "",
"is_accepted": false
}
] |
fa721da7a4662ca08c84e1abccc09704 |
ドットインストールのローカル開発環境を学習している者です。
virtualboxとvagrantをダウンロードし、7/8にVagrant up後、PuTTYに接続、PHPやRubyなどのアプリもインストール出来ました。ここで1度はログイン出来たんです。そこで学習を終了し、次の日に同じようにvagrant upして続きをと思ったら、PuTTYにエラーが出るようになってしまいました。やり直しすぎてもう埒が明かないので、どなたかご教示願いたく質問立てました。
現在の段階では、仮想マシンは起動出来ていますが、PuTTYを起動した時点で
putty fatal error server unexpectedly closed network
と表示され、先に進む事が出来ません。色々と調べ、アイドル状態になっているのか、PuTTYの接続のkeepaliveの数字を0から15とか、変えてみましたが結果は同じで。
もう、どうしたらいいか分かりません。ドットインストールの管理者に質問もし、
色々と対処済みであり、poderozaを進められました。結果、PuTTYが何か問題が有るようなので、poderozaが使えるならそれで学習を進めてくださいとの事でしたが・・・poderozaでは接続出来たのですが、使い方がイマイチわからず、PuTTYでは一度は接続出来たので、何とか出来ないかと悪戦苦闘しております。
vagrant upで途中の経過が気になるのですが、これは関係有るのでしょうか。
PS C:\Users\user\Myvagrant\MyCentOS> vagrant up
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Checking if box 'bento/centos-6.8' is up to date...
==> default: Machine already provisioned. Run `vagrant provision` or use the `--provision`
==> default: flag to force provisioning. Provisioners marked to run always will still run.
PS C:\Users\user\Myvagrant\MyCentOS> vagrant halt
==> default: Attempting graceful shutdown of VM...
PS C:\Users\user\Myvagrant\MyCentOS> vagrant up
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Checking if box 'bento/centos-6.8' is up to date...
==> default: Clearing any previously set forwarded ports...
==> default: Clearing any previously set network interfaces...
==> default: Preparing network interfaces based on configuration...
default: Adapter 1: nat
default: Adapter 2: hostonly
==> default: Forwarding ports...
default: 22 (guest) => 2222 (host) (adapter 1)
==> default: Booting VM...
==> default: Waiting for machine to boot. This may take a few minutes...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant
default: SSH auth method: private key
default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
==> default: Machine booted and ready!
==> default: Checking for guest additions in VM...
==> default: Configuring and enabling network interfaces...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant
default: SSH auth method: private key
==> default: Mounting shared folders...
default: /vagrant => C:/Users/user/MyVagrant/MyCentOS
==> default: Machine already provisioned. Run `vagrant provision` or use the `--provision`
==> default: flag to force provisioning. Provisioners marked to run always will still run.
『default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...』とエラーを繰り返す割には、
PS C:\Users\user\Myvagrant\MyCentOS> vagrant status
Current machine states:
default running (virtualbox)
The VM is running. To stop this VM, you can run `vagrant halt` to
shut it down forcefully, or you can run `vagrant suspend` to simply
suspend the virtual machine. In either case, to restart it again,
となっており、起動出来てる・・のがよく分かりません。
環境
windows 10 64 bit
vagrant/virtualbox 最新版
宜しくお願い致します！！
| 1度は接続出来たのに・・PuTTY・・接続したい！
=========================
| teratail.com | 2020.29 | [
{
"text": "色々教えて頂きましたが、自己で解決できず、PuTTYではなく違うターミナルで接続出来たため。 \n\n\n色々ご教授くださった皆様、ありがとうございました。\n\n",
"name": "",
"is_accepted": true
}
] |
8272e60591ee07fc160c486ebaf2162e |
7/8にVagrant up後、PuTTYに接続、PHPやRubyなどのアプリもインストール出来ました。ここで1度はログイン出来たんです。そこで学習を終了し、次の日に同じようにvagrant upして続きをと思ったら、PuTTYにエラーが出るようになってしまいました。やり直しすぎてもう埒が明かないので、どなたかご教示願いたく質問立てました。
現在の段階では、仮想マシンは起動出来ていますが、PuTTYを起動した時点で
putty fatal error server unexpectedly closed network
と表示され、先に進む事が出来ません。色々と調べ、アイドル状態になっているのか、PuTTYの接続のkeepaliveの数字を0から15とか、変えてみましたが結果は同じで。
もう、どうしたらいいか分かりません。ドットインストールの管理者に質問もし、
色々と対処済みであり、poderozaを進められました。結果、PuTTYが何か問題が有るようなので、poderozaが使えるならそれで学習を進めてくださいとの事でしたが・・・poderozaでは接続出来たのですが、使い方がイマイチわからず、PuTTYでは一度は接続出来たので、何とか出来ないかと悪戦苦闘しております。
vagrant upで途中の経過が気になるのですが、これは関係有るのでしょうか。
PS C:\Users\user\Myvagrant\MyCentOS> vagrant up
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Checking if box 'bento/centos-6.8' is up to date...
==> default: Machine already provisioned. Run `vagrant provision` or use the `--provision`
==> default: flag to force provisioning. Provisioners marked to run always will still run.
PS C:\Users\user\Myvagrant\MyCentOS> vagrant halt
==> default: Attempting graceful shutdown of VM...
PS C:\Users\user\Myvagrant\MyCentOS> vagrant up
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Checking if box 'bento/centos-6.8' is up to date...
==> default: Clearing any previously set forwarded ports...
==> default: Clearing any previously set network interfaces...
==> default: Preparing network interfaces based on configuration...
default: Adapter 1: nat
default: Adapter 2: hostonly
==> default: Forwarding ports...
default: 22 (guest) => 2222 (host) (adapter 1)
==> default: Booting VM...
==> default: Waiting for machine to boot. This may take a few minutes...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant
default: SSH auth method: private key
default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
==> default: Machine booted and ready!
==> default: Checking for guest additions in VM...
==> default: Configuring and enabling network interfaces...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant
default: SSH auth method: private key
==> default: Mounting shared folders...
default: /vagrant => C:/Users/user/MyVagrant/MyCentOS
==> default: Machine already provisioned. Run `vagrant provision` or use the `--provision`
==> default: flag to force provisioning. Provisioners marked to run always will still run.
『default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...』とエラーを繰り返す割には、
PS C:\Users\user\Myvagrant\MyCentOS> vagrant status
Current machine states:
default running (virtualbox)
The VM is running. To stop this VM, you can run `vagrant halt` to
shut it down forcefully, or you can run `vagrant suspend` to simply
suspend the virtual machine. In either case, to restart it again,
となっており、起動出来てる・・のがよく分かりません。
環境
windows 10 64 bit
vagrant/virtualbox 最新版
宜しくお願い致します！！
| 1度は接続出来たのに・・PuTTY・・接続したい！
=========================
| teratail.com | 2021.17 | [
{
"text": "他のターミナルを利用し、接続完了です！ \n\n\nご回答下さいました皆様、ありがとうございます！\n\n",
"name": "",
"is_accepted": false
}
] |
2ef6970e8421a44320ac88dae3b8a79f |
windows内に仮想サーバーを作り、その中にLinuxディストリビューションのCentOSとubuntuを入れたいと考えています。
vagrantを用いて、CentOSは既にインストールできている状況なのですが、ubuntuがうまく入らない状況となっています。CentOSの方のvagrantは切った状態で、ubuntuのディレクトリでvagrant upコマンドによりvagrant立ち上げを行いましたが、次の表示：
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Checking if box 'bento/ubuntu-17.10' is up to date...
==> default: Clearing any previously set forwarded ports...
==> default: Clearing any previously set network interfaces...
==> default: Preparing network interfaces based on configuration...
default: Adapter 1: nat
default: Adapter 2: hostonly
==> default: Forwarding ports...
default: 22 (guest) => 2222 (host) (adapter 1)
==> default: Booting VM...
==> default: Waiting for machine to boot. This may take a few minutes...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant
default: SSH auth method: private key
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
==> default: Machine booted and ready!
[default] GuestAdditions versions on your host (5.2.0) and guest (5.2.1) do not match.
Reading package lists...
Building dependency tree...
Reading state information...
dkms is already the newest version (2.3-3ubuntu3).
linux-headers-4.13.0-21-generic is already the newest version (4.13.0-21.24).
0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded.
Copy iso file C:\Program Files\Oracle\VirtualBox\VBoxGuestAdditions.iso into the box /tmp/VBoxGuestAdditions.iso
Mounting Virtualbox Guest Additions ISO to: /mnt
mount: /mnt: WARNING: device write-protected, mounted read-only.
Installing Virtualbox Guest Additions 5.2.1 - guest version is 5.2.1
Verifying archive integrity... All good.
Uncompressing VirtualBox 5.2.1 Guest Additions for Linux........
VirtualBox Guest Additions installer
Removing installed version 5.2.1 of VirtualBox Guest Additions...
Copying additional installer modules ...
Installing additional modules ...
VirtualBox Guest Additions: Building the VirtualBox Guest Additions kernel modules.
VirtualBox Guest Additions: Look at /var/log/vboxadd-setup.log to find out what went wrong
VirtualBox Guest Additions: Running kernel modules will not be replaced until the system is restarted
VirtualBox Guest Additions: Starting.
An error occurred during installation of VirtualBox Guest Additions 5.2.1. Some functionality may not work as intended.
In most cases it is OK that the "Window System drivers" installation failed.
Unmounting Virtualbox Guest Additions ISO from: /mnt
==> default: Checking for guest additions in VM...
==> default: Configuring and enabling network interfaces...
The following SSH command responded with a non-zero exit status.
Vagrant assumes that this means the command failed!
/sbin/ifdown 'eth1' || true
/sbin/ip addr flush dev 'eth1'
Remove any previous network modifications from the interfaces file
===================================================================
sed -e '/^#VAGRANT-BEGIN/,$ d' /etc/network/interfaces > /tmp/vagrant-network-interfaces.pre
sed -ne '/^#VAGRANT-END/,$ p' /etc/network/interfaces | tac | sed -e '/^#VAGRANT-END/,$ d' | tac > /tmp/vagrant-network-interfaces.post
cat \
/tmp/vagrant-network-interfaces.pre \
/tmp/vagrant-network-entry \
/tmp/vagrant-network-interfaces.post \
>
> /etc/network/interfaces
>
>
>
rm -f /tmp/vagrant-network-interfaces.pre
rm -f /tmp/vagrant-network-entry
rm -f /tmp/vagrant-network-interfaces.post
/sbin/ifup 'eth1'
Stdout from the command:
Stderr from the command:
bash: line 4: /sbin/ifdown: No such file or directory
bash: line 20: /sbin/ifup: No such file or directory
が出て、この状態でputtyからubuntuにアクセスしようとしてもタイムアウトしてアクセスできない状況です。
どうすれば解決できるでしょうか。
| Vagrantでのubuntuのダウンロード/インストール
=============================
| teratail.com | 2021.25 | [
{
"text": "私も、公式の boxの18.04で同じ現象発生しています。 ubuntu16.04では問題がなかったのですが 、17.10からネットワーク管理ツールが変更になったことの弊害と思われます。 \n\n\nいずれ vagrant側で対応するかもしれませんが、今できる対応としては \n\n\n1. 17.10以前の boxを使用する\n2. vagrant upしてエラーになった後、vagrant sshで中に入って手動で \n\napt-get update、 apt-get install -y ifupdown を実行して \n\n再度vagrant upや vagrant provisionを実行する。\n\n\nという方法しかないかと思います。\n\n",
"name": "",
"is_accepted": true
},
{
"text": "現在利用中のboxは、vagrantbox.esのではないですか？ \n\nもし、そうであれば公式のボックスをお勧めします。 \n\n\nちなみに、apt-get update、 apt-get install -y ifupdownで治りませんか？\n\n",
"name": "",
"is_accepted": false
}
] |
7cddd673c458dc4fa397fa67697e67cf |
joushima-no-MacBook-Pro:aaa joshima$ vagrant init bbb
A `Vagrantfile` has been placed in this directory. You are now
ready to `vagrant up` your first virtual environment! Please read
the comments in the Vagrantfile as well as documentation on
`vagrantup.com` for more information on using Vagrant.
joushimaryouta-no-MacBook-Pro:aaa joshima$ vagrant up
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Importing base box 'bbb'...
==> default: Matching MAC address for NAT networking...
==> default: Setting the name of the VM: aaa\_default\_1450170504946\_82847
==> default: Clearing any previously set forwarded ports...
==> default: Clearing any previously set network interfaces...
==> default: Preparing network interfaces based on configuration...
default: Adapter 1: nat
==> default: Forwarding ports...
default: 22 => 2222 (adapter 1)
==> default: Booting VM...
==> default: Waiting for machine to boot. This may take a few minutes...
default: SSH address:
default: SSH username: vagrant
default: SSH auth method: private key
default: Warning: Connection timeout. Retrying...
default: Warning: Connection timeout. Retrying...
default:
default: Vagrant insecure key detected. Vagrant will automatically replace
default: this with a newly generated keypair for better security.
default:
default: Inserting generated public key within guest...
default: Removing insecure key from the guest if it's present...
default: Key inserted! Disconnecting and reconnecting using new SSH key...
==> default: Machine booted and ready!
==> default: Checking for guest additions in VM...
default: The guest additions on this VM do not match the installed version of
default: VirtualBox! In most cases this is fine, but in rare cases it can
default: prevent things such as shared folders from working properly. If you see
default: shared folder errors, please make sure the guest additions within the
default: virtual machine match the version of VirtualBox you have installed on
default: your host and reload your VM.
default:
default: Guest Additions Version: 4.3.28
default: VirtualBox Version: 5.0
==> default: Mounting shared folders...
default: /vagrant => /Users/joshima/aaa
joushima-no-MacBook-Pro:aaa joshima$ vagrant ssh
Last login: Thu Jul 16 08:48:31 2015 from 10.0.2.2
Welcome to your Vagrant-built virtual machine.
[vagrant@localhost ~]$ echo "Hi"
Hi
[vagrant@localhost ~]$ rails new aaa
-bash: rails: コマンドが見つかりません
[vagrant@localhost ~]$ ls
base.sh cleanup.sh puppet.sh vagrant.sh virtualbox.sh zerodisk.sh
[vagrant@localhost ~]$ rails new ccc
-bash: rails: コマンドが見つかりません
[vagrant@localhost ~]$
vagrantのゲストOS上でrails アプリケーションの骨格が作れない。
プログラミング初心者で何がおかしいすらわかりません。
よろしくお願いいたします。
| vagrantのゲストOS上でrails アプリケーションの骨格が作れない。
======================================
| teratail.com | 2020.29 | [
{
"text": "エラーメッセージを見ると、 \n\n\n-bash: rails: コマンドが見つかりません\nとなっています。railsはインストールされていますか？ \n\n\n第1回の講義ビデオを見てみましたが、RubyならびにRuby on Railsをインストールしてあることが前提になっているような気がします。\n\n",
"name": "",
"is_accepted": true
}
] |
bb343ca24021cf7b4d018f3f2f967d39 |
### 前提・実現したいこと
rLoginを使ってUbuntuつなぎたい
コマンドプロンプトでvagrant upのコマンドを打ちました
default: SSH username: vagrant
↑の通りユーザーネームがvagrantなっていましたが
rLoginの新規設定でユーザーネームのところをubuntuにしたいため
これだとエラーが出てしまいます。
下のコードはコマンドプロンプトでvagrant upをした時のやつです。
usernameのところをubuntuにするにはどうしたらいいですか？
### 該当のソースコード
Bringing machine 'default' up with 'virtualbox' provider...
==> default: Importing base box 'ubuntu/xenial64'...
==> default: Matching MAC address for NAT networking...
==> default: Setting the name of the VM: ubuntu64\_16\_default\_1516113629748\_57595
==> default: Clearing any previously set network interfaces...
==> default: Preparing network interfaces based on configuration...
default: Adapter 1: nat
==> default: Forwarding ports...
default: 22 (guest) => 2222 (host) (adapter 1)
==> default: Running 'pre-boot' VM customizations...
==> default: Booting VM...
==> default: Waiting for machine to boot. This may take a few minutes...
default: SSH address: 127.0.0.1:2222
default: SSH username: vagrant ←ココ！！！！！
default: SSH auth method: private key
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Remote connection disconnect. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default: Warning: Connection reset. Retrying...
default: Warning: Connection aborted. Retrying...
default:
default: Vagrant insecure key detected. Vagrant will automatically replace
default: this with a newly generated keypair for better security.
default:
default: Inserting generated public key within guest...
default: Removing insecure key from the guest if it's present...
default: Key inserted! Disconnecting and reconnecting using new SSH key...
==> default: Machine booted and ready!
==> default: Checking for guest additions in VM...
default: The guest additions on this VM do not match the installed version of
default: VirtualBox! In most cases this is fine, but in rare cases it can
default: prevent things such as shared folders from working properly. If you see
default: shared folder errors, please make sure the guest additions within the
default: virtual machine match the version of VirtualBox you have installed on
default: your host and reload your VM.
default:
default: Guest Additions Version: 5.0.40
default: VirtualBox Version: 5.1
==> default: Mounting shared folders...
### 補足情報(言語/FW/ツール等のバージョンなど)
環境は
windows10
virtualbox
vagrant
ubuntu
rLogin
| ubuntuをつかいたい
============
| teratail.com | 2020.29 | [
{
"text": "つconfig.ssh.username = \"ubuntu\"\n\n",
"name": "",
"is_accepted": true
}
] |
49e90d751fd801dd17b346fbb5bb863e | giúp tớ với ạ! ngày mai tớ kiểm tra rồi!!! | date. no
nan aug aa
lut faon
biat le ss mo saf
ygbm/s
1
auala
a toc
tit f ao plucg u
luc facp va
| hoidap247.com | 2021.31 | [
{
"text": "đáp án:\n a. $a = 9m/{s^2}$\nb. $a = 4m/{s^2}$\ngiải thích các bước giải:\n a. lực f theo phương ngang:\n$a = \\frac{{f - {f\\_{ms}}}}{m} = \\frac{{20 - 0,1.2.10}}{2} = 9m/{s^2}$\nb. lực f tạo phương ngang góc 60\n$a = \\frac{{f\\cos 60 - {f\\_{ms}}}}{m} = 4m/{s^2}$",
"name": "",
"is_accepted": false
},
{
"text": "đây bạn ạ. câu b tóm tắt bạn ghi thêm điều kiện anpha= 60 độ nha\n ",
"name": "",
"is_accepted": false
}
] |
da5940dfe6c749f9d414e75c0fa03923 | tanx+cosx-2=0
tìm x ? | tanx+cosx-2=0
tìm x ? câu hỏi 124865 - hoidap247.com | hoidap247.com | 2021.31 | [
{
"text": "tanx +cosx =2\nsinx/cosx +cosx/sinx =2\nsinx^2+cosx^2/sinx.cosx =2\nsinx^2+cosx^2 =2sinx.cosx\n 1 =2sinx.cosx\n sin2x =1\nbạn giải tiếp đi nhé\n ",
"name": "",
"is_accepted": false
},
{
"text": "$\\tan x+\\cot x-2=0$\nđk: $x\\ne \\dfrac{\\pi}{2}+k\\pi$\npt $\\leftrightarrow \\dfrac{\\sin x}{\\cos x}+\\dfrac{\\cos x}{\\sin x}-2=0$\n$\\leftrightarrow \\dfrac{1}{\\sin x.\\cos x}=2$\n$\\leftrightarrow \\sin x.\\cos x=\\dfrac{1}{2}$\n$\\leftrightarrow \\sin 2x=1$\n$\\leftrightarrow x=\\dfrac{\\pi}{4}+k\\pi$ (tm)",
"name": "",
"is_accepted": false
}
] |
845a351f617255e9e84edfc435ca6f86 | a,chuyển các tính từ sau thành trạng từ:
lucky ---> .....
bad ---> .....
magic ---> .....
late ---> .....
beautiful ---> .....
hard ---> .....
normal ---> ....
dramatic ---> ....
b, sau khi chuyển tính từ thành trạng từ, hãy chỉ ra đâu là tính từ phải thêm đuôi ở cuối từ, từ nào thì không? | a,chuyển các tính từ sau thành trạng từ:
lucky ---> .....
bad ---> .....
magic ---> .....
late ---> .....
beautiful ---> .....
hard ---> .....
normal ---> .... | hoidap247.com | 2021.43 | [
{
"text": "1. luckily2. badly3. magically4. late (trạng từ đặc biệt, # lately (gần đây)5. beautifully6. hard (trạng từ đặc biệt, # hardly (hiếm khi)7. normally 8. dramaticallycác từ \"bad\", \"hard\" không phải thêm đuôi cuối tính từ để tạo thành trạng từ; các từ còn lại có thêm -ly hoặc -ally",
"name": "",
"is_accepted": false
},
{
"text": "lucky ---> luckilybad ---> badlymagic ---> magicallylate ---> latebeautiful ---> beautifullyhard ---> hardnormal ---> normallydramatic ---> dramatically",
"name": "",
"is_accepted": false
}
] |
52cb1a903f486ce4b5aed6f772be709b | if <span lang="en | if <span lang="en | goprep.co | 2021.21 | [
{
"text": "⇒ ⇒ ⇒ ∴ b(3, - 3,1)ans: b(3, - 3,1)",
"name": "⇒ ⇒ ⇒ ∴ b(3, - 3,1)ans: b(3, - 3,1)",
"is_accepted": true
}
] |
5864d848de8edbd3712bdf3e58b138c9 | let’s fill up the table below : | let’s fill up the table below : | goprep.co | 2020.40 | [
{
"text": "(b)first part,given, (i) x4 – 4x3 + 6x2(ii) x2(i) × (ii)= (x4 – 4x3 + 6x2) × x2= x4x2 – 4x3x2 + 6x2x2we know (xaxb= xa+b)= x4+2– 4x3+2 + 6x2+2= x6 – 4x5 + 6x4(i) ÷ (ii)we know = x4-2 – 4x3-2 + 6x2-2= x2 – 4x + 6second partgiven, (i) 3m2n3 + 40m3n4 – 5m4n5(ii) 10m2n2(i) × (ii)= (3m2n3 + 40m3n4 – 5m4n5) × 10m2n2we know (xaxb= xa+b)= 30m2m2n3n2 + 400m3m2n4n2 – 50m4m2n5n2= 30m2+2n3+2 + 400m3+2n4+2 – 50m4+2n5+2= 30m4n5 + 400m5n6 – 50m6n7(i) ÷ (ii)we know (c)given,(i) 49l2 – 100m2(ii) (7l + 10m)(i) × (ii)= (49l2 – 100m2)(7l + 10m)we know (xaxb= xa+b)= 343l2l+ 490l2m – 700m2l – 1000m2m= 343l2+1 + 490l2m – 700lm2 – 1000m2+1= 343l3 + 490l2m – 700lm2 – 1000m3(i) ÷ (ii)∵ a2 – b2 = (a – b)(a + b), taking a = 7l, b = 10m we havecancelling out the common terms from numerator and denominator, we get= 7l – 10m(d)given,(i) 625a4 – 81b4(ii) 5a + 3b(i) × (ii)= (625a4 – 81b4)(5a + 3b)= 625a4a + 1875a4b – 405ab4 – 243b4bwe know (xaxb= xa+b)= 625a4+1 + 1875a4b – 405ab4 – 243b4+1= 3125a5 + 1875a4b – 405ab4 – 243b5(i) ÷ (ii)∵ a2 – b2 = (a – b)(a + b), taking a = 25a2, b = 9b2, we have∵ a2 – b2 = (a – b)(a + b), taking a = 5a, b = 3b we have=cancelling out the common terms from numerator and denominator, we get= (5a – 3b)(25a2 + 9b2)= 125aa2 + 45ab2 – 75a2b – 27bb2we know (xaxb= xa+b)= 125a2+1 + 45ab2 – 75a2b – 27b2+1= 125a3 + 45ab2 – 75a2b – 27b3",
"name": "(b)first part,given, (i) x4 – 4x3 + 6x2(ii) x2(i) × (ii)= (x4 – 4x3 + 6x2) × x2= x4x2 – 4x3x2 + 6x2x2we know (xaxb= xa+b)= x4+2– 4x3+2 + 6x2+2= x6 – 4x5 + 6x4(i) ÷ (ii)we know = x4-2 – 4x3-2 + 6x2-2= x2 – 4x + 6second partgiven, (i) 3m2n3 + 40m3n4 – 5m4n5(ii) 10m2n2(i) × (ii)= (3m2n3 + 40m3n4 – 5m4n5) × 10m2n2we know (xaxb= xa+b)= 30m2m2n3n2 + 400m3m2n4n2 – 50m4m2n5n2= 30m2+2n3+2 + 400m3+2n4+2 – 50m4+2n5+2= 30m4n5 + 400m5n6 – 50m6n7(i) ÷ (ii)we know (c)given,(i) 49l2 – 100m2(ii) (7l + 10m)(i) × (ii)= (49l2 – 100m2)(7l + 10m)we know (xaxb= xa+b)= 343l2l+ 490l2m – 700m2l – 1000m2m= 343l2+1 + 490l2m – 700lm2 – 1000m2+1= 343l3 + 490l2m – 700lm2 – 1000m3(i) ÷ (ii)∵ a2 – b2 = (a – b)(a + b), taking a = 7l, b = 10m we havecancelling out the common terms from numerator and denominator, we get= 7l – 10m(d)given,(i) 625a4 – 81b4(ii) 5a + 3b(i) × (ii)= (625a4 – 81b4)(5a + 3b)= 625a4a + 1875a4b – 405ab4 – 243b4bwe know (xaxb= xa+b)= 625a4+1 + 1875a4b – 405ab4 – 243b4+1= 3125a5 + 1875a4b – 405ab4 – 243b5(i) ÷ (ii)∵ a2 – b2 = (a – b)(a + b), taking a = 25a2, b = 9b2, we have∵ a2 – b2 = (a – b)(a + b), taking a = 5a, b = 3b we have=cancelling out the common terms from numerator and denominator, we get= (5a – 3b)(25a2 + 9b2)= 125aa2 + 45ab2 – 75a2b – 27bb2we know (xaxb= xa+b)= 125a2+1 + 45ab2 – 75a2b – 27b2+1= 125a3 + 45ab2 – 75a2b – 27b3",
"is_accepted": true
}
] |
5e8442ddfa78055acbcc5aebec0703e0 | if <span lang="en | if <span lang="en | goprep.co | 2021.21 | [
{
"text": "given: to find: cos2xwe know that,cos 2x = 1 – 2sin2xputting the value, we get",
"name": "given: to find: cos2xwe know that,cos 2x = 1 – 2sin2xputting the value, we get",
"is_accepted": true
}
] |
17dccb3cf7d881d1c98204844d25e02a | if <span lang="en | if <span lang="en | goprep.co | 2021.21 | [
{
"text": "r.h.s:)⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ = l.h.shence, provedii)r.h.s. = ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ tanθ/2 = l.h.shence,proved.",
"name": "r.h.s:)⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ = l.h.shence, provedii)r.h.s. = ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ tanθ/2 = l.h.shence,proved.",
"is_accepted": true
}
] |
dc5997a2d56fcaefa90164b83efbdcba | add:3a (2b + 5c), 3c (2a + 2b) | add:3a (2b + 5c), 3c (2a + 2b) | goprep.co | 2020.45 | [
{
"text": "here, 3a(2b + 5c) = 6ab + 15ac3c(2a + 2b) = 6ac + 6bchence the two polynomials to be added are 6ab + 15ac and6ac + 6bcthe result is as follows 6ab + 21ac + 6bc",
"name": "here, 3a(2b + 5c) = 6ab + 15ac3c(2a + 2b) = 6ac + 6bchence the two polynomials to be added are 6ab + 15ac and6ac + 6bcthe result is as follows 6ab + 21ac + 6bc",
"is_accepted": true
}
] |
809c42b1d130275605d54e423ba5b1a8 | if <span lang="en | if <span lang="en | goprep.co | 2021.17 | [
{
"text": "we have, now , ",
"name": "we have, now , ",
"is_accepted": true
}
] |
136902346ca445559184b57d92ad2f47 | if <span lang="en | if <span lang="en | goprep.co | 2021.10 | [
{
"text": "using the chain rule of differentiation, (ans)",
"name": "using the chain rule of differentiation, (ans)",
"is_accepted": true
}
] |
e927ca1cb91d76c6fb859dc904d75f25 | if <span lang="en | if <span lang="en | goprep.co | 2021.17 | [
{
"text": "λ = 3μ = 1so, λ + μ = 3 + 1= 4",
"name": "λ = 3μ = 1so, λ + μ = 3 + 1= 4",
"is_accepted": true
}
] |
1f9316dc2776d2c4c351c0059f9bf2dd | 3x2 + 7ix + 6 = 0 | 3x2 + 7ix + 6 = 0 | goprep.co | 2020.45 | [
{
"text": "given:3x2 + 7ix + 6 = 0⇒3x2 + 9ix-2ix + 6 = 0⇒⇒ …(i2 = -1)⇒ = 0⇒⇒⇒x + 3i = 0 & 3x-2i = 0⇒ x = 3i & ans: x = 3i and ",
"name": "given:3x2 + 7ix + 6 = 0⇒3x2 + 9ix-2ix + 6 = 0⇒⇒ …(i2 = -1)⇒ = 0⇒⇒⇒x + 3i = 0 & 3x-2i = 0⇒ x = 3i & ans: x = 3i and ",
"is_accepted": true
}
] |
72ed8817f39308dc19fceca9ec65f7f5 | express <span lan | express <span lan | goprep.co | 2021.17 | [
{
"text": "here,…… eq 1multiplying eq 1 by 100 …… eq 2subtracting eq 1 from eq2⇒ 100 x – x = 234⇒ 99 x = 234 ……eq 3now, let ……eq 4multiplying eq 3 by 100⇒ ⇒ 100 y – y = 23⇒ 99 y = 23 …… eq 5from eq 3 and eq 5",
"name": "here,…… eq 1multiplying eq 1 by 100 …… eq 2subtracting eq 1 from eq2⇒ 100 x – x = 234⇒ 99 x = 234 ……eq 3now, let ……eq 4multiplying eq 3 by 100⇒ ⇒ 100 y – y = 23⇒ 99 y = 23 …… eq 5from eq 3 and eq 5",
"is_accepted": true
}
] |
90e1d2b358ac8ccf016d4c1e87907fd3 | if x2 | if x2 | goprep.co | 2021.25 | [
{
"text": "⇒ ⇒ cot45 = 1⇒ ⇒ x2 = sin230 + 4cot245-sec260⇒ ⇒ ⇒ ⇒ ",
"name": "⇒ ⇒ cot45 = 1⇒ ⇒ x2 = sin230 + 4cot245-sec260⇒ ⇒ ⇒ ⇒ ",
"is_accepted": true
}
] |
2b88fefe3119d8b80f0dc7c8239d9340 | if <span lang="en | if <span lang="en | goprep.co | 2021.17 | [
{
"text": "let (given)⇒ ⇒ ⇒ k=17",
"name": "let (given)⇒ ⇒ ⇒ k=17",
"is_accepted": true
}
] |
ade9b1c2c320cb50d813f69062a72191 | if <span lang="en | if <span lang="en | goprep.co | 2021.17 | [
{
"text": "given data:nowalso,3(2-3λ) + 4(1-4λ) - 5(4+5λ) = 0-50λ = 10using the above value,",
"name": "given data:nowalso,3(2-3λ) + 4(1-4λ) - 5(4+5λ) = 0-50λ = 10using the above value,",
"is_accepted": true
}
] |
dec2f7f7db774ed8da03510e3fe056de | if <span lang="en | if <span lang="en | goprep.co | 2021.43 | [
{
"text": "given, we should find the value for [by using the formulae, sin2θ + cos2θ = 1 and sin2θ = 2 sinθcosθ]as already mentioned in the question, , so x lies in the 1st quadrant and both sine and cosine functions are positive.therefore, sin x + cos x",
"name": "given, we should find the value for [by using the formulae, sin2θ + cos2θ = 1 and sin2θ = 2 sinθcosθ]as already mentioned in the question, , so x lies in the 1st quadrant and both sine and cosine functions are positive.therefore, sin x + cos x",
"is_accepted": true
}
] |